The correct unit of Specific conductance is : \({\text{S }}{{\text{m}}^{ - 1}}\)
CHXII03:ELECTROCHEMISTRY
330371
Given \({\rm{l/a = 0}}{\rm{.5}}\,\,{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{,R = 50}}\,\,{\rm{ohm,N = 1}}{\rm{.0}}\). The equivalent conductance of the electrolyte is
330372
The resistance of a N/10 KCl solution is \({\rm{245}}\,\,{\rm{\Omega }}\). The equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. is
330373
The compound exhibiting maximum value of equivalent conductance in a fused state is
1 \(\mathrm{SrCl}_{2}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{MgCl}_{2}\)
4 \(\mathrm{BeCl}_{2}\)
Explanation:
On moving downward in a group, atomic size increases, and, hence ionic character increases. Thus, \(\mathrm{SrCl}_{2}\) is most ionic among the given compounds, i.e. it will give ion readily in fused state. Hence, \(\mathrm{SrCl}_{2}\) exhibit the maximum value of equivalent conductance in fused state.
The correct unit of Specific conductance is : \({\text{S }}{{\text{m}}^{ - 1}}\)
CHXII03:ELECTROCHEMISTRY
330371
Given \({\rm{l/a = 0}}{\rm{.5}}\,\,{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{,R = 50}}\,\,{\rm{ohm,N = 1}}{\rm{.0}}\). The equivalent conductance of the electrolyte is
330372
The resistance of a N/10 KCl solution is \({\rm{245}}\,\,{\rm{\Omega }}\). The equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. is
330373
The compound exhibiting maximum value of equivalent conductance in a fused state is
1 \(\mathrm{SrCl}_{2}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{MgCl}_{2}\)
4 \(\mathrm{BeCl}_{2}\)
Explanation:
On moving downward in a group, atomic size increases, and, hence ionic character increases. Thus, \(\mathrm{SrCl}_{2}\) is most ionic among the given compounds, i.e. it will give ion readily in fused state. Hence, \(\mathrm{SrCl}_{2}\) exhibit the maximum value of equivalent conductance in fused state.
The correct unit of Specific conductance is : \({\text{S }}{{\text{m}}^{ - 1}}\)
CHXII03:ELECTROCHEMISTRY
330371
Given \({\rm{l/a = 0}}{\rm{.5}}\,\,{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{,R = 50}}\,\,{\rm{ohm,N = 1}}{\rm{.0}}\). The equivalent conductance of the electrolyte is
330372
The resistance of a N/10 KCl solution is \({\rm{245}}\,\,{\rm{\Omega }}\). The equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. is
330373
The compound exhibiting maximum value of equivalent conductance in a fused state is
1 \(\mathrm{SrCl}_{2}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{MgCl}_{2}\)
4 \(\mathrm{BeCl}_{2}\)
Explanation:
On moving downward in a group, atomic size increases, and, hence ionic character increases. Thus, \(\mathrm{SrCl}_{2}\) is most ionic among the given compounds, i.e. it will give ion readily in fused state. Hence, \(\mathrm{SrCl}_{2}\) exhibit the maximum value of equivalent conductance in fused state.
The correct unit of Specific conductance is : \({\text{S }}{{\text{m}}^{ - 1}}\)
CHXII03:ELECTROCHEMISTRY
330371
Given \({\rm{l/a = 0}}{\rm{.5}}\,\,{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{,R = 50}}\,\,{\rm{ohm,N = 1}}{\rm{.0}}\). The equivalent conductance of the electrolyte is
330372
The resistance of a N/10 KCl solution is \({\rm{245}}\,\,{\rm{\Omega }}\). The equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. is
330373
The compound exhibiting maximum value of equivalent conductance in a fused state is
1 \(\mathrm{SrCl}_{2}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{MgCl}_{2}\)
4 \(\mathrm{BeCl}_{2}\)
Explanation:
On moving downward in a group, atomic size increases, and, hence ionic character increases. Thus, \(\mathrm{SrCl}_{2}\) is most ionic among the given compounds, i.e. it will give ion readily in fused state. Hence, \(\mathrm{SrCl}_{2}\) exhibit the maximum value of equivalent conductance in fused state.