CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317449
Assertion : The stability of carbonium ion is influenced by both resonance and inductive effect. Reason : More the number of alkyl groups, greater the dispersal of positive charge and more is the stability of carbonium ion observed.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The stability of carbonium ions is influenced by both resonance and inductive effects. The reason is also true, as more alkyl groups lead to greater dispersal of positive charge, enhancing the stability of the carbonium ion. So, the option (1) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317450
The decreasing order of hydride affinity for following carbocations is
Choose the correct answer from the options given below:
1 A, C, B, D
2 C, A, D, B
3 A, C, D, B
4 C, A, B, D
Explanation:
The correct hydride affinity order of the carbocations will be decided by the stability of the carbocation. Higher the stability of carbocation, lower will be hydride affinity. The stability order of carbocations is, \(\mathrm{C} < \mathrm{A} < \mathrm{B} < \mathrm{D}\). Thus, the decreasing order of hydride affinity is \(\mathrm{C}>\mathrm{A}>\mathrm{B}>\mathrm{D}\).
JEE - 2023
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317451
Carbocaton as an intermediate is likely to be formed in the reaction:
Carbocation intermediate is formed in the reaction Hexane \(\xrightarrow{{{\text{anhy AlC}}{{\text{l}}_{\text{3}}}{\text{/HCl}}}}\) 2-methyl pentane Hexane on reaction with anhy. \(\mathrm{AlCl}_{3}\) undergoes rearrangement reaction forming a secondary carbocation which ultimately forms 2-methyl pentane.
KCET - 2014
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317452
The various carbocations that can be obtained from 2-methylbutane given as
The correct order of increasing stability of these carbocations is
1 II \( < \) III \( < \) I \( < \) IV
2 IV \( < \) I \( < \) II \( < \) III
3 III \( < \) II \( < \) I \( < \) IV
4 I \( < \) III \( < \) II \( < \) IV
Explanation:
Order of increasing stability : IV \( < \) I \( < \) II \( < \) III. The stability order of carbocations in general is \(1^{o} < 2^{o} < 3^{o}\).
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CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317449
Assertion : The stability of carbonium ion is influenced by both resonance and inductive effect. Reason : More the number of alkyl groups, greater the dispersal of positive charge and more is the stability of carbonium ion observed.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The stability of carbonium ions is influenced by both resonance and inductive effects. The reason is also true, as more alkyl groups lead to greater dispersal of positive charge, enhancing the stability of the carbonium ion. So, the option (1) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317450
The decreasing order of hydride affinity for following carbocations is
Choose the correct answer from the options given below:
1 A, C, B, D
2 C, A, D, B
3 A, C, D, B
4 C, A, B, D
Explanation:
The correct hydride affinity order of the carbocations will be decided by the stability of the carbocation. Higher the stability of carbocation, lower will be hydride affinity. The stability order of carbocations is, \(\mathrm{C} < \mathrm{A} < \mathrm{B} < \mathrm{D}\). Thus, the decreasing order of hydride affinity is \(\mathrm{C}>\mathrm{A}>\mathrm{B}>\mathrm{D}\).
JEE - 2023
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317451
Carbocaton as an intermediate is likely to be formed in the reaction:
Carbocation intermediate is formed in the reaction Hexane \(\xrightarrow{{{\text{anhy AlC}}{{\text{l}}_{\text{3}}}{\text{/HCl}}}}\) 2-methyl pentane Hexane on reaction with anhy. \(\mathrm{AlCl}_{3}\) undergoes rearrangement reaction forming a secondary carbocation which ultimately forms 2-methyl pentane.
KCET - 2014
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317452
The various carbocations that can be obtained from 2-methylbutane given as
The correct order of increasing stability of these carbocations is
1 II \( < \) III \( < \) I \( < \) IV
2 IV \( < \) I \( < \) II \( < \) III
3 III \( < \) II \( < \) I \( < \) IV
4 I \( < \) III \( < \) II \( < \) IV
Explanation:
Order of increasing stability : IV \( < \) I \( < \) II \( < \) III. The stability order of carbocations in general is \(1^{o} < 2^{o} < 3^{o}\).
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317449
Assertion : The stability of carbonium ion is influenced by both resonance and inductive effect. Reason : More the number of alkyl groups, greater the dispersal of positive charge and more is the stability of carbonium ion observed.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The stability of carbonium ions is influenced by both resonance and inductive effects. The reason is also true, as more alkyl groups lead to greater dispersal of positive charge, enhancing the stability of the carbonium ion. So, the option (1) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317450
The decreasing order of hydride affinity for following carbocations is
Choose the correct answer from the options given below:
1 A, C, B, D
2 C, A, D, B
3 A, C, D, B
4 C, A, B, D
Explanation:
The correct hydride affinity order of the carbocations will be decided by the stability of the carbocation. Higher the stability of carbocation, lower will be hydride affinity. The stability order of carbocations is, \(\mathrm{C} < \mathrm{A} < \mathrm{B} < \mathrm{D}\). Thus, the decreasing order of hydride affinity is \(\mathrm{C}>\mathrm{A}>\mathrm{B}>\mathrm{D}\).
JEE - 2023
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317451
Carbocaton as an intermediate is likely to be formed in the reaction:
Carbocation intermediate is formed in the reaction Hexane \(\xrightarrow{{{\text{anhy AlC}}{{\text{l}}_{\text{3}}}{\text{/HCl}}}}\) 2-methyl pentane Hexane on reaction with anhy. \(\mathrm{AlCl}_{3}\) undergoes rearrangement reaction forming a secondary carbocation which ultimately forms 2-methyl pentane.
KCET - 2014
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317452
The various carbocations that can be obtained from 2-methylbutane given as
The correct order of increasing stability of these carbocations is
1 II \( < \) III \( < \) I \( < \) IV
2 IV \( < \) I \( < \) II \( < \) III
3 III \( < \) II \( < \) I \( < \) IV
4 I \( < \) III \( < \) II \( < \) IV
Explanation:
Order of increasing stability : IV \( < \) I \( < \) II \( < \) III. The stability order of carbocations in general is \(1^{o} < 2^{o} < 3^{o}\).
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317449
Assertion : The stability of carbonium ion is influenced by both resonance and inductive effect. Reason : More the number of alkyl groups, greater the dispersal of positive charge and more is the stability of carbonium ion observed.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The stability of carbonium ions is influenced by both resonance and inductive effects. The reason is also true, as more alkyl groups lead to greater dispersal of positive charge, enhancing the stability of the carbonium ion. So, the option (1) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317450
The decreasing order of hydride affinity for following carbocations is
Choose the correct answer from the options given below:
1 A, C, B, D
2 C, A, D, B
3 A, C, D, B
4 C, A, B, D
Explanation:
The correct hydride affinity order of the carbocations will be decided by the stability of the carbocation. Higher the stability of carbocation, lower will be hydride affinity. The stability order of carbocations is, \(\mathrm{C} < \mathrm{A} < \mathrm{B} < \mathrm{D}\). Thus, the decreasing order of hydride affinity is \(\mathrm{C}>\mathrm{A}>\mathrm{B}>\mathrm{D}\).
JEE - 2023
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317451
Carbocaton as an intermediate is likely to be formed in the reaction:
Carbocation intermediate is formed in the reaction Hexane \(\xrightarrow{{{\text{anhy AlC}}{{\text{l}}_{\text{3}}}{\text{/HCl}}}}\) 2-methyl pentane Hexane on reaction with anhy. \(\mathrm{AlCl}_{3}\) undergoes rearrangement reaction forming a secondary carbocation which ultimately forms 2-methyl pentane.
KCET - 2014
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317452
The various carbocations that can be obtained from 2-methylbutane given as
The correct order of increasing stability of these carbocations is
1 II \( < \) III \( < \) I \( < \) IV
2 IV \( < \) I \( < \) II \( < \) III
3 III \( < \) II \( < \) I \( < \) IV
4 I \( < \) III \( < \) II \( < \) IV
Explanation:
Order of increasing stability : IV \( < \) I \( < \) II \( < \) III. The stability order of carbocations in general is \(1^{o} < 2^{o} < 3^{o}\).
