Relative Lowering of Vapour Pressure
CHXII02:SOLUTIONS

319356 What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )

1 2.59 g
2 3.69 g
3 3.59 g
4 4.69 g
CHXII02:SOLUTIONS

319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:

1 0.25
2 0.75
3 0.5
4 0.35
CHXII02:SOLUTIONS

319358 Which of the following solutions have more lowering in vapour pressure at a certain temperature?

1 90 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
2 34.2 grams of sucrose in 450 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
3 20 grams of urea in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
4 45 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
CHXII02:SOLUTIONS

319359 The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is

1 1 g
2 3 g
3 6 g
4 18 g
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CHXII02:SOLUTIONS

319356 What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )

1 2.59 g
2 3.69 g
3 3.59 g
4 4.69 g
CHXII02:SOLUTIONS

319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:

1 0.25
2 0.75
3 0.5
4 0.35
CHXII02:SOLUTIONS

319358 Which of the following solutions have more lowering in vapour pressure at a certain temperature?

1 90 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
2 34.2 grams of sucrose in 450 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
3 20 grams of urea in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
4 45 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
CHXII02:SOLUTIONS

319359 The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is

1 1 g
2 3 g
3 6 g
4 18 g
CHXII02:SOLUTIONS

319356 What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )

1 2.59 g
2 3.69 g
3 3.59 g
4 4.69 g
CHXII02:SOLUTIONS

319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:

1 0.25
2 0.75
3 0.5
4 0.35
CHXII02:SOLUTIONS

319358 Which of the following solutions have more lowering in vapour pressure at a certain temperature?

1 90 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
2 34.2 grams of sucrose in 450 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
3 20 grams of urea in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
4 45 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
CHXII02:SOLUTIONS

319359 The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is

1 1 g
2 3 g
3 6 g
4 18 g
CHXII02:SOLUTIONS

319356 What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )

1 2.59 g
2 3.69 g
3 3.59 g
4 4.69 g
CHXII02:SOLUTIONS

319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:

1 0.25
2 0.75
3 0.5
4 0.35
CHXII02:SOLUTIONS

319358 Which of the following solutions have more lowering in vapour pressure at a certain temperature?

1 90 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
2 34.2 grams of sucrose in 450 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
3 20 grams of urea in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
4 45 grams of glucose in 900 grams of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)
CHXII02:SOLUTIONS

319359 The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1 g of urea in the same quantity of water is

1 1 g
2 3 g
3 6 g
4 18 g