CHXI11:THE P-BLOCK ELEMENTS
316739
A brown ring is formed in the ring test for \(\mathrm{NO}_{3}^{-}\) ion. It is due to formation of:
1 \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right]^{2+}\)
2 \(\mathrm{FeSO}_{4} \mathrm{NO}_{2}\)
3 \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}(\mathrm{NO})_{2}\right]^{2+}\)
4 \(\mathrm{FeSO}_{4} \cdot \mathrm{HNO}_{3}\)
Explanation:
\(\mathrm{NO}_{3}^{-}+3 \mathrm{Fe}^{2+}+4 \mathrm{H}^{+} \rightarrow \mathrm{NO}+3 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O}\)
\(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+\mathrm{NO} \rightarrow\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right]^{2+}+\mathrm{H}_{2} \mathrm{O}\)