317865
The number of enantiomeric pairs that is produced by the monochlorination of 2-Methylbutane is
1 1
2 2
3 3
4 4
Explanation:
Only one enantiomeric pair formed.
CHXI13:HYDROCARBONS
317866
The inhibitor used to control halogenation of alkanes is -
1 Tetra Ethyl Lead
2 Ozone
3 Inert gas
4 Oxygen
Explanation:
The inhibitor is oxygen. It reacts with intermediate alkyl radical to form ROO • radical which is very less reactive and thus helps to control the reaction.
CHXI13:HYDROCARBONS
317867
Assertion : Chlorination of methane gives a mixture of products. Reason : Chlorination proceeds through the formation of carbanion.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chlorination of methane occurs through the formation of free radicals and at \(520-670 \mathrm{~K}\) gives a mixture of four products i.e., \(\mathrm{CH}_{3} \mathrm{Cl}, \mathrm{CH}_{2} \mathrm{Cl}_{2}, \mathrm{CHCl}_{3}\) and \(\mathrm{CCl}_{4}\). So, option (3) is correct.
CHXI13:HYDROCARBONS
317868
Arrange the halogens \({{\text{F}}_{\text{2}}}{\text{, C}}{{\text{l}}_{\text{2}}}{\text{, B}}{{\text{r}}_{\text{2}}}{\text{, }}{{\text{I}}_{\text{2}}}{\text{,}}\) in order of their increasing reactivity with alkanes.
317865
The number of enantiomeric pairs that is produced by the monochlorination of 2-Methylbutane is
1 1
2 2
3 3
4 4
Explanation:
Only one enantiomeric pair formed.
CHXI13:HYDROCARBONS
317866
The inhibitor used to control halogenation of alkanes is -
1 Tetra Ethyl Lead
2 Ozone
3 Inert gas
4 Oxygen
Explanation:
The inhibitor is oxygen. It reacts with intermediate alkyl radical to form ROO • radical which is very less reactive and thus helps to control the reaction.
CHXI13:HYDROCARBONS
317867
Assertion : Chlorination of methane gives a mixture of products. Reason : Chlorination proceeds through the formation of carbanion.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chlorination of methane occurs through the formation of free radicals and at \(520-670 \mathrm{~K}\) gives a mixture of four products i.e., \(\mathrm{CH}_{3} \mathrm{Cl}, \mathrm{CH}_{2} \mathrm{Cl}_{2}, \mathrm{CHCl}_{3}\) and \(\mathrm{CCl}_{4}\). So, option (3) is correct.
CHXI13:HYDROCARBONS
317868
Arrange the halogens \({{\text{F}}_{\text{2}}}{\text{, C}}{{\text{l}}_{\text{2}}}{\text{, B}}{{\text{r}}_{\text{2}}}{\text{, }}{{\text{I}}_{\text{2}}}{\text{,}}\) in order of their increasing reactivity with alkanes.
317865
The number of enantiomeric pairs that is produced by the monochlorination of 2-Methylbutane is
1 1
2 2
3 3
4 4
Explanation:
Only one enantiomeric pair formed.
CHXI13:HYDROCARBONS
317866
The inhibitor used to control halogenation of alkanes is -
1 Tetra Ethyl Lead
2 Ozone
3 Inert gas
4 Oxygen
Explanation:
The inhibitor is oxygen. It reacts with intermediate alkyl radical to form ROO • radical which is very less reactive and thus helps to control the reaction.
CHXI13:HYDROCARBONS
317867
Assertion : Chlorination of methane gives a mixture of products. Reason : Chlorination proceeds through the formation of carbanion.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chlorination of methane occurs through the formation of free radicals and at \(520-670 \mathrm{~K}\) gives a mixture of four products i.e., \(\mathrm{CH}_{3} \mathrm{Cl}, \mathrm{CH}_{2} \mathrm{Cl}_{2}, \mathrm{CHCl}_{3}\) and \(\mathrm{CCl}_{4}\). So, option (3) is correct.
CHXI13:HYDROCARBONS
317868
Arrange the halogens \({{\text{F}}_{\text{2}}}{\text{, C}}{{\text{l}}_{\text{2}}}{\text{, B}}{{\text{r}}_{\text{2}}}{\text{, }}{{\text{I}}_{\text{2}}}{\text{,}}\) in order of their increasing reactivity with alkanes.
317865
The number of enantiomeric pairs that is produced by the monochlorination of 2-Methylbutane is
1 1
2 2
3 3
4 4
Explanation:
Only one enantiomeric pair formed.
CHXI13:HYDROCARBONS
317866
The inhibitor used to control halogenation of alkanes is -
1 Tetra Ethyl Lead
2 Ozone
3 Inert gas
4 Oxygen
Explanation:
The inhibitor is oxygen. It reacts with intermediate alkyl radical to form ROO • radical which is very less reactive and thus helps to control the reaction.
CHXI13:HYDROCARBONS
317867
Assertion : Chlorination of methane gives a mixture of products. Reason : Chlorination proceeds through the formation of carbanion.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chlorination of methane occurs through the formation of free radicals and at \(520-670 \mathrm{~K}\) gives a mixture of four products i.e., \(\mathrm{CH}_{3} \mathrm{Cl}, \mathrm{CH}_{2} \mathrm{Cl}_{2}, \mathrm{CHCl}_{3}\) and \(\mathrm{CCl}_{4}\). So, option (3) is correct.
CHXI13:HYDROCARBONS
317868
Arrange the halogens \({{\text{F}}_{\text{2}}}{\text{, C}}{{\text{l}}_{\text{2}}}{\text{, B}}{{\text{r}}_{\text{2}}}{\text{, }}{{\text{I}}_{\text{2}}}{\text{,}}\) in order of their increasing reactivity with alkanes.
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