As the s-character or number of \(\pi\) - electrons increases, bond length decreases. Therefore, \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}{\rm{B}}{{\rm{r}}_{\rm{2}}}\) due to the absence of \({\rm{\pi - electrons}}\)or dueto the presence of lesser s-character (25%),has the longest \({\rm{\pi - electrons}}\)bond distance.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317280
The correct stability order of the following resonance structures of \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{CH}} = {\rm{CH}} - {\rm{CHO}}\) is
1 II \({\mathrm{>}}\) III \({\mathrm{>}}\) I
2 I \({\mathrm{>}}\) II \({\mathrm{>}}\) III
3 II \({\mathrm{>}}\) I \({\mathrm{>}}\) III
4 III \({\mathrm{>}}\) II \({\mathrm{>}}\) I
Explanation:
The correct order of stability of given resonating III \({\mathrm{>}}\) II \({\mathrm{>}}\) I III is most stable as it does not have any separation of charges. II is more stable than I as in II negative charge is on more electronegative oxygen atom and positive charge is on less electronegative carbon atom. So, the correct option is (4).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317281
The correct stability order of following species is
1 \({\rm{x > y > w > z}}\)
2 \({\rm{y > x > w > z}}\)
3 \({\rm{x > w > z > y}}\)
4 \({\rm{z > x > y > w}}\)
Explanation:
\({\rm{x}}\) is a conjugated diene system, \({\rm{w}}\) is an isolated diene system, \(\mathrm{z}\) is a cumulated diene system, y is antiaromatic system. Hence, stability order is \(\mathrm{x}>\mathrm{w}>\mathrm{z}>\mathrm{y}\).
As the s-character or number of \(\pi\) - electrons increases, bond length decreases. Therefore, \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}{\rm{B}}{{\rm{r}}_{\rm{2}}}\) due to the absence of \({\rm{\pi - electrons}}\)or dueto the presence of lesser s-character (25%),has the longest \({\rm{\pi - electrons}}\)bond distance.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317280
The correct stability order of the following resonance structures of \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{CH}} = {\rm{CH}} - {\rm{CHO}}\) is
1 II \({\mathrm{>}}\) III \({\mathrm{>}}\) I
2 I \({\mathrm{>}}\) II \({\mathrm{>}}\) III
3 II \({\mathrm{>}}\) I \({\mathrm{>}}\) III
4 III \({\mathrm{>}}\) II \({\mathrm{>}}\) I
Explanation:
The correct order of stability of given resonating III \({\mathrm{>}}\) II \({\mathrm{>}}\) I III is most stable as it does not have any separation of charges. II is more stable than I as in II negative charge is on more electronegative oxygen atom and positive charge is on less electronegative carbon atom. So, the correct option is (4).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317281
The correct stability order of following species is
1 \({\rm{x > y > w > z}}\)
2 \({\rm{y > x > w > z}}\)
3 \({\rm{x > w > z > y}}\)
4 \({\rm{z > x > y > w}}\)
Explanation:
\({\rm{x}}\) is a conjugated diene system, \({\rm{w}}\) is an isolated diene system, \(\mathrm{z}\) is a cumulated diene system, y is antiaromatic system. Hence, stability order is \(\mathrm{x}>\mathrm{w}>\mathrm{z}>\mathrm{y}\).
As the s-character or number of \(\pi\) - electrons increases, bond length decreases. Therefore, \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}{\rm{B}}{{\rm{r}}_{\rm{2}}}\) due to the absence of \({\rm{\pi - electrons}}\)or dueto the presence of lesser s-character (25%),has the longest \({\rm{\pi - electrons}}\)bond distance.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317280
The correct stability order of the following resonance structures of \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{CH}} = {\rm{CH}} - {\rm{CHO}}\) is
1 II \({\mathrm{>}}\) III \({\mathrm{>}}\) I
2 I \({\mathrm{>}}\) II \({\mathrm{>}}\) III
3 II \({\mathrm{>}}\) I \({\mathrm{>}}\) III
4 III \({\mathrm{>}}\) II \({\mathrm{>}}\) I
Explanation:
The correct order of stability of given resonating III \({\mathrm{>}}\) II \({\mathrm{>}}\) I III is most stable as it does not have any separation of charges. II is more stable than I as in II negative charge is on more electronegative oxygen atom and positive charge is on less electronegative carbon atom. So, the correct option is (4).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317281
The correct stability order of following species is
1 \({\rm{x > y > w > z}}\)
2 \({\rm{y > x > w > z}}\)
3 \({\rm{x > w > z > y}}\)
4 \({\rm{z > x > y > w}}\)
Explanation:
\({\rm{x}}\) is a conjugated diene system, \({\rm{w}}\) is an isolated diene system, \(\mathrm{z}\) is a cumulated diene system, y is antiaromatic system. Hence, stability order is \(\mathrm{x}>\mathrm{w}>\mathrm{z}>\mathrm{y}\).
As the s-character or number of \(\pi\) - electrons increases, bond length decreases. Therefore, \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}{\rm{B}}{{\rm{r}}_{\rm{2}}}\) due to the absence of \({\rm{\pi - electrons}}\)or dueto the presence of lesser s-character (25%),has the longest \({\rm{\pi - electrons}}\)bond distance.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317280
The correct stability order of the following resonance structures of \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{CH}} = {\rm{CH}} - {\rm{CHO}}\) is
1 II \({\mathrm{>}}\) III \({\mathrm{>}}\) I
2 I \({\mathrm{>}}\) II \({\mathrm{>}}\) III
3 II \({\mathrm{>}}\) I \({\mathrm{>}}\) III
4 III \({\mathrm{>}}\) II \({\mathrm{>}}\) I
Explanation:
The correct order of stability of given resonating III \({\mathrm{>}}\) II \({\mathrm{>}}\) I III is most stable as it does not have any separation of charges. II is more stable than I as in II negative charge is on more electronegative oxygen atom and positive charge is on less electronegative carbon atom. So, the correct option is (4).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317281
The correct stability order of following species is
1 \({\rm{x > y > w > z}}\)
2 \({\rm{y > x > w > z}}\)
3 \({\rm{x > w > z > y}}\)
4 \({\rm{z > x > y > w}}\)
Explanation:
\({\rm{x}}\) is a conjugated diene system, \({\rm{w}}\) is an isolated diene system, \(\mathrm{z}\) is a cumulated diene system, y is antiaromatic system. Hence, stability order is \(\mathrm{x}>\mathrm{w}>\mathrm{z}>\mathrm{y}\).
