314460 In the reaction \({\text{Fe(OH}}{{\text{)}}_{\text{2}}}_{{\text{(S)}}} \rightleftharpoons {\text{Fe}}_{{\text{(aq)}}}^{{\text{3 + }}}{\text{ + 3OH}}_{{\text{(aq)}}}^{{\text{ - }}}\)
If the concentration of \(\mathrm{OH}^{-}\)ions is decreased by \(1 / 4\) times, then the equilibrium concentration of \(\mathrm{Fe}^{3+}\) will increase by

314461 If the mixture of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) mixture in a closed apparatus is \(100 \mathrm{~atm}\) and \(20 \%\) of the mixture then reacts, the pressure at the same temperature will be

314462 A mixture of 2 moles of \(\mathrm{N}_{2}\) and 8 moles of \(\mathrm{H}_{2}\) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of \(\mathrm{N}_{2}\) was present. The equilibrium concentration of \(\mathrm{H}_{2}\) will be

314463 An amount of solid \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{~S}\) gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm . The equilibrium constant for \(\mathrm{NH}_{4} \mathrm{HS}\) decomposition at this temperature is

314464 Formaldehyde polymerises to form glucose according to the reaction, \(6 \mathrm{HCHO} \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). The theoretically computed equilibrium constant for this reaction is found to be \(6 \times 10^{22}\). If \(1 \mathrm{M}\) solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

314460 In the reaction \({\text{Fe(OH}}{{\text{)}}_{\text{2}}}_{{\text{(S)}}} \rightleftharpoons {\text{Fe}}_{{\text{(aq)}}}^{{\text{3 + }}}{\text{ + 3OH}}_{{\text{(aq)}}}^{{\text{ - }}}\)
If the concentration of \(\mathrm{OH}^{-}\)ions is decreased by \(1 / 4\) times, then the equilibrium concentration of \(\mathrm{Fe}^{3+}\) will increase by

314461 If the mixture of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) mixture in a closed apparatus is \(100 \mathrm{~atm}\) and \(20 \%\) of the mixture then reacts, the pressure at the same temperature will be

314462 A mixture of 2 moles of \(\mathrm{N}_{2}\) and 8 moles of \(\mathrm{H}_{2}\) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of \(\mathrm{N}_{2}\) was present. The equilibrium concentration of \(\mathrm{H}_{2}\) will be

314463 An amount of solid \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{~S}\) gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm . The equilibrium constant for \(\mathrm{NH}_{4} \mathrm{HS}\) decomposition at this temperature is

314464 Formaldehyde polymerises to form glucose according to the reaction, \(6 \mathrm{HCHO} \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). The theoretically computed equilibrium constant for this reaction is found to be \(6 \times 10^{22}\). If \(1 \mathrm{M}\) solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

314460 In the reaction \({\text{Fe(OH}}{{\text{)}}_{\text{2}}}_{{\text{(S)}}} \rightleftharpoons {\text{Fe}}_{{\text{(aq)}}}^{{\text{3 + }}}{\text{ + 3OH}}_{{\text{(aq)}}}^{{\text{ - }}}\)
If the concentration of \(\mathrm{OH}^{-}\)ions is decreased by \(1 / 4\) times, then the equilibrium concentration of \(\mathrm{Fe}^{3+}\) will increase by

314461 If the mixture of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) mixture in a closed apparatus is \(100 \mathrm{~atm}\) and \(20 \%\) of the mixture then reacts, the pressure at the same temperature will be

314462 A mixture of 2 moles of \(\mathrm{N}_{2}\) and 8 moles of \(\mathrm{H}_{2}\) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of \(\mathrm{N}_{2}\) was present. The equilibrium concentration of \(\mathrm{H}_{2}\) will be

314463 An amount of solid \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{~S}\) gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm . The equilibrium constant for \(\mathrm{NH}_{4} \mathrm{HS}\) decomposition at this temperature is

314464 Formaldehyde polymerises to form glucose according to the reaction, \(6 \mathrm{HCHO} \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). The theoretically computed equilibrium constant for this reaction is found to be \(6 \times 10^{22}\). If \(1 \mathrm{M}\) solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

314460 In the reaction \({\text{Fe(OH}}{{\text{)}}_{\text{2}}}_{{\text{(S)}}} \rightleftharpoons {\text{Fe}}_{{\text{(aq)}}}^{{\text{3 + }}}{\text{ + 3OH}}_{{\text{(aq)}}}^{{\text{ - }}}\)
If the concentration of \(\mathrm{OH}^{-}\)ions is decreased by \(1 / 4\) times, then the equilibrium concentration of \(\mathrm{Fe}^{3+}\) will increase by

314461 If the mixture of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) mixture in a closed apparatus is \(100 \mathrm{~atm}\) and \(20 \%\) of the mixture then reacts, the pressure at the same temperature will be

314462 A mixture of 2 moles of \(\mathrm{N}_{2}\) and 8 moles of \(\mathrm{H}_{2}\) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of \(\mathrm{N}_{2}\) was present. The equilibrium concentration of \(\mathrm{H}_{2}\) will be

314463 An amount of solid \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{~S}\) gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm . The equilibrium constant for \(\mathrm{NH}_{4} \mathrm{HS}\) decomposition at this temperature is

314464 Formaldehyde polymerises to form glucose according to the reaction, \(6 \mathrm{HCHO} \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). The theoretically computed equilibrium constant for this reaction is found to be \(6 \times 10^{22}\). If \(1 \mathrm{M}\) solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be

314460 In the reaction \({\text{Fe(OH}}{{\text{)}}_{\text{2}}}_{{\text{(S)}}} \rightleftharpoons {\text{Fe}}_{{\text{(aq)}}}^{{\text{3 + }}}{\text{ + 3OH}}_{{\text{(aq)}}}^{{\text{ - }}}\)
If the concentration of \(\mathrm{OH}^{-}\)ions is decreased by \(1 / 4\) times, then the equilibrium concentration of \(\mathrm{Fe}^{3+}\) will increase by

314461 If the mixture of \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) mixture in a closed apparatus is \(100 \mathrm{~atm}\) and \(20 \%\) of the mixture then reacts, the pressure at the same temperature will be

314462 A mixture of 2 moles of \(\mathrm{N}_{2}\) and 8 moles of \(\mathrm{H}_{2}\) are heated in a 2 lit vessel, till equilibrium is established. At equilibrium, 0.4 moles of \(\mathrm{N}_{2}\) was present. The equilibrium concentration of \(\mathrm{H}_{2}\) will be

314463 An amount of solid \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. Ammonium hydrogen sulphide decomposes to yield \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{~S}\) gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm . The equilibrium constant for \(\mathrm{NH}_{4} \mathrm{HS}\) decomposition at this temperature is

314464 Formaldehyde polymerises to form glucose according to the reaction, \(6 \mathrm{HCHO} \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\). The theoretically computed equilibrium constant for this reaction is found to be \(6 \times 10^{22}\). If \(1 \mathrm{M}\) solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be