NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXII02:SOLUTIONS
319514
Which one of the following statements regarding Henry’s law is not correct?
1 Different gases have different \({{\rm{K}}_{\rm{H}}}\) (Henry’s law constant) values at the same temperature.
2 The value of \({{\rm{K}}_{\rm{H}}}\) increases with increase of temperature and \({K_H}\) is function of the nature of the gas.
3 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution.
4 Higher the value of \({{\rm{K}}_{\rm{H}}}\) at a given pressure, higher is the solubility of the gas in the liquids.
Explanation:
Higher \({{\rm{K}}_{\rm{H}}}\) - Lower is solubility at a given pressure.
JEE - 2019
CHXII02:SOLUTIONS
319515
Two liquids having vapour pressures \({\rm{P}}_{\rm{1}}^{\rm{o}}\,\,{\rm{and}}\,\,{\rm{P}}_{\rm{2}}^{\rm{o}}\) in pure state in the ratio of 2 : 1 are mixed in the molar ratio of 1 : 2. The ratio of their moles in the vapour state would be
319516
The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene ( \({\mathrm{P_{\mathrm{B}}{ }^{\circ}=120}}\) torr) and toluene ( \({\mathrm{P_{\mathrm{T}}{ }^{\circ}=80}}\) torr) having 2.0 mol of each, is ____ .
319517
A solution has a \({\rm{1:4}}\) mole ratio of pentane to hexane. The vapour pressures of pure hydrocarbons at \({\rm{2}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\) are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in vapour phase would be
319514
Which one of the following statements regarding Henry’s law is not correct?
1 Different gases have different \({{\rm{K}}_{\rm{H}}}\) (Henry’s law constant) values at the same temperature.
2 The value of \({{\rm{K}}_{\rm{H}}}\) increases with increase of temperature and \({K_H}\) is function of the nature of the gas.
3 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution.
4 Higher the value of \({{\rm{K}}_{\rm{H}}}\) at a given pressure, higher is the solubility of the gas in the liquids.
Explanation:
Higher \({{\rm{K}}_{\rm{H}}}\) - Lower is solubility at a given pressure.
JEE - 2019
CHXII02:SOLUTIONS
319515
Two liquids having vapour pressures \({\rm{P}}_{\rm{1}}^{\rm{o}}\,\,{\rm{and}}\,\,{\rm{P}}_{\rm{2}}^{\rm{o}}\) in pure state in the ratio of 2 : 1 are mixed in the molar ratio of 1 : 2. The ratio of their moles in the vapour state would be
319516
The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene ( \({\mathrm{P_{\mathrm{B}}{ }^{\circ}=120}}\) torr) and toluene ( \({\mathrm{P_{\mathrm{T}}{ }^{\circ}=80}}\) torr) having 2.0 mol of each, is ____ .
319517
A solution has a \({\rm{1:4}}\) mole ratio of pentane to hexane. The vapour pressures of pure hydrocarbons at \({\rm{2}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\) are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in vapour phase would be
319514
Which one of the following statements regarding Henry’s law is not correct?
1 Different gases have different \({{\rm{K}}_{\rm{H}}}\) (Henry’s law constant) values at the same temperature.
2 The value of \({{\rm{K}}_{\rm{H}}}\) increases with increase of temperature and \({K_H}\) is function of the nature of the gas.
3 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution.
4 Higher the value of \({{\rm{K}}_{\rm{H}}}\) at a given pressure, higher is the solubility of the gas in the liquids.
Explanation:
Higher \({{\rm{K}}_{\rm{H}}}\) - Lower is solubility at a given pressure.
JEE - 2019
CHXII02:SOLUTIONS
319515
Two liquids having vapour pressures \({\rm{P}}_{\rm{1}}^{\rm{o}}\,\,{\rm{and}}\,\,{\rm{P}}_{\rm{2}}^{\rm{o}}\) in pure state in the ratio of 2 : 1 are mixed in the molar ratio of 1 : 2. The ratio of their moles in the vapour state would be
319516
The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene ( \({\mathrm{P_{\mathrm{B}}{ }^{\circ}=120}}\) torr) and toluene ( \({\mathrm{P_{\mathrm{T}}{ }^{\circ}=80}}\) torr) having 2.0 mol of each, is ____ .
319517
A solution has a \({\rm{1:4}}\) mole ratio of pentane to hexane. The vapour pressures of pure hydrocarbons at \({\rm{2}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\) are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in vapour phase would be
319514
Which one of the following statements regarding Henry’s law is not correct?
1 Different gases have different \({{\rm{K}}_{\rm{H}}}\) (Henry’s law constant) values at the same temperature.
2 The value of \({{\rm{K}}_{\rm{H}}}\) increases with increase of temperature and \({K_H}\) is function of the nature of the gas.
3 The partial pressure of the gas in vapour phase is proportional to the mole fraction of the gas in the solution.
4 Higher the value of \({{\rm{K}}_{\rm{H}}}\) at a given pressure, higher is the solubility of the gas in the liquids.
Explanation:
Higher \({{\rm{K}}_{\rm{H}}}\) - Lower is solubility at a given pressure.
JEE - 2019
CHXII02:SOLUTIONS
319515
Two liquids having vapour pressures \({\rm{P}}_{\rm{1}}^{\rm{o}}\,\,{\rm{and}}\,\,{\rm{P}}_{\rm{2}}^{\rm{o}}\) in pure state in the ratio of 2 : 1 are mixed in the molar ratio of 1 : 2. The ratio of their moles in the vapour state would be
319516
The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene ( \({\mathrm{P_{\mathrm{B}}{ }^{\circ}=120}}\) torr) and toluene ( \({\mathrm{P_{\mathrm{T}}{ }^{\circ}=80}}\) torr) having 2.0 mol of each, is ____ .
319517
A solution has a \({\rm{1:4}}\) mole ratio of pentane to hexane. The vapour pressures of pure hydrocarbons at \({\rm{2}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\) are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in vapour phase would be
