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CHXI11:THE P-BLOCK ELEMENTS

316572 The number of stable isotopes of oxygen is ____ .

1 1

2 2

3 3

4 4

Explanation:

Oxygen has three stable isotopes; $^{16} O,^{17} O$ and $^{18} O$ .

CHXI11:THE P-BLOCK ELEMENTS

316573 Assertion :
Dinegative anion of oxygen $(O^{- 2})$ is quite common but dinegative anion of sulphur $(S^{2 -})$ is less common.
Reason :
Covalency of oxygen is two.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion $(O^{- 2})$ , a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316574 The compounding not acting as a reducing agent is

1

S O_{2}

2

S e O_{2}

3

T e O_{2}

4 All of these

Explanation:

Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence $T e^{4 +}$ is more stable than $T e^{6 +}$ . Hence $T e O_{2}$ will act as on oxidising agent and not as reducing agent.

CHXI11:THE P-BLOCK ELEMENTS

316575 The elements of group- 16 which show negative oxidation state are
I. Oxygen
II. Polonium
III. Tellurium
IV. Selenium
Choose the correct option.

1 I, II and III

2 II,III and IV

3 I, III and IV

4 I, II, III and IV

Explanation:

Except polonium, all the other three, i.e., $O, Te, Se$ , show negative oxidation state $(- 2)$ .

CHXI11:THE P-BLOCK ELEMENTS

316572 The number of stable isotopes of oxygen is ____ .

1 1

2 2

3 3

4 4

Explanation:

Oxygen has three stable isotopes; $^{16} O,^{17} O$ and $^{18} O$ .

CHXI11:THE P-BLOCK ELEMENTS

316573 Assertion :
Dinegative anion of oxygen $(O^{- 2})$ is quite common but dinegative anion of sulphur $(S^{2 -})$ is less common.
Reason :
Covalency of oxygen is two.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion $(O^{- 2})$ , a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316574 The compounding not acting as a reducing agent is

1

S O_{2}

2

S e O_{2}

3

T e O_{2}

4 All of these

Explanation:

Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence $T e^{4 +}$ is more stable than $T e^{6 +}$ . Hence $T e O_{2}$ will act as on oxidising agent and not as reducing agent.

CHXI11:THE P-BLOCK ELEMENTS

316575 The elements of group- 16 which show negative oxidation state are
I. Oxygen
II. Polonium
III. Tellurium
IV. Selenium
Choose the correct option.

1 I, II and III

2 II,III and IV

3 I, III and IV

4 I, II, III and IV

Explanation:

Except polonium, all the other three, i.e., $O, Te, Se$ , show negative oxidation state $(- 2)$ .

CHXI11:THE P-BLOCK ELEMENTS

316572 The number of stable isotopes of oxygen is ____ .

1 1

2 2

3 3

4 4

Explanation:

Oxygen has three stable isotopes; $^{16} O,^{17} O$ and $^{18} O$ .

CHXI11:THE P-BLOCK ELEMENTS

316573 Assertion :
Dinegative anion of oxygen $(O^{- 2})$ is quite common but dinegative anion of sulphur $(S^{2 -})$ is less common.
Reason :
Covalency of oxygen is two.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion $(O^{- 2})$ , a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316574 The compounding not acting as a reducing agent is

1

S O_{2}

2

S e O_{2}

3

T e O_{2}

4 All of these

Explanation:

Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence $T e^{4 +}$ is more stable than $T e^{6 +}$ . Hence $T e O_{2}$ will act as on oxidising agent and not as reducing agent.

CHXI11:THE P-BLOCK ELEMENTS

316575 The elements of group- 16 which show negative oxidation state are
I. Oxygen
II. Polonium
III. Tellurium
IV. Selenium
Choose the correct option.

1 I, II and III

2 II,III and IV

3 I, III and IV

4 I, II, III and IV

Explanation:

Except polonium, all the other three, i.e., $O, Te, Se$ , show negative oxidation state $(- 2)$ .

CHXI11:THE P-BLOCK ELEMENTS

316572 The number of stable isotopes of oxygen is ____ .

1 1

2 2

3 3

4 4

Explanation:

Oxygen has three stable isotopes; $^{16} O,^{17} O$ and $^{18} O$ .

CHXI11:THE P-BLOCK ELEMENTS

316573 Assertion :
Dinegative anion of oxygen $(O^{- 2})$ is quite common but dinegative anion of sulphur $(S^{2 -})$ is less common.
Reason :
Covalency of oxygen is two.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Oxygen ranks as the second most electronegative element, following fluorine. This characteristic allows oxygen to readily acquire electrons and form a doubly negative anion $(O^{- 2})$ , a trait not as prominent in sulfur, which is less electronegative compared to oxygen. Covalency of oxygen is 2 . So option (2) is correct.

CHXI11:THE P-BLOCK ELEMENTS

316574 The compounding not acting as a reducing agent is

1

S O_{2}

2

S e O_{2}

3

T e O_{2}

4 All of these

Explanation:

Group 16 elements are O,S,Se,Te.Due to inert pair of effect stability of +4,+6 oxidation state decreases on moving down the group.Hence $T e^{4 +}$ is more stable than $T e^{6 +}$ . Hence $T e O_{2}$ will act as on oxidising agent and not as reducing agent.

CHXI11:THE P-BLOCK ELEMENTS

316575 The elements of group- 16 which show negative oxidation state are
I. Oxygen
II. Polonium
III. Tellurium
IV. Selenium
Choose the correct option.

1 I, II and III

2 II,III and IV

3 I, III and IV

4 I, II, III and IV

Explanation:

Except polonium, all the other three, i.e., $O, Te, Se$ , show negative oxidation state $(- 2)$ .

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