314352
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude
1 Pressure increases
2 Temperature decreases
3 Pressure decreases
4 Temperature increases
Explanation:
At high altitude, pressure is low.
CHXI06:STATES OF MATTER
314353
Which of the following sets consists of gases with the same rate of diffusion at identical temperature and pressure?
Rate of diffusion depends upon the molecular mass of a gas as \(\frac{{{{\rm{r}}_{\rm{1}}}}}{{{{\rm{r}}_{\rm{2}}}}} = \sqrt {\frac{{{{\rm{M}}_{\rm{2}}}}}{{{{\rm{M}}_{\rm{1}}}}}} \) . \(\mathrm{CO}_{2} \mathrm{~N}_{2} \mathrm{O}\) and \(\mathrm{C}_{3} \mathrm{H}_{8}\) all have same molecular mass, hence will have same rate of diffusion.
CHXI06:STATES OF MATTER
314354
In order to increase the volume of a gas by \(\mathrm{10 \%}\), the pressure of the gas should be
1 decreased by \(\mathrm{10 \%}\)
2 decreased by \(\mathrm{1 \%}\)
3 increased by \(\mathrm{10 \%}\)
4 increased by \(\mathrm{1 \%}\)
Explanation:
According to Boyle's law, Pressure is inversely proportional to volume at constant temperature. i.e., \(\mathrm{\mathrm{P} \propto \dfrac{1}{\mathrm{~V}}}\) or \(\mathrm{\mathrm{PV}=}\) constant \(\therefore {{\rm{P}}_{\rm{1}}}{\rm{\;}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{P}}_{\rm{2}}}{\rm{\;}}\) \({{\rm{V}}_{\rm{2}}}{{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{{\rm{P}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}}}{{{{\rm{V}}_{\rm{2}}}}}\) \({{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{P \times V}}}}{{{\rm{1}}{\rm{.1\;V}}}}\) \(\mathrm{\mathrm{P}_{2}=0.9 \times \mathrm{P}}\) (i.e., \(\mathrm{10 \%}\) decrease in pressure). Hint : If volume increases by \(\mathrm{10 \%}\), pressure decreases by \(\mathrm{10 \%}\), according to Boyle's law.
KCET - 2008
CHXI06:STATES OF MATTER
314355
What will be the minimum pressure(in bar) required to compress \(\mathrm{500 \mathrm{dm}^{3}}\) of air at 1 bar to \(\mathrm{200 \mathrm{dm}^{3}}\) at \(\mathrm{30^{\circ} \mathrm{C}}\) ?
1 3
2 3.5
3 2
4 2.5
Explanation:
According to Boyle's law, \(\mathrm{\mathrm{P}_{1} \mathrm{~V}_{1}=\mathrm{P}_{2} \mathrm{~V}_{2}}\) (1) \(\mathrm{\left(500 \mathrm{dm}^{3}\right)=P_{2}\left(200 \mathrm{dm}^{3}\right)}\) \(\mathrm{\mathrm{P}_{2}=2.5}\) bar
CHXI06:STATES OF MATTER
314356
At what temperature in the Celsius scale, volume of a certain mass of gas at \(\mathrm{27^{\circ} \mathrm{C}}\) will be doubled keeping the pressure constant?
314352
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude
1 Pressure increases
2 Temperature decreases
3 Pressure decreases
4 Temperature increases
Explanation:
At high altitude, pressure is low.
CHXI06:STATES OF MATTER
314353
Which of the following sets consists of gases with the same rate of diffusion at identical temperature and pressure?
Rate of diffusion depends upon the molecular mass of a gas as \(\frac{{{{\rm{r}}_{\rm{1}}}}}{{{{\rm{r}}_{\rm{2}}}}} = \sqrt {\frac{{{{\rm{M}}_{\rm{2}}}}}{{{{\rm{M}}_{\rm{1}}}}}} \) . \(\mathrm{CO}_{2} \mathrm{~N}_{2} \mathrm{O}\) and \(\mathrm{C}_{3} \mathrm{H}_{8}\) all have same molecular mass, hence will have same rate of diffusion.
CHXI06:STATES OF MATTER
314354
In order to increase the volume of a gas by \(\mathrm{10 \%}\), the pressure of the gas should be
1 decreased by \(\mathrm{10 \%}\)
2 decreased by \(\mathrm{1 \%}\)
3 increased by \(\mathrm{10 \%}\)
4 increased by \(\mathrm{1 \%}\)
Explanation:
According to Boyle's law, Pressure is inversely proportional to volume at constant temperature. i.e., \(\mathrm{\mathrm{P} \propto \dfrac{1}{\mathrm{~V}}}\) or \(\mathrm{\mathrm{PV}=}\) constant \(\therefore {{\rm{P}}_{\rm{1}}}{\rm{\;}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{P}}_{\rm{2}}}{\rm{\;}}\) \({{\rm{V}}_{\rm{2}}}{{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{{\rm{P}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}}}{{{{\rm{V}}_{\rm{2}}}}}\) \({{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{P \times V}}}}{{{\rm{1}}{\rm{.1\;V}}}}\) \(\mathrm{\mathrm{P}_{2}=0.9 \times \mathrm{P}}\) (i.e., \(\mathrm{10 \%}\) decrease in pressure). Hint : If volume increases by \(\mathrm{10 \%}\), pressure decreases by \(\mathrm{10 \%}\), according to Boyle's law.
KCET - 2008
CHXI06:STATES OF MATTER
314355
What will be the minimum pressure(in bar) required to compress \(\mathrm{500 \mathrm{dm}^{3}}\) of air at 1 bar to \(\mathrm{200 \mathrm{dm}^{3}}\) at \(\mathrm{30^{\circ} \mathrm{C}}\) ?
1 3
2 3.5
3 2
4 2.5
Explanation:
According to Boyle's law, \(\mathrm{\mathrm{P}_{1} \mathrm{~V}_{1}=\mathrm{P}_{2} \mathrm{~V}_{2}}\) (1) \(\mathrm{\left(500 \mathrm{dm}^{3}\right)=P_{2}\left(200 \mathrm{dm}^{3}\right)}\) \(\mathrm{\mathrm{P}_{2}=2.5}\) bar
CHXI06:STATES OF MATTER
314356
At what temperature in the Celsius scale, volume of a certain mass of gas at \(\mathrm{27^{\circ} \mathrm{C}}\) will be doubled keeping the pressure constant?
314352
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude
1 Pressure increases
2 Temperature decreases
3 Pressure decreases
4 Temperature increases
Explanation:
At high altitude, pressure is low.
CHXI06:STATES OF MATTER
314353
Which of the following sets consists of gases with the same rate of diffusion at identical temperature and pressure?
Rate of diffusion depends upon the molecular mass of a gas as \(\frac{{{{\rm{r}}_{\rm{1}}}}}{{{{\rm{r}}_{\rm{2}}}}} = \sqrt {\frac{{{{\rm{M}}_{\rm{2}}}}}{{{{\rm{M}}_{\rm{1}}}}}} \) . \(\mathrm{CO}_{2} \mathrm{~N}_{2} \mathrm{O}\) and \(\mathrm{C}_{3} \mathrm{H}_{8}\) all have same molecular mass, hence will have same rate of diffusion.
CHXI06:STATES OF MATTER
314354
In order to increase the volume of a gas by \(\mathrm{10 \%}\), the pressure of the gas should be
1 decreased by \(\mathrm{10 \%}\)
2 decreased by \(\mathrm{1 \%}\)
3 increased by \(\mathrm{10 \%}\)
4 increased by \(\mathrm{1 \%}\)
Explanation:
According to Boyle's law, Pressure is inversely proportional to volume at constant temperature. i.e., \(\mathrm{\mathrm{P} \propto \dfrac{1}{\mathrm{~V}}}\) or \(\mathrm{\mathrm{PV}=}\) constant \(\therefore {{\rm{P}}_{\rm{1}}}{\rm{\;}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{P}}_{\rm{2}}}{\rm{\;}}\) \({{\rm{V}}_{\rm{2}}}{{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{{\rm{P}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}}}{{{{\rm{V}}_{\rm{2}}}}}\) \({{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{P \times V}}}}{{{\rm{1}}{\rm{.1\;V}}}}\) \(\mathrm{\mathrm{P}_{2}=0.9 \times \mathrm{P}}\) (i.e., \(\mathrm{10 \%}\) decrease in pressure). Hint : If volume increases by \(\mathrm{10 \%}\), pressure decreases by \(\mathrm{10 \%}\), according to Boyle's law.
KCET - 2008
CHXI06:STATES OF MATTER
314355
What will be the minimum pressure(in bar) required to compress \(\mathrm{500 \mathrm{dm}^{3}}\) of air at 1 bar to \(\mathrm{200 \mathrm{dm}^{3}}\) at \(\mathrm{30^{\circ} \mathrm{C}}\) ?
1 3
2 3.5
3 2
4 2.5
Explanation:
According to Boyle's law, \(\mathrm{\mathrm{P}_{1} \mathrm{~V}_{1}=\mathrm{P}_{2} \mathrm{~V}_{2}}\) (1) \(\mathrm{\left(500 \mathrm{dm}^{3}\right)=P_{2}\left(200 \mathrm{dm}^{3}\right)}\) \(\mathrm{\mathrm{P}_{2}=2.5}\) bar
CHXI06:STATES OF MATTER
314356
At what temperature in the Celsius scale, volume of a certain mass of gas at \(\mathrm{27^{\circ} \mathrm{C}}\) will be doubled keeping the pressure constant?
314352
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude
1 Pressure increases
2 Temperature decreases
3 Pressure decreases
4 Temperature increases
Explanation:
At high altitude, pressure is low.
CHXI06:STATES OF MATTER
314353
Which of the following sets consists of gases with the same rate of diffusion at identical temperature and pressure?
Rate of diffusion depends upon the molecular mass of a gas as \(\frac{{{{\rm{r}}_{\rm{1}}}}}{{{{\rm{r}}_{\rm{2}}}}} = \sqrt {\frac{{{{\rm{M}}_{\rm{2}}}}}{{{{\rm{M}}_{\rm{1}}}}}} \) . \(\mathrm{CO}_{2} \mathrm{~N}_{2} \mathrm{O}\) and \(\mathrm{C}_{3} \mathrm{H}_{8}\) all have same molecular mass, hence will have same rate of diffusion.
CHXI06:STATES OF MATTER
314354
In order to increase the volume of a gas by \(\mathrm{10 \%}\), the pressure of the gas should be
1 decreased by \(\mathrm{10 \%}\)
2 decreased by \(\mathrm{1 \%}\)
3 increased by \(\mathrm{10 \%}\)
4 increased by \(\mathrm{1 \%}\)
Explanation:
According to Boyle's law, Pressure is inversely proportional to volume at constant temperature. i.e., \(\mathrm{\mathrm{P} \propto \dfrac{1}{\mathrm{~V}}}\) or \(\mathrm{\mathrm{PV}=}\) constant \(\therefore {{\rm{P}}_{\rm{1}}}{\rm{\;}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{P}}_{\rm{2}}}{\rm{\;}}\) \({{\rm{V}}_{\rm{2}}}{{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{{\rm{P}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}}}{{{{\rm{V}}_{\rm{2}}}}}\) \({{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{P \times V}}}}{{{\rm{1}}{\rm{.1\;V}}}}\) \(\mathrm{\mathrm{P}_{2}=0.9 \times \mathrm{P}}\) (i.e., \(\mathrm{10 \%}\) decrease in pressure). Hint : If volume increases by \(\mathrm{10 \%}\), pressure decreases by \(\mathrm{10 \%}\), according to Boyle's law.
KCET - 2008
CHXI06:STATES OF MATTER
314355
What will be the minimum pressure(in bar) required to compress \(\mathrm{500 \mathrm{dm}^{3}}\) of air at 1 bar to \(\mathrm{200 \mathrm{dm}^{3}}\) at \(\mathrm{30^{\circ} \mathrm{C}}\) ?
1 3
2 3.5
3 2
4 2.5
Explanation:
According to Boyle's law, \(\mathrm{\mathrm{P}_{1} \mathrm{~V}_{1}=\mathrm{P}_{2} \mathrm{~V}_{2}}\) (1) \(\mathrm{\left(500 \mathrm{dm}^{3}\right)=P_{2}\left(200 \mathrm{dm}^{3}\right)}\) \(\mathrm{\mathrm{P}_{2}=2.5}\) bar
CHXI06:STATES OF MATTER
314356
At what temperature in the Celsius scale, volume of a certain mass of gas at \(\mathrm{27^{\circ} \mathrm{C}}\) will be doubled keeping the pressure constant?
314352
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude
1 Pressure increases
2 Temperature decreases
3 Pressure decreases
4 Temperature increases
Explanation:
At high altitude, pressure is low.
CHXI06:STATES OF MATTER
314353
Which of the following sets consists of gases with the same rate of diffusion at identical temperature and pressure?
Rate of diffusion depends upon the molecular mass of a gas as \(\frac{{{{\rm{r}}_{\rm{1}}}}}{{{{\rm{r}}_{\rm{2}}}}} = \sqrt {\frac{{{{\rm{M}}_{\rm{2}}}}}{{{{\rm{M}}_{\rm{1}}}}}} \) . \(\mathrm{CO}_{2} \mathrm{~N}_{2} \mathrm{O}\) and \(\mathrm{C}_{3} \mathrm{H}_{8}\) all have same molecular mass, hence will have same rate of diffusion.
CHXI06:STATES OF MATTER
314354
In order to increase the volume of a gas by \(\mathrm{10 \%}\), the pressure of the gas should be
1 decreased by \(\mathrm{10 \%}\)
2 decreased by \(\mathrm{1 \%}\)
3 increased by \(\mathrm{10 \%}\)
4 increased by \(\mathrm{1 \%}\)
Explanation:
According to Boyle's law, Pressure is inversely proportional to volume at constant temperature. i.e., \(\mathrm{\mathrm{P} \propto \dfrac{1}{\mathrm{~V}}}\) or \(\mathrm{\mathrm{PV}=}\) constant \(\therefore {{\rm{P}}_{\rm{1}}}{\rm{\;}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{P}}_{\rm{2}}}{\rm{\;}}\) \({{\rm{V}}_{\rm{2}}}{{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{{\rm{P}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}}}{{{{\rm{V}}_{\rm{2}}}}}\) \({{\rm{P}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{P \times V}}}}{{{\rm{1}}{\rm{.1\;V}}}}\) \(\mathrm{\mathrm{P}_{2}=0.9 \times \mathrm{P}}\) (i.e., \(\mathrm{10 \%}\) decrease in pressure). Hint : If volume increases by \(\mathrm{10 \%}\), pressure decreases by \(\mathrm{10 \%}\), according to Boyle's law.
KCET - 2008
CHXI06:STATES OF MATTER
314355
What will be the minimum pressure(in bar) required to compress \(\mathrm{500 \mathrm{dm}^{3}}\) of air at 1 bar to \(\mathrm{200 \mathrm{dm}^{3}}\) at \(\mathrm{30^{\circ} \mathrm{C}}\) ?
1 3
2 3.5
3 2
4 2.5
Explanation:
According to Boyle's law, \(\mathrm{\mathrm{P}_{1} \mathrm{~V}_{1}=\mathrm{P}_{2} \mathrm{~V}_{2}}\) (1) \(\mathrm{\left(500 \mathrm{dm}^{3}\right)=P_{2}\left(200 \mathrm{dm}^{3}\right)}\) \(\mathrm{\mathrm{P}_{2}=2.5}\) bar
CHXI06:STATES OF MATTER
314356
At what temperature in the Celsius scale, volume of a certain mass of gas at \(\mathrm{27^{\circ} \mathrm{C}}\) will be doubled keeping the pressure constant?
