3 \(\mathrm{SF}_{4}\) exists but \(\mathrm{OF}_{4}\) does not exist
4 \(\mathrm{SO}_{3}\) and \(\mathrm{SO}_{3}^{2-}\) both have trigonal planar geometry
Explanation:
\(\mathrm{SO}_{3}\) is trigonal planar due to \(\mathrm{sp}^{2}\) hybridised sulphur. \(\mathrm{SO}_{3}^{2-}\) is \(\mathrm{sp}^{3}\) hybridised, but pyramidal due to presence of a lone pair of electrons.
AIIMS - 2011
CHXI11:THE P-BLOCK ELEMENTS
316675
Which one of the following is wrongly matched?
316676
On addition of conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
1 \(\mathrm{H}_{2} \mathrm{SO}_{4}\) reduces \(\mathrm{HI}\) to \(\mathrm{I}_{2}\)
2 \(\mathrm{HI}\) is of violet colour
3 \(\mathrm{HI}\) gets oxidised to \(\mathrm{I}_{2}\)
4 \(\mathrm{HI}\) changes to \(\mathrm{HIO}_{3}\)
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316677
A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.
1 \(\mathrm{Br}_{2}, \mathrm{KBrO}_{3}\)
2 \(\mathrm{Cl}_{2}, \mathrm{KClO}_{3}\)
3 \(\mathrm{I}_{2}, \mathrm{NaIO}_{3}\)
4 \(\mathrm{Cl}_{2}, \mathrm{NaClO}_{3}\)
Explanation:
\(\mathrm{Cl}_{2}\) is greenish yellow gas and it reacts with \(\mathrm{KOH}\) to form \(\mathrm{KClO}_{3}\) which is used in fire works and safety matches. \(3 \mathrm{Cl}_{2}+6 \mathrm{KOH} \rightarrow \mathrm{KClO}_{3}+5 \mathrm{KCl}+3 \mathrm{H}_{2} \mathrm{O}\)
3 \(\mathrm{SF}_{4}\) exists but \(\mathrm{OF}_{4}\) does not exist
4 \(\mathrm{SO}_{3}\) and \(\mathrm{SO}_{3}^{2-}\) both have trigonal planar geometry
Explanation:
\(\mathrm{SO}_{3}\) is trigonal planar due to \(\mathrm{sp}^{2}\) hybridised sulphur. \(\mathrm{SO}_{3}^{2-}\) is \(\mathrm{sp}^{3}\) hybridised, but pyramidal due to presence of a lone pair of electrons.
AIIMS - 2011
CHXI11:THE P-BLOCK ELEMENTS
316675
Which one of the following is wrongly matched?
316676
On addition of conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
1 \(\mathrm{H}_{2} \mathrm{SO}_{4}\) reduces \(\mathrm{HI}\) to \(\mathrm{I}_{2}\)
2 \(\mathrm{HI}\) is of violet colour
3 \(\mathrm{HI}\) gets oxidised to \(\mathrm{I}_{2}\)
4 \(\mathrm{HI}\) changes to \(\mathrm{HIO}_{3}\)
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316677
A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.
1 \(\mathrm{Br}_{2}, \mathrm{KBrO}_{3}\)
2 \(\mathrm{Cl}_{2}, \mathrm{KClO}_{3}\)
3 \(\mathrm{I}_{2}, \mathrm{NaIO}_{3}\)
4 \(\mathrm{Cl}_{2}, \mathrm{NaClO}_{3}\)
Explanation:
\(\mathrm{Cl}_{2}\) is greenish yellow gas and it reacts with \(\mathrm{KOH}\) to form \(\mathrm{KClO}_{3}\) which is used in fire works and safety matches. \(3 \mathrm{Cl}_{2}+6 \mathrm{KOH} \rightarrow \mathrm{KClO}_{3}+5 \mathrm{KCl}+3 \mathrm{H}_{2} \mathrm{O}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI11:THE P-BLOCK ELEMENTS
316674
Which is not the correct statement?
1 The \(\mathrm{S}_{8}\) ring is not planar
2 Oxygen is more electronegative than sulphur
3 \(\mathrm{SF}_{4}\) exists but \(\mathrm{OF}_{4}\) does not exist
4 \(\mathrm{SO}_{3}\) and \(\mathrm{SO}_{3}^{2-}\) both have trigonal planar geometry
Explanation:
\(\mathrm{SO}_{3}\) is trigonal planar due to \(\mathrm{sp}^{2}\) hybridised sulphur. \(\mathrm{SO}_{3}^{2-}\) is \(\mathrm{sp}^{3}\) hybridised, but pyramidal due to presence of a lone pair of electrons.
AIIMS - 2011
CHXI11:THE P-BLOCK ELEMENTS
316675
Which one of the following is wrongly matched?
316676
On addition of conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
1 \(\mathrm{H}_{2} \mathrm{SO}_{4}\) reduces \(\mathrm{HI}\) to \(\mathrm{I}_{2}\)
2 \(\mathrm{HI}\) is of violet colour
3 \(\mathrm{HI}\) gets oxidised to \(\mathrm{I}_{2}\)
4 \(\mathrm{HI}\) changes to \(\mathrm{HIO}_{3}\)
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316677
A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.
1 \(\mathrm{Br}_{2}, \mathrm{KBrO}_{3}\)
2 \(\mathrm{Cl}_{2}, \mathrm{KClO}_{3}\)
3 \(\mathrm{I}_{2}, \mathrm{NaIO}_{3}\)
4 \(\mathrm{Cl}_{2}, \mathrm{NaClO}_{3}\)
Explanation:
\(\mathrm{Cl}_{2}\) is greenish yellow gas and it reacts with \(\mathrm{KOH}\) to form \(\mathrm{KClO}_{3}\) which is used in fire works and safety matches. \(3 \mathrm{Cl}_{2}+6 \mathrm{KOH} \rightarrow \mathrm{KClO}_{3}+5 \mathrm{KCl}+3 \mathrm{H}_{2} \mathrm{O}\)
3 \(\mathrm{SF}_{4}\) exists but \(\mathrm{OF}_{4}\) does not exist
4 \(\mathrm{SO}_{3}\) and \(\mathrm{SO}_{3}^{2-}\) both have trigonal planar geometry
Explanation:
\(\mathrm{SO}_{3}\) is trigonal planar due to \(\mathrm{sp}^{2}\) hybridised sulphur. \(\mathrm{SO}_{3}^{2-}\) is \(\mathrm{sp}^{3}\) hybridised, but pyramidal due to presence of a lone pair of electrons.
AIIMS - 2011
CHXI11:THE P-BLOCK ELEMENTS
316675
Which one of the following is wrongly matched?
316676
On addition of conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
1 \(\mathrm{H}_{2} \mathrm{SO}_{4}\) reduces \(\mathrm{HI}\) to \(\mathrm{I}_{2}\)
2 \(\mathrm{HI}\) is of violet colour
3 \(\mathrm{HI}\) gets oxidised to \(\mathrm{I}_{2}\)
4 \(\mathrm{HI}\) changes to \(\mathrm{HIO}_{3}\)
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316677
A green yellow gas reacts with an alkali metal hydroxide to form a halate which can be used in fireworks and safety matches. The gas and halate are, respectively.
1 \(\mathrm{Br}_{2}, \mathrm{KBrO}_{3}\)
2 \(\mathrm{Cl}_{2}, \mathrm{KClO}_{3}\)
3 \(\mathrm{I}_{2}, \mathrm{NaIO}_{3}\)
4 \(\mathrm{Cl}_{2}, \mathrm{NaClO}_{3}\)
Explanation:
\(\mathrm{Cl}_{2}\) is greenish yellow gas and it reacts with \(\mathrm{KOH}\) to form \(\mathrm{KClO}_{3}\) which is used in fire works and safety matches. \(3 \mathrm{Cl}_{2}+6 \mathrm{KOH} \rightarrow \mathrm{KClO}_{3}+5 \mathrm{KCl}+3 \mathrm{H}_{2} \mathrm{O}\)