Calculation of x-factor or Valency Factor and Equivalent Weight
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CHXI08:REDOX REACTIONS

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

1 12
2 24
3 6
4 48
CHXI08:REDOX REACTIONS

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

1 \(\mathrm{\left(\dfrac{2 x_{1}-x_{2}}{6}\right)}\)
2 \(\mathrm{\left(x_{1}-x_{2}\right)}\)
3 \(\mathrm{\left(3 x_{1}-x_{2}\right)}\)
4 \(\mathrm{\left(x_{1}-3 x_{2}\right)}\)
CHXI08:REDOX REACTIONS

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

1 16
2 24
3 8
4 12
CHXI08:REDOX REACTIONS

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

1 +4 to +2
2 +5 to +3
3 +6 to +3
4 +7 to +1
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CHXI08:REDOX REACTIONS

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

1 12
2 24
3 6
4 48
CHXI08:REDOX REACTIONS

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

1 \(\mathrm{\left(\dfrac{2 x_{1}-x_{2}}{6}\right)}\)
2 \(\mathrm{\left(x_{1}-x_{2}\right)}\)
3 \(\mathrm{\left(3 x_{1}-x_{2}\right)}\)
4 \(\mathrm{\left(x_{1}-3 x_{2}\right)}\)
CHXI08:REDOX REACTIONS

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

1 16
2 24
3 8
4 12
CHXI08:REDOX REACTIONS

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

1 +4 to +2
2 +5 to +3
3 +6 to +3
4 +7 to +1
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CHXI08:REDOX REACTIONS

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

1 12
2 24
3 6
4 48
CHXI08:REDOX REACTIONS

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

1 \(\mathrm{\left(\dfrac{2 x_{1}-x_{2}}{6}\right)}\)
2 \(\mathrm{\left(x_{1}-x_{2}\right)}\)
3 \(\mathrm{\left(3 x_{1}-x_{2}\right)}\)
4 \(\mathrm{\left(x_{1}-3 x_{2}\right)}\)
CHXI08:REDOX REACTIONS

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

1 16
2 24
3 8
4 12
CHXI08:REDOX REACTIONS

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

1 +4 to +2
2 +5 to +3
3 +6 to +3
4 +7 to +1
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CHXI08:REDOX REACTIONS

315128 The molar mass of a metallic oxide \(\mathrm{\mathrm{MO}}\) is 40 . The equivalent mass of the element will be

1 12
2 24
3 6
4 48
CHXI08:REDOX REACTIONS

315129 \(\mathrm{\mathrm{N}_{2}+3 \mathrm{H}_{2} \longrightarrow 2 \mathrm{NH}_{3}}\)
Molecular weight of \(\mathrm{\mathrm{NH}_{3}}\) and \(\mathrm{\mathrm{N}_{2}}\) are \(\mathrm{\mathrm{x}_{1}}\) and \(\mathrm{\mathrm{x}_{2}}\), their equivalent weight are \(\mathrm{y_{1}}\) and \(\mathrm{y_{2}}\). Then \(\mathrm{\left(y_{1}-y_{2}\right)}\) is

1 \(\mathrm{\left(\dfrac{2 x_{1}-x_{2}}{6}\right)}\)
2 \(\mathrm{\left(x_{1}-x_{2}\right)}\)
3 \(\mathrm{\left(3 x_{1}-x_{2}\right)}\)
4 \(\mathrm{\left(x_{1}-3 x_{2}\right)}\)
CHXI08:REDOX REACTIONS

315130 In the reaction \(\mathrm{\mathrm{Al}+\mathrm{Fe}_{3} \mathrm{O}_{4} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe}}\) what is the total no. of electrons transferred during the change?

1 16
2 24
3 8
4 12
CHXI08:REDOX REACTIONS

315131 When \(\mathrm{\mathrm{SO}_{2}}\) is passed through acidified \(\mathrm{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}\) solution, \(\mathrm{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}\) is formed. The change in oxidation state of \(\mathrm{\mathrm{Cr}}\) is -

1 +4 to +2
2 +5 to +3
3 +6 to +3
4 +7 to +1