NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI11:THE P-BLOCK ELEMENTS
316572
The number of stable isotopes of oxygen is ____ .
1 1
2 2
3 3
4 4
Explanation:
Oxygen has three stable isotopes; \({\mathrm{{ }^{16} \mathrm{O},{ }^{17} \mathrm{O}}}\) and \({\mathrm{{ }^{18} \mathrm{O}}}\).
CHXI11:THE P-BLOCK ELEMENTS
316573
Assertion : Dinegative anion of oxygen \(\left(\mathrm{O}^{-2}\right)\) is quite common but dinegative anion of sulphur \(\left(\mathrm{S}^{2-}\right)\) is less common. Reason : Covalency of oxygen is two.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion \(\left(\mathrm{O}^{-2}\right)\), a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316574
The compounding not acting as a reducing agent is
1 \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)
2 \({\rm{Se}}{{\rm{O}}_{\rm{2}}}\)
3 \({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)
4 All of these
Explanation:
Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence \({\rm{T}}{{\rm{e}}^{{\rm{4 + }}}}\) is more stable than \({\rm{T}}{{\rm{e}}^{{\rm{6 + }}}}\). Hence\({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)will act as on oxidising agent and not as reducing agent.
CHXI11:THE P-BLOCK ELEMENTS
316575
The elements of group- 16 which show negative oxidation state are I. Oxygen II. Polonium III. Tellurium IV. Selenium Choose the correct option.
1 I, II and III
2 II,III and IV
3 I, III and IV
4 I, II, III and IV
Explanation:
Except polonium, all the other three, i.e., \(\mathrm{O}, \mathrm{Te}, \mathrm{Se}\), show negative oxidation state \((-2)\).
316572
The number of stable isotopes of oxygen is ____ .
1 1
2 2
3 3
4 4
Explanation:
Oxygen has three stable isotopes; \({\mathrm{{ }^{16} \mathrm{O},{ }^{17} \mathrm{O}}}\) and \({\mathrm{{ }^{18} \mathrm{O}}}\).
CHXI11:THE P-BLOCK ELEMENTS
316573
Assertion : Dinegative anion of oxygen \(\left(\mathrm{O}^{-2}\right)\) is quite common but dinegative anion of sulphur \(\left(\mathrm{S}^{2-}\right)\) is less common. Reason : Covalency of oxygen is two.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion \(\left(\mathrm{O}^{-2}\right)\), a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316574
The compounding not acting as a reducing agent is
1 \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)
2 \({\rm{Se}}{{\rm{O}}_{\rm{2}}}\)
3 \({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)
4 All of these
Explanation:
Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence \({\rm{T}}{{\rm{e}}^{{\rm{4 + }}}}\) is more stable than \({\rm{T}}{{\rm{e}}^{{\rm{6 + }}}}\). Hence\({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)will act as on oxidising agent and not as reducing agent.
CHXI11:THE P-BLOCK ELEMENTS
316575
The elements of group- 16 which show negative oxidation state are I. Oxygen II. Polonium III. Tellurium IV. Selenium Choose the correct option.
1 I, II and III
2 II,III and IV
3 I, III and IV
4 I, II, III and IV
Explanation:
Except polonium, all the other three, i.e., \(\mathrm{O}, \mathrm{Te}, \mathrm{Se}\), show negative oxidation state \((-2)\).
316572
The number of stable isotopes of oxygen is ____ .
1 1
2 2
3 3
4 4
Explanation:
Oxygen has three stable isotopes; \({\mathrm{{ }^{16} \mathrm{O},{ }^{17} \mathrm{O}}}\) and \({\mathrm{{ }^{18} \mathrm{O}}}\).
CHXI11:THE P-BLOCK ELEMENTS
316573
Assertion : Dinegative anion of oxygen \(\left(\mathrm{O}^{-2}\right)\) is quite common but dinegative anion of sulphur \(\left(\mathrm{S}^{2-}\right)\) is less common. Reason : Covalency of oxygen is two.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion \(\left(\mathrm{O}^{-2}\right)\), a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316574
The compounding not acting as a reducing agent is
1 \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)
2 \({\rm{Se}}{{\rm{O}}_{\rm{2}}}\)
3 \({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)
4 All of these
Explanation:
Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence \({\rm{T}}{{\rm{e}}^{{\rm{4 + }}}}\) is more stable than \({\rm{T}}{{\rm{e}}^{{\rm{6 + }}}}\). Hence\({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)will act as on oxidising agent and not as reducing agent.
CHXI11:THE P-BLOCK ELEMENTS
316575
The elements of group- 16 which show negative oxidation state are I. Oxygen II. Polonium III. Tellurium IV. Selenium Choose the correct option.
1 I, II and III
2 II,III and IV
3 I, III and IV
4 I, II, III and IV
Explanation:
Except polonium, all the other three, i.e., \(\mathrm{O}, \mathrm{Te}, \mathrm{Se}\), show negative oxidation state \((-2)\).
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXI11:THE P-BLOCK ELEMENTS
316572
The number of stable isotopes of oxygen is ____ .
1 1
2 2
3 3
4 4
Explanation:
Oxygen has three stable isotopes; \({\mathrm{{ }^{16} \mathrm{O},{ }^{17} \mathrm{O}}}\) and \({\mathrm{{ }^{18} \mathrm{O}}}\).
CHXI11:THE P-BLOCK ELEMENTS
316573
Assertion : Dinegative anion of oxygen \(\left(\mathrm{O}^{-2}\right)\) is quite common but dinegative anion of sulphur \(\left(\mathrm{S}^{2-}\right)\) is less common. Reason : Covalency of oxygen is two.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion \(\left(\mathrm{O}^{-2}\right)\), a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316574
The compounding not acting as a reducing agent is
1 \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)
2 \({\rm{Se}}{{\rm{O}}_{\rm{2}}}\)
3 \({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)
4 All of these
Explanation:
Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence \({\rm{T}}{{\rm{e}}^{{\rm{4 + }}}}\) is more stable than \({\rm{T}}{{\rm{e}}^{{\rm{6 + }}}}\). Hence\({\rm{Te}}{{\rm{O}}_{\rm{2}}}\)will act as on oxidising agent and not as reducing agent.
CHXI11:THE P-BLOCK ELEMENTS
316575
The elements of group- 16 which show negative oxidation state are I. Oxygen II. Polonium III. Tellurium IV. Selenium Choose the correct option.
1 I, II and III
2 II,III and IV
3 I, III and IV
4 I, II, III and IV
Explanation:
Except polonium, all the other three, i.e., \(\mathrm{O}, \mathrm{Te}, \mathrm{Se}\), show negative oxidation state \((-2)\).