319356
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )
319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:
319356
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )
319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:
319356
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )
319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is:
319356
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg ? (Assume dilute solution is being formed.)
(Given : Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-1}\). )
319357 The vapour pressure of pure solvent is \(0.8 \mathrm{~mm}\) of \(\mathrm{Hg}\) at a particular temperature. On addition of a non-volatile solute ' \(\mathrm{A}\) ', the vapour pressure of solution becomes \(0.6 \mathrm{~mm}\) of \(\mathrm{Hg}\). The mole dfraction of component ' \(\mathrm{A}\) ' is: