315244
The difference in oxidation state of \(\mathrm{Cl}\) in \(\mathrm{CaOCl}_{2}\) (bleaching powder) is ____.
1 0
2 2
3 3
4 \(-\)1
Explanation:
CHXI08:REDOX REACTIONS
315245
Assertion : Oxidation number of carbon in \(\mathrm{CH}_{2} \mathrm{O}\) is zero. Reason : \(\mathrm{CH}_{2} \mathrm{O}\) (formaldehyde) is a covalent compound.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxidation numbers are determined by specific rules. Hydrogen \((\mathrm{H})\) is assigned an oxidation state of \((+ 1)\) , and oxygen \((\mathrm{O})\) of \((- 2)\) . Let the oxidation number of carbon \((\mathrm{C})\) in \(\mathrm{CH}_{2} \mathrm{O}\) be \(\mathrm{x}\). Then \(\mathrm{x}+2(+1)+(-2)=0\) \(\mathrm{x}=0\) So, in this compound, carbon \((\mathrm{C})\) has an oxidation number of \(0 . \mathrm{CH}_{2} \mathrm{O}\) is a covalent compound. So the option (2) is correct.
CHXI08:REDOX REACTIONS
315246
Atomic number of an element is 22 . The highest O.S. exhibited by it in its compounds is
1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ + 3}}\)
4 \({\rm{ + 4}}\)
Explanation:
The element is Ti (At. no. 22). Electronic configuration is \(\mathrm{1 s^{2}, 2 s^{2} p^{6}, 3 s^{2} p^{6} d^{2}, 4 s^{2}}\). The energy level of \(\mathrm{3 \mathrm{~d}}\) and \(\mathrm{4 \mathrm{~s}}\) is very close. It can have \(\mathrm{\mathrm{Ti}^{4+}}\) O.S.
CHXI08:REDOX REACTIONS
315247
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
1 An element in the free or the uncombined state bears oxidation number zero.
2 The oxidation number of hydrogen is always \(\mathrm{+1}\)
3 The algebraic sum of all the oxidation numbers in a compound is zero.
4 In all its compounds, the oxidation number of fluorine is \({\rm{ - 1}}\) .
315244
The difference in oxidation state of \(\mathrm{Cl}\) in \(\mathrm{CaOCl}_{2}\) (bleaching powder) is ____.
1 0
2 2
3 3
4 \(-\)1
Explanation:
CHXI08:REDOX REACTIONS
315245
Assertion : Oxidation number of carbon in \(\mathrm{CH}_{2} \mathrm{O}\) is zero. Reason : \(\mathrm{CH}_{2} \mathrm{O}\) (formaldehyde) is a covalent compound.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxidation numbers are determined by specific rules. Hydrogen \((\mathrm{H})\) is assigned an oxidation state of \((+ 1)\) , and oxygen \((\mathrm{O})\) of \((- 2)\) . Let the oxidation number of carbon \((\mathrm{C})\) in \(\mathrm{CH}_{2} \mathrm{O}\) be \(\mathrm{x}\). Then \(\mathrm{x}+2(+1)+(-2)=0\) \(\mathrm{x}=0\) So, in this compound, carbon \((\mathrm{C})\) has an oxidation number of \(0 . \mathrm{CH}_{2} \mathrm{O}\) is a covalent compound. So the option (2) is correct.
CHXI08:REDOX REACTIONS
315246
Atomic number of an element is 22 . The highest O.S. exhibited by it in its compounds is
1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ + 3}}\)
4 \({\rm{ + 4}}\)
Explanation:
The element is Ti (At. no. 22). Electronic configuration is \(\mathrm{1 s^{2}, 2 s^{2} p^{6}, 3 s^{2} p^{6} d^{2}, 4 s^{2}}\). The energy level of \(\mathrm{3 \mathrm{~d}}\) and \(\mathrm{4 \mathrm{~s}}\) is very close. It can have \(\mathrm{\mathrm{Ti}^{4+}}\) O.S.
CHXI08:REDOX REACTIONS
315247
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
1 An element in the free or the uncombined state bears oxidation number zero.
2 The oxidation number of hydrogen is always \(\mathrm{+1}\)
3 The algebraic sum of all the oxidation numbers in a compound is zero.
4 In all its compounds, the oxidation number of fluorine is \({\rm{ - 1}}\) .
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI08:REDOX REACTIONS
315244
The difference in oxidation state of \(\mathrm{Cl}\) in \(\mathrm{CaOCl}_{2}\) (bleaching powder) is ____.
1 0
2 2
3 3
4 \(-\)1
Explanation:
CHXI08:REDOX REACTIONS
315245
Assertion : Oxidation number of carbon in \(\mathrm{CH}_{2} \mathrm{O}\) is zero. Reason : \(\mathrm{CH}_{2} \mathrm{O}\) (formaldehyde) is a covalent compound.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxidation numbers are determined by specific rules. Hydrogen \((\mathrm{H})\) is assigned an oxidation state of \((+ 1)\) , and oxygen \((\mathrm{O})\) of \((- 2)\) . Let the oxidation number of carbon \((\mathrm{C})\) in \(\mathrm{CH}_{2} \mathrm{O}\) be \(\mathrm{x}\). Then \(\mathrm{x}+2(+1)+(-2)=0\) \(\mathrm{x}=0\) So, in this compound, carbon \((\mathrm{C})\) has an oxidation number of \(0 . \mathrm{CH}_{2} \mathrm{O}\) is a covalent compound. So the option (2) is correct.
CHXI08:REDOX REACTIONS
315246
Atomic number of an element is 22 . The highest O.S. exhibited by it in its compounds is
1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ + 3}}\)
4 \({\rm{ + 4}}\)
Explanation:
The element is Ti (At. no. 22). Electronic configuration is \(\mathrm{1 s^{2}, 2 s^{2} p^{6}, 3 s^{2} p^{6} d^{2}, 4 s^{2}}\). The energy level of \(\mathrm{3 \mathrm{~d}}\) and \(\mathrm{4 \mathrm{~s}}\) is very close. It can have \(\mathrm{\mathrm{Ti}^{4+}}\) O.S.
CHXI08:REDOX REACTIONS
315247
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
1 An element in the free or the uncombined state bears oxidation number zero.
2 The oxidation number of hydrogen is always \(\mathrm{+1}\)
3 The algebraic sum of all the oxidation numbers in a compound is zero.
4 In all its compounds, the oxidation number of fluorine is \({\rm{ - 1}}\) .
315244
The difference in oxidation state of \(\mathrm{Cl}\) in \(\mathrm{CaOCl}_{2}\) (bleaching powder) is ____.
1 0
2 2
3 3
4 \(-\)1
Explanation:
CHXI08:REDOX REACTIONS
315245
Assertion : Oxidation number of carbon in \(\mathrm{CH}_{2} \mathrm{O}\) is zero. Reason : \(\mathrm{CH}_{2} \mathrm{O}\) (formaldehyde) is a covalent compound.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Oxidation numbers are determined by specific rules. Hydrogen \((\mathrm{H})\) is assigned an oxidation state of \((+ 1)\) , and oxygen \((\mathrm{O})\) of \((- 2)\) . Let the oxidation number of carbon \((\mathrm{C})\) in \(\mathrm{CH}_{2} \mathrm{O}\) be \(\mathrm{x}\). Then \(\mathrm{x}+2(+1)+(-2)=0\) \(\mathrm{x}=0\) So, in this compound, carbon \((\mathrm{C})\) has an oxidation number of \(0 . \mathrm{CH}_{2} \mathrm{O}\) is a covalent compound. So the option (2) is correct.
CHXI08:REDOX REACTIONS
315246
Atomic number of an element is 22 . The highest O.S. exhibited by it in its compounds is
1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ + 3}}\)
4 \({\rm{ + 4}}\)
Explanation:
The element is Ti (At. no. 22). Electronic configuration is \(\mathrm{1 s^{2}, 2 s^{2} p^{6}, 3 s^{2} p^{6} d^{2}, 4 s^{2}}\). The energy level of \(\mathrm{3 \mathrm{~d}}\) and \(\mathrm{4 \mathrm{~s}}\) is very close. It can have \(\mathrm{\mathrm{Ti}^{4+}}\) O.S.
CHXI08:REDOX REACTIONS
315247
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
1 An element in the free or the uncombined state bears oxidation number zero.
2 The oxidation number of hydrogen is always \(\mathrm{+1}\)
3 The algebraic sum of all the oxidation numbers in a compound is zero.
4 In all its compounds, the oxidation number of fluorine is \({\rm{ - 1}}\) .
