Measurement of the Conductivity
« Previous Topic: Kohlrausch Law of Independent migration of Ions and Its Applications Next Topic: Relation between Gibbs free energy, Equilibrium constant and emf of cell »
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII03:ELECTROCHEMISTRY

330374 The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of \({\rm{0}}{\rm{.88c}}{{\rm{m}}^{{\rm{ - 1}}}}\). The value of equivalent conductance of solution is

1 \({\rm{400}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{295}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{419}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{425}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
CHXII03:ELECTROCHEMISTRY

330375 The conductivity of a saturated solution of Sparingly soluble salt (x-factor = 1) is \({\rm{1}}{\rm{.53 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}\) and its conductance is \({\rm{0}}{\rm{.765oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{equi}}{{\rm{v}}^{{\rm{ - 1}}}}\). The molarity of sparingly soluble salt will be

1 \({\rm{1}}{{\rm{0}}^{{\rm{ - 6}}}}\)
2 \({\rm{25 \times 1}}{{\rm{0}}^{{\rm{ - 9}}}}\)
3 \({\rm{4 \times 1}}{{\rm{0}}^{{\rm{ - 12}}}}\)
4 \({\rm{2 \times 1}}{{\rm{0}}^{{\rm{ - 2}}}}\)
CHXII03:ELECTROCHEMISTRY

330376 What are the units of equivalent conductivity of a solution?

1 mho. \(\mathrm{cm}^{-1}\)
2 ohm. \(\mathrm{cm}^{-1} \cdot \mathrm{g}\) equiv \({ }^{-1}\)
3 mho. \(\mathrm{cm}^{-2}\). g equiv \({ }^{-1}\)
4 mho. \(\mathrm{cm}^{2}\). equiv \({ }^{-1}\)
CHXII03:ELECTROCHEMISTRY

330377 In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of \({\rm{50}}\,\,{\rm{\Omega }}\) find equivalent conductance of the salt solution?

1 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{120}}\,\,{\rm{S}}\,\,{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{160}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
NEET DIGITAL LIBRARY
CHXII03:ELECTROCHEMISTRY

330374 The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of \({\rm{0}}{\rm{.88c}}{{\rm{m}}^{{\rm{ - 1}}}}\). The value of equivalent conductance of solution is

1 \({\rm{400}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{295}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{419}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{425}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
CHXII03:ELECTROCHEMISTRY

330375 The conductivity of a saturated solution of Sparingly soluble salt (x-factor = 1) is \({\rm{1}}{\rm{.53 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}\) and its conductance is \({\rm{0}}{\rm{.765oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{equi}}{{\rm{v}}^{{\rm{ - 1}}}}\). The molarity of sparingly soluble salt will be

1 \({\rm{1}}{{\rm{0}}^{{\rm{ - 6}}}}\)
2 \({\rm{25 \times 1}}{{\rm{0}}^{{\rm{ - 9}}}}\)
3 \({\rm{4 \times 1}}{{\rm{0}}^{{\rm{ - 12}}}}\)
4 \({\rm{2 \times 1}}{{\rm{0}}^{{\rm{ - 2}}}}\)
CHXII03:ELECTROCHEMISTRY

330376 What are the units of equivalent conductivity of a solution?

1 mho. \(\mathrm{cm}^{-1}\)
2 ohm. \(\mathrm{cm}^{-1} \cdot \mathrm{g}\) equiv \({ }^{-1}\)
3 mho. \(\mathrm{cm}^{-2}\). g equiv \({ }^{-1}\)
4 mho. \(\mathrm{cm}^{2}\). equiv \({ }^{-1}\)
CHXII03:ELECTROCHEMISTRY

330377 In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of \({\rm{50}}\,\,{\rm{\Omega }}\) find equivalent conductance of the salt solution?

1 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{120}}\,\,{\rm{S}}\,\,{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{160}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
Join With Us for More Updates
CHXII03:ELECTROCHEMISTRY

330374 The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of \({\rm{0}}{\rm{.88c}}{{\rm{m}}^{{\rm{ - 1}}}}\). The value of equivalent conductance of solution is

1 \({\rm{400}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{295}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{419}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{425}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
CHXII03:ELECTROCHEMISTRY

330375 The conductivity of a saturated solution of Sparingly soluble salt (x-factor = 1) is \({\rm{1}}{\rm{.53 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}\) and its conductance is \({\rm{0}}{\rm{.765oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{equi}}{{\rm{v}}^{{\rm{ - 1}}}}\). The molarity of sparingly soluble salt will be

1 \({\rm{1}}{{\rm{0}}^{{\rm{ - 6}}}}\)
2 \({\rm{25 \times 1}}{{\rm{0}}^{{\rm{ - 9}}}}\)
3 \({\rm{4 \times 1}}{{\rm{0}}^{{\rm{ - 12}}}}\)
4 \({\rm{2 \times 1}}{{\rm{0}}^{{\rm{ - 2}}}}\)
CHXII03:ELECTROCHEMISTRY

330376 What are the units of equivalent conductivity of a solution?

1 mho. \(\mathrm{cm}^{-1}\)
2 ohm. \(\mathrm{cm}^{-1} \cdot \mathrm{g}\) equiv \({ }^{-1}\)
3 mho. \(\mathrm{cm}^{-2}\). g equiv \({ }^{-1}\)
4 mho. \(\mathrm{cm}^{2}\). equiv \({ }^{-1}\)
CHXII03:ELECTROCHEMISTRY

330377 In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of \({\rm{50}}\,\,{\rm{\Omega }}\) find equivalent conductance of the salt solution?

1 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{120}}\,\,{\rm{S}}\,\,{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{160}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII03:ELECTROCHEMISTRY

330374 The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of \({\rm{0}}{\rm{.88c}}{{\rm{m}}^{{\rm{ - 1}}}}\). The value of equivalent conductance of solution is

1 \({\rm{400}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{295}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{419}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{425}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{g}}\,\,{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
CHXII03:ELECTROCHEMISTRY

330375 The conductivity of a saturated solution of Sparingly soluble salt (x-factor = 1) is \({\rm{1}}{\rm{.53 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\,\,{\rm{oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}\) and its conductance is \({\rm{0}}{\rm{.765oh}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{c}}{{\rm{m}}^{{\rm{ - 1}}}}{\rm{equi}}{{\rm{v}}^{{\rm{ - 1}}}}\). The molarity of sparingly soluble salt will be

1 \({\rm{1}}{{\rm{0}}^{{\rm{ - 6}}}}\)
2 \({\rm{25 \times 1}}{{\rm{0}}^{{\rm{ - 9}}}}\)
3 \({\rm{4 \times 1}}{{\rm{0}}^{{\rm{ - 12}}}}\)
4 \({\rm{2 \times 1}}{{\rm{0}}^{{\rm{ - 2}}}}\)
CHXII03:ELECTROCHEMISTRY

330376 What are the units of equivalent conductivity of a solution?

1 mho. \(\mathrm{cm}^{-1}\)
2 ohm. \(\mathrm{cm}^{-1} \cdot \mathrm{g}\) equiv \({ }^{-1}\)
3 mho. \(\mathrm{cm}^{-2}\). g equiv \({ }^{-1}\)
4 mho. \(\mathrm{cm}^{2}\). equiv \({ }^{-1}\)
CHXII03:ELECTROCHEMISTRY

330377 In a conductivity cell the two platinum electrodes, each of area 10 sq. cm is fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of \({\rm{50}}\,\,{\rm{\Omega }}\) find equivalent conductance of the salt solution?

1 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
2 \({\rm{120}}\,\,{\rm{S}}\,\,{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
3 \({\rm{160}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
4 \({\rm{125}}\,\,{\rm{S}}\,\,{\rm{c}}{{\rm{m}}^{\rm{2}}}{\rm{e}}{{\rm{q}}^{{\rm{ - 1}}}}\)
NEET DIGITAL LIBRARY