318030 The intermediate carbocation formed in the reactions of \(\mathrm{HI}, \mathrm{HBr}\) and \(\mathrm{HCl}\) with propene is the same and the bond energy of \(\mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) is \(430.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 363.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and 296.8 \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. What will be the order of reactivity of these halogen acids?

318031 The reaction of propene with \(\mathrm{HOCl}\left(\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}\right)\) proceeds through the intermediate:

318032
How many products will be formed in above reaction?

318033 The addition of \(\mathrm{HI}\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

318034 3-phenylpropene on reaction with \(\mathrm{HBr}\) gives (as a major product)

318030 The intermediate carbocation formed in the reactions of \(\mathrm{HI}, \mathrm{HBr}\) and \(\mathrm{HCl}\) with propene is the same and the bond energy of \(\mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) is \(430.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 363.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and 296.8 \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. What will be the order of reactivity of these halogen acids?

318031 The reaction of propene with \(\mathrm{HOCl}\left(\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}\right)\) proceeds through the intermediate:

318032
How many products will be formed in above reaction?

318033 The addition of \(\mathrm{HI}\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

318034 3-phenylpropene on reaction with \(\mathrm{HBr}\) gives (as a major product)

318030 The intermediate carbocation formed in the reactions of \(\mathrm{HI}, \mathrm{HBr}\) and \(\mathrm{HCl}\) with propene is the same and the bond energy of \(\mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) is \(430.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 363.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and 296.8 \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. What will be the order of reactivity of these halogen acids?

318031 The reaction of propene with \(\mathrm{HOCl}\left(\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}\right)\) proceeds through the intermediate:

318032
How many products will be formed in above reaction?

318033 The addition of \(\mathrm{HI}\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

318034 3-phenylpropene on reaction with \(\mathrm{HBr}\) gives (as a major product)

318030 The intermediate carbocation formed in the reactions of \(\mathrm{HI}, \mathrm{HBr}\) and \(\mathrm{HCl}\) with propene is the same and the bond energy of \(\mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) is \(430.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 363.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and 296.8 \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. What will be the order of reactivity of these halogen acids?

318031 The reaction of propene with \(\mathrm{HOCl}\left(\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}\right)\) proceeds through the intermediate:

318032
How many products will be formed in above reaction?

318033 The addition of \(\mathrm{HI}\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

318034 3-phenylpropene on reaction with \(\mathrm{HBr}\) gives (as a major product)

318030 The intermediate carbocation formed in the reactions of \(\mathrm{HI}, \mathrm{HBr}\) and \(\mathrm{HCl}\) with propene is the same and the bond energy of \(\mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) is \(430.5 \mathrm{~kJ} \mathrm{~mol}^{-1}, 363.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and 296.8 \(\mathrm{kJ} \mathrm{mol}^{-1}\) respectively. What will be the order of reactivity of these halogen acids?

318031 The reaction of propene with \(\mathrm{HOCl}\left(\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}\right)\) proceeds through the intermediate:

318032
How many products will be formed in above reaction?

318033 The addition of \(\mathrm{HI}\) in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

318034 3-phenylpropene on reaction with \(\mathrm{HBr}\) gives (as a major product)