Expressing Concentration of Solutions
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII02:SOLUTIONS

319190 250 mL of a sodium carbonate solution contains 2.65 grams of \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\). 10 mL of this solution is added to x mL of water to obtain 0.001 M \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\) solution. What is the value of x in mL?
\(\left( {{\rm{Molecular}}{\mkern 1mu} {\mkern 1mu} {\rm{weight}}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ = 106}}} \right)\)

1 1000
2 990
3 9990
4 90
CHXII02:SOLUTIONS

319191 The molarity of 0.006 mole of NaCl in 100 ml solution is

1 0.06
2 0.006
3 0.6
4 0.066
CHXII02:SOLUTIONS

319192 To neutralise completely \(20 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) aqueous
solution of phosphorous acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{3}\right)\), the value
of \(0.1 \mathrm{M}\) aqueous \(\mathrm{KOH}\) solution required is

1 \(40 \mathrm{~mL}\)
2 \(20 \mathrm{~mL}\)
3 \(10 \mathrm{~mL}\)
4 \(60 \mathrm{~mL}\)
CHXII02:SOLUTIONS

319193 Equal volumes of 0.1 M \({\rm{AgN}}{{\rm{O}}_{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{0}}{\rm{.2}}\,\,{\rm{M}}\,\,{\rm{NaCl}}\) are mixed. The concentration of \({\rm{NO}}_{\rm{3}}^{\rm{ - }}\) ions in the mixture will be

1 0.1 M
2 0.05 M
3 0.2 M
4 0.15 M
CHXII02:SOLUTIONS

319190 250 mL of a sodium carbonate solution contains 2.65 grams of \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\). 10 mL of this solution is added to x mL of water to obtain 0.001 M \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\) solution. What is the value of x in mL?
\(\left( {{\rm{Molecular}}{\mkern 1mu} {\mkern 1mu} {\rm{weight}}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ = 106}}} \right)\)

1 1000
2 990
3 9990
4 90
CHXII02:SOLUTIONS

319191 The molarity of 0.006 mole of NaCl in 100 ml solution is

1 0.06
2 0.006
3 0.6
4 0.066
CHXII02:SOLUTIONS

319192 To neutralise completely \(20 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) aqueous
solution of phosphorous acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{3}\right)\), the value
of \(0.1 \mathrm{M}\) aqueous \(\mathrm{KOH}\) solution required is

1 \(40 \mathrm{~mL}\)
2 \(20 \mathrm{~mL}\)
3 \(10 \mathrm{~mL}\)
4 \(60 \mathrm{~mL}\)
CHXII02:SOLUTIONS

319193 Equal volumes of 0.1 M \({\rm{AgN}}{{\rm{O}}_{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{0}}{\rm{.2}}\,\,{\rm{M}}\,\,{\rm{NaCl}}\) are mixed. The concentration of \({\rm{NO}}_{\rm{3}}^{\rm{ - }}\) ions in the mixture will be

1 0.1 M
2 0.05 M
3 0.2 M
4 0.15 M
CHXII02:SOLUTIONS

319190 250 mL of a sodium carbonate solution contains 2.65 grams of \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\). 10 mL of this solution is added to x mL of water to obtain 0.001 M \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\) solution. What is the value of x in mL?
\(\left( {{\rm{Molecular}}{\mkern 1mu} {\mkern 1mu} {\rm{weight}}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ = 106}}} \right)\)

1 1000
2 990
3 9990
4 90
CHXII02:SOLUTIONS

319191 The molarity of 0.006 mole of NaCl in 100 ml solution is

1 0.06
2 0.006
3 0.6
4 0.066
CHXII02:SOLUTIONS

319192 To neutralise completely \(20 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) aqueous
solution of phosphorous acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{3}\right)\), the value
of \(0.1 \mathrm{M}\) aqueous \(\mathrm{KOH}\) solution required is

1 \(40 \mathrm{~mL}\)
2 \(20 \mathrm{~mL}\)
3 \(10 \mathrm{~mL}\)
4 \(60 \mathrm{~mL}\)
CHXII02:SOLUTIONS

319193 Equal volumes of 0.1 M \({\rm{AgN}}{{\rm{O}}_{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{0}}{\rm{.2}}\,\,{\rm{M}}\,\,{\rm{NaCl}}\) are mixed. The concentration of \({\rm{NO}}_{\rm{3}}^{\rm{ - }}\) ions in the mixture will be

1 0.1 M
2 0.05 M
3 0.2 M
4 0.15 M
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII02:SOLUTIONS

319190 250 mL of a sodium carbonate solution contains 2.65 grams of \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\). 10 mL of this solution is added to x mL of water to obtain 0.001 M \({\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}\) solution. What is the value of x in mL?
\(\left( {{\rm{Molecular}}{\mkern 1mu} {\mkern 1mu} {\rm{weight}}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{N}}{{\rm{a}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{ = 106}}} \right)\)

1 1000
2 990
3 9990
4 90
CHXII02:SOLUTIONS

319191 The molarity of 0.006 mole of NaCl in 100 ml solution is

1 0.06
2 0.006
3 0.6
4 0.066
CHXII02:SOLUTIONS

319192 To neutralise completely \(20 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) aqueous
solution of phosphorous acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{3}\right)\), the value
of \(0.1 \mathrm{M}\) aqueous \(\mathrm{KOH}\) solution required is

1 \(40 \mathrm{~mL}\)
2 \(20 \mathrm{~mL}\)
3 \(10 \mathrm{~mL}\)
4 \(60 \mathrm{~mL}\)
CHXII02:SOLUTIONS

319193 Equal volumes of 0.1 M \({\rm{AgN}}{{\rm{O}}_{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{0}}{\rm{.2}}\,\,{\rm{M}}\,\,{\rm{NaCl}}\) are mixed. The concentration of \({\rm{NO}}_{\rm{3}}^{\rm{ - }}\) ions in the mixture will be

1 0.1 M
2 0.05 M
3 0.2 M
4 0.15 M