315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -