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CHXI11:THE P-BLOCK ELEMENTS

316674 Which is not the correct statement?

1 The

S_{8}

ring is not planar

2 Oxygen is more electronegative than sulphur

3

{SF}_{4}

exists but

{OF}_{4}

does not exist

4

{SO}_{3}

and

{SO}_{3}^{2 -}

both have trigonal planar geometry

Explanation:

${SO}_{3}$ is trigonal planar due to ${sp}^{2}$ hybridised sulphur. ${SO}_{3}^{2 -}$ is ${sp}^{3}$ hybridised, but pyramidal due to presence of a lone pair of electrons.

AIIMS - 2011

CHXI11:THE P-BLOCK ELEMENTS

316675 Which one of the following is wrongly matched?

1

{C l O}_{3}^{-}, s p^{3}

, pyramidal

2

{C l O}_{4}^{-}, s p^{3}

, tetrahedral

3

{I C l}_{4}^{-}, s p^{3} d^{2}

, square planar

4

{I C l}_{2}^{-}, d s p^{2}

, trigonal bipyramidal

Explanation:

${I C l}_{2}^{-}, s p^{3} d$ , trigonal bipyramidal

CHXI11:THE P-BLOCK ELEMENTS

316676 On addition of conc. $H_{2} {SO}_{4}$ to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because

1

H_{2} {SO}_{4}

reduces

HI

to

I_{2}

2

HI

is of violet colour

3

HI

gets oxidised to

I_{2}

4

HI

changes to

{HIO}_{3}

CHXI11:THE P-BLOCK ELEMENTS

316677 A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.

1

{Br}_{2}, {KBrO}_{3}

2

{Cl}_{2}, {KClO}_{3}

3

I_{2}, {NaIO}_{3}

4

{Cl}_{2}, {NaClO}_{3}

Explanation:

${Cl}_{2}$ is greenish yellow gas and it reacts with $KOH$ to form ${KClO}_{3}$ which is used in fire works and safety matches.
$3 {Cl}_{2} + 6 KOH \to {KClO}_{3} + 5 KCl + 3 H_{2} O$

AIIMS - 2019

CHXI11:THE P-BLOCK ELEMENTS

316674 Which is not the correct statement?

1 The

S_{8}

ring is not planar

2 Oxygen is more electronegative than sulphur

3

{SF}_{4}

exists but

{OF}_{4}

does not exist

4

{SO}_{3}

and

{SO}_{3}^{2 -}

both have trigonal planar geometry

Explanation:

${SO}_{3}$ is trigonal planar due to ${sp}^{2}$ hybridised sulphur. ${SO}_{3}^{2 -}$ is ${sp}^{3}$ hybridised, but pyramidal due to presence of a lone pair of electrons.

AIIMS - 2011

CHXI11:THE P-BLOCK ELEMENTS

316675 Which one of the following is wrongly matched?

1

{C l O}_{3}^{-}, s p^{3}

, pyramidal

2

{C l O}_{4}^{-}, s p^{3}

, tetrahedral

3

{I C l}_{4}^{-}, s p^{3} d^{2}

, square planar

4

{I C l}_{2}^{-}, d s p^{2}

, trigonal bipyramidal

Explanation:

${I C l}_{2}^{-}, s p^{3} d$ , trigonal bipyramidal

CHXI11:THE P-BLOCK ELEMENTS

316676 On addition of conc. $H_{2} {SO}_{4}$ to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because

1

H_{2} {SO}_{4}

reduces

HI

to

I_{2}

2

HI

is of violet colour

3

HI

gets oxidised to

I_{2}

4

HI

changes to

{HIO}_{3}

CHXI11:THE P-BLOCK ELEMENTS

316677 A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.

1

{Br}_{2}, {KBrO}_{3}

2

{Cl}_{2}, {KClO}_{3}

3

I_{2}, {NaIO}_{3}

4

{Cl}_{2}, {NaClO}_{3}

Explanation:

${Cl}_{2}$ is greenish yellow gas and it reacts with $KOH$ to form ${KClO}_{3}$ which is used in fire works and safety matches.
$3 {Cl}_{2} + 6 KOH \to {KClO}_{3} + 5 KCl + 3 H_{2} O$

AIIMS - 2019

CHXI11:THE P-BLOCK ELEMENTS

316674 Which is not the correct statement?

1 The

S_{8}

ring is not planar

2 Oxygen is more electronegative than sulphur

3

{SF}_{4}

exists but

{OF}_{4}

does not exist

4

{SO}_{3}

and

{SO}_{3}^{2 -}

both have trigonal planar geometry

Explanation:

${SO}_{3}$ is trigonal planar due to ${sp}^{2}$ hybridised sulphur. ${SO}_{3}^{2 -}$ is ${sp}^{3}$ hybridised, but pyramidal due to presence of a lone pair of electrons.

AIIMS - 2011

CHXI11:THE P-BLOCK ELEMENTS

316675 Which one of the following is wrongly matched?

1

{C l O}_{3}^{-}, s p^{3}

, pyramidal

2

{C l O}_{4}^{-}, s p^{3}

, tetrahedral

3

{I C l}_{4}^{-}, s p^{3} d^{2}

, square planar

4

{I C l}_{2}^{-}, d s p^{2}

, trigonal bipyramidal

Explanation:

${I C l}_{2}^{-}, s p^{3} d$ , trigonal bipyramidal

CHXI11:THE P-BLOCK ELEMENTS

316676 On addition of conc. $H_{2} {SO}_{4}$ to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because

1

H_{2} {SO}_{4}

reduces

HI

to

I_{2}

2

HI

is of violet colour

3

HI

gets oxidised to

I_{2}

4

HI

changes to

{HIO}_{3}

CHXI11:THE P-BLOCK ELEMENTS

316677 A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.

1

{Br}_{2}, {KBrO}_{3}

2

{Cl}_{2}, {KClO}_{3}

3

I_{2}, {NaIO}_{3}

4

{Cl}_{2}, {NaClO}_{3}

Explanation:

${Cl}_{2}$ is greenish yellow gas and it reacts with $KOH$ to form ${KClO}_{3}$ which is used in fire works and safety matches.
$3 {Cl}_{2} + 6 KOH \to {KClO}_{3} + 5 KCl + 3 H_{2} O$

AIIMS - 2019

CHXI11:THE P-BLOCK ELEMENTS

316674 Which is not the correct statement?

1 The

S_{8}

ring is not planar

2 Oxygen is more electronegative than sulphur

3

{SF}_{4}

exists but

{OF}_{4}

does not exist

4

{SO}_{3}

and

{SO}_{3}^{2 -}

both have trigonal planar geometry

Explanation:

${SO}_{3}$ is trigonal planar due to ${sp}^{2}$ hybridised sulphur. ${SO}_{3}^{2 -}$ is ${sp}^{3}$ hybridised, but pyramidal due to presence of a lone pair of electrons.

AIIMS - 2011

CHXI11:THE P-BLOCK ELEMENTS

316675 Which one of the following is wrongly matched?

1

{C l O}_{3}^{-}, s p^{3}

, pyramidal

2

{C l O}_{4}^{-}, s p^{3}

, tetrahedral

3

{I C l}_{4}^{-}, s p^{3} d^{2}

, square planar

4

{I C l}_{2}^{-}, d s p^{2}

, trigonal bipyramidal

Explanation:

${I C l}_{2}^{-}, s p^{3} d$ , trigonal bipyramidal

CHXI11:THE P-BLOCK ELEMENTS

316676 On addition of conc. $H_{2} {SO}_{4}$ to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because

1

H_{2} {SO}_{4}

reduces

HI

to

I_{2}

2

HI

is of violet colour

3

HI

gets oxidised to

I_{2}

4

HI

changes to

{HIO}_{3}

CHXI11:THE P-BLOCK ELEMENTS

316677 A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.

1

{Br}_{2}, {KBrO}_{3}

2

{Cl}_{2}, {KClO}_{3}

3

I_{2}, {NaIO}_{3}

4

{Cl}_{2}, {NaClO}_{3}

Explanation:

${Cl}_{2}$ is greenish yellow gas and it reacts with $KOH$ to form ${KClO}_{3}$ which is used in fire works and safety matches.
$3 {Cl}_{2} + 6 KOH \to {KClO}_{3} + 5 KCl + 3 H_{2} O$

AIIMS - 2019

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