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CHXI11:THE P-BLOCK ELEMENTS

316735 Nitric acid (conc.) oxidises phosphorus to :

1

H_{3} {PO}_{4}

2

P_{2} O_{3}

3

H_{3} {PO}_{3}

4

H_{4} P_{2} O_{7}

Explanation:

$P_{4} + 20 {HNO}_{3} \to 4 H_{3} {PO}_{4} + 20 {NO}_{2} + 4 H_{2} O$

CHXI11:THE P-BLOCK ELEMENTS

316736 The correct statements about ${HNO}_{3}$ are
I. ${HNO}_{3}$ acts as a dehydrating agent
II. The proteins are converted into xanthoproteins
III. ${HNO}_{3}$ acts as an oxidising agent
IV. It exists in two canonical forms
The correct option is

1 I, II and III

2 II, III and IV

3 I, III and IV

4 I, II and IV

Explanation:

${HNO}_{3}$ is an oxidising not dehydrating agent.

CHXI11:THE P-BLOCK ELEMENTS

316737 Which of the following products will be obtained when copper metal is reacted with ${HNO}_{3}$ ?

1

NO

and

N_{2} O_{5}

2

NO

and

{NO}_{2}

3

{NO}_{2}

and

N_{2} O_{5}

4

{HNO}_{2}

and

N_{2}

Explanation:

The products of copper reaction with ${HNO}_{3}$ depends upon the concentration of ${HNO}_{3}$ used.
Copper metal reacts with dilute ${HNO}_{3}$ to form nitrogen (II) oxide (NO).
$\begin{aligned} 3 Cu + 8 {HNO}_{3} (dil.) \to \\ 3 Cu {({NO}_{3})}_{2} + 2 NO + 4 H_{2} O \end{aligned}$
Copper metal reacts with conc. ${HNO}_{3}$ to form nitrogen (IV) oxide or nitrogen dioxide $({NO}_{2})$ . $Cu + 4 {HNO}_{3}$ (conc.) $\to Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O$

AIIMS - 2018

CHXI11:THE P-BLOCK ELEMENTS

316738 Assertion :
${HNO}_{3}$ is a stronger acid than ${HNO}_{2}$ .
Reason :
In ${HNO}_{3}$ there are two nitrogen oxygen bonds while in ${HNO}_{2}$ it is only one.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

supporting img
The acid strength of ${HNO}_{3}$ is higher than that of ${HNO}_{2}$ due to the higher oxidation state of nitrogen ( +5 in ${HNO}_{3}$ compared to +3 in ${HNO}_{2}$ ). Therefore, option (3) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316735 Nitric acid (conc.) oxidises phosphorus to :

1

H_{3} {PO}_{4}

2

P_{2} O_{3}

3

H_{3} {PO}_{3}

4

H_{4} P_{2} O_{7}

Explanation:

$P_{4} + 20 {HNO}_{3} \to 4 H_{3} {PO}_{4} + 20 {NO}_{2} + 4 H_{2} O$

CHXI11:THE P-BLOCK ELEMENTS

316736 The correct statements about ${HNO}_{3}$ are
I. ${HNO}_{3}$ acts as a dehydrating agent
II. The proteins are converted into xanthoproteins
III. ${HNO}_{3}$ acts as an oxidising agent
IV. It exists in two canonical forms
The correct option is

1 I, II and III

2 II, III and IV

3 I, III and IV

4 I, II and IV

Explanation:

${HNO}_{3}$ is an oxidising not dehydrating agent.

CHXI11:THE P-BLOCK ELEMENTS

316737 Which of the following products will be obtained when copper metal is reacted with ${HNO}_{3}$ ?

1

NO

and

N_{2} O_{5}

2

NO

and

{NO}_{2}

3

{NO}_{2}

and

N_{2} O_{5}

4

{HNO}_{2}

and

N_{2}

Explanation:

The products of copper reaction with ${HNO}_{3}$ depends upon the concentration of ${HNO}_{3}$ used.
Copper metal reacts with dilute ${HNO}_{3}$ to form nitrogen (II) oxide (NO).
$\begin{aligned} 3 Cu + 8 {HNO}_{3} (dil.) \to \\ 3 Cu {({NO}_{3})}_{2} + 2 NO + 4 H_{2} O \end{aligned}$
Copper metal reacts with conc. ${HNO}_{3}$ to form nitrogen (IV) oxide or nitrogen dioxide $({NO}_{2})$ . $Cu + 4 {HNO}_{3}$ (conc.) $\to Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O$

AIIMS - 2018

CHXI11:THE P-BLOCK ELEMENTS

316738 Assertion :
${HNO}_{3}$ is a stronger acid than ${HNO}_{2}$ .
Reason :
In ${HNO}_{3}$ there are two nitrogen oxygen bonds while in ${HNO}_{2}$ it is only one.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

supporting img
The acid strength of ${HNO}_{3}$ is higher than that of ${HNO}_{2}$ due to the higher oxidation state of nitrogen ( +5 in ${HNO}_{3}$ compared to +3 in ${HNO}_{2}$ ). Therefore, option (3) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316735 Nitric acid (conc.) oxidises phosphorus to :

1

H_{3} {PO}_{4}

2

P_{2} O_{3}

3

H_{3} {PO}_{3}

4

H_{4} P_{2} O_{7}

Explanation:

$P_{4} + 20 {HNO}_{3} \to 4 H_{3} {PO}_{4} + 20 {NO}_{2} + 4 H_{2} O$

CHXI11:THE P-BLOCK ELEMENTS

316736 The correct statements about ${HNO}_{3}$ are
I. ${HNO}_{3}$ acts as a dehydrating agent
II. The proteins are converted into xanthoproteins
III. ${HNO}_{3}$ acts as an oxidising agent
IV. It exists in two canonical forms
The correct option is

1 I, II and III

2 II, III and IV

3 I, III and IV

4 I, II and IV

Explanation:

${HNO}_{3}$ is an oxidising not dehydrating agent.

CHXI11:THE P-BLOCK ELEMENTS

316737 Which of the following products will be obtained when copper metal is reacted with ${HNO}_{3}$ ?

1

NO

and

N_{2} O_{5}

2

NO

and

{NO}_{2}

3

{NO}_{2}

and

N_{2} O_{5}

4

{HNO}_{2}

and

N_{2}

Explanation:

The products of copper reaction with ${HNO}_{3}$ depends upon the concentration of ${HNO}_{3}$ used.
Copper metal reacts with dilute ${HNO}_{3}$ to form nitrogen (II) oxide (NO).
$\begin{aligned} 3 Cu + 8 {HNO}_{3} (dil.) \to \\ 3 Cu {({NO}_{3})}_{2} + 2 NO + 4 H_{2} O \end{aligned}$
Copper metal reacts with conc. ${HNO}_{3}$ to form nitrogen (IV) oxide or nitrogen dioxide $({NO}_{2})$ . $Cu + 4 {HNO}_{3}$ (conc.) $\to Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O$

AIIMS - 2018

CHXI11:THE P-BLOCK ELEMENTS

316738 Assertion :
${HNO}_{3}$ is a stronger acid than ${HNO}_{2}$ .
Reason :
In ${HNO}_{3}$ there are two nitrogen oxygen bonds while in ${HNO}_{2}$ it is only one.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

supporting img
The acid strength of ${HNO}_{3}$ is higher than that of ${HNO}_{2}$ due to the higher oxidation state of nitrogen ( +5 in ${HNO}_{3}$ compared to +3 in ${HNO}_{2}$ ). Therefore, option (3) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316735 Nitric acid (conc.) oxidises phosphorus to :

1

H_{3} {PO}_{4}

2

P_{2} O_{3}

3

H_{3} {PO}_{3}

4

H_{4} P_{2} O_{7}

Explanation:

$P_{4} + 20 {HNO}_{3} \to 4 H_{3} {PO}_{4} + 20 {NO}_{2} + 4 H_{2} O$

CHXI11:THE P-BLOCK ELEMENTS

316736 The correct statements about ${HNO}_{3}$ are
I. ${HNO}_{3}$ acts as a dehydrating agent
II. The proteins are converted into xanthoproteins
III. ${HNO}_{3}$ acts as an oxidising agent
IV. It exists in two canonical forms
The correct option is

1 I, II and III

2 II, III and IV

3 I, III and IV

4 I, II and IV

Explanation:

${HNO}_{3}$ is an oxidising not dehydrating agent.

CHXI11:THE P-BLOCK ELEMENTS

316737 Which of the following products will be obtained when copper metal is reacted with ${HNO}_{3}$ ?

1

NO

and

N_{2} O_{5}

2

NO

and

{NO}_{2}

3

{NO}_{2}

and

N_{2} O_{5}

4

{HNO}_{2}

and

N_{2}

Explanation:

The products of copper reaction with ${HNO}_{3}$ depends upon the concentration of ${HNO}_{3}$ used.
Copper metal reacts with dilute ${HNO}_{3}$ to form nitrogen (II) oxide (NO).
$\begin{aligned} 3 Cu + 8 {HNO}_{3} (dil.) \to \\ 3 Cu {({NO}_{3})}_{2} + 2 NO + 4 H_{2} O \end{aligned}$
Copper metal reacts with conc. ${HNO}_{3}$ to form nitrogen (IV) oxide or nitrogen dioxide $({NO}_{2})$ . $Cu + 4 {HNO}_{3}$ (conc.) $\to Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O$

AIIMS - 2018

CHXI11:THE P-BLOCK ELEMENTS

316738 Assertion :
${HNO}_{3}$ is a stronger acid than ${HNO}_{2}$ .
Reason :
In ${HNO}_{3}$ there are two nitrogen oxygen bonds while in ${HNO}_{2}$ it is only one.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

supporting img
The acid strength of ${HNO}_{3}$ is higher than that of ${HNO}_{2}$ due to the higher oxidation state of nitrogen ( +5 in ${HNO}_{3}$ compared to +3 in ${HNO}_{2}$ ). Therefore, option (3) is correct.

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