319195
The molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL of water is (Given : Molar mass Na: 23 and \(\left.\mathrm{Cl}: 35.5 \mathrm{~g} \mathrm{~mol}^{-1}\right)\)
1 4
2 20
3 0.2
4 2
Explanation:
\({\mathrm{\mathrm{M}=\dfrac{\operatorname{mass}(\mathrm{g})}{\text { gram molar mass }} \times \dfrac{1000}{\mathrm{~V}(\mathrm{~mL})}}}\) \(\begin{aligned}& =\dfrac{5.85}{58.5} \times \dfrac{1000}{500} \\& =0.2 \mathrm{M}\end{aligned}\) So, the correct option is (3).
JEE Main - 2024
CHXII02:SOLUTIONS
319196
Which of the following contains more number of ions per unit volume?
319195
The molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL of water is (Given : Molar mass Na: 23 and \(\left.\mathrm{Cl}: 35.5 \mathrm{~g} \mathrm{~mol}^{-1}\right)\)
1 4
2 20
3 0.2
4 2
Explanation:
\({\mathrm{\mathrm{M}=\dfrac{\operatorname{mass}(\mathrm{g})}{\text { gram molar mass }} \times \dfrac{1000}{\mathrm{~V}(\mathrm{~mL})}}}\) \(\begin{aligned}& =\dfrac{5.85}{58.5} \times \dfrac{1000}{500} \\& =0.2 \mathrm{M}\end{aligned}\) So, the correct option is (3).
JEE Main - 2024
CHXII02:SOLUTIONS
319196
Which of the following contains more number of ions per unit volume?
319195
The molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL of water is (Given : Molar mass Na: 23 and \(\left.\mathrm{Cl}: 35.5 \mathrm{~g} \mathrm{~mol}^{-1}\right)\)
1 4
2 20
3 0.2
4 2
Explanation:
\({\mathrm{\mathrm{M}=\dfrac{\operatorname{mass}(\mathrm{g})}{\text { gram molar mass }} \times \dfrac{1000}{\mathrm{~V}(\mathrm{~mL})}}}\) \(\begin{aligned}& =\dfrac{5.85}{58.5} \times \dfrac{1000}{500} \\& =0.2 \mathrm{M}\end{aligned}\) So, the correct option is (3).
JEE Main - 2024
CHXII02:SOLUTIONS
319196
Which of the following contains more number of ions per unit volume?
319195
The molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL of water is (Given : Molar mass Na: 23 and \(\left.\mathrm{Cl}: 35.5 \mathrm{~g} \mathrm{~mol}^{-1}\right)\)
1 4
2 20
3 0.2
4 2
Explanation:
\({\mathrm{\mathrm{M}=\dfrac{\operatorname{mass}(\mathrm{g})}{\text { gram molar mass }} \times \dfrac{1000}{\mathrm{~V}(\mathrm{~mL})}}}\) \(\begin{aligned}& =\dfrac{5.85}{58.5} \times \dfrac{1000}{500} \\& =0.2 \mathrm{M}\end{aligned}\) So, the correct option is (3).
JEE Main - 2024
CHXII02:SOLUTIONS
319196
Which of the following contains more number of ions per unit volume?