For ' \(\mathrm{n}\) ' moles of gas van der Waal's equation is \(\mathrm{\left(P+\dfrac{a n^{2}}{V^{2}}\right)(V-n b)=n R T}\) For \(\mathrm{0.2 \mathrm{~mol},\left(P+\dfrac{a(0.2)^{2}}{V^{2}}\right)(V-0.2 b)=0.2 R T}\)
CHXI06:STATES OF MATTER
314090
At relatively high pressure, van der Waals' equation reduces to
At high pressure, the pressure correction for 1 mole of gas is negligible. \(\therefore \;\;\;{\mkern 1mu} {\kern 1pt} \frac{{\rm{a}}}{{{{\rm{V}}^{\rm{2}}}}} = 0\) However, the volume correction cannot be neglected. Hence, van der Waals' equation reduces to \(({\rm{p}} + 0)({\rm{V}} - {\rm{b}}) = {\rm{RT}}\) \({\rm{(For}}\,{\rm{1}}\,{\rm{mole)}}\) \(\,{\rm{pV}} - {\rm{pb}} = {\rm{RT}}\) \({\rm{pV}} = {\rm{RT}} + {\rm{pb}}\)
CHXI06:STATES OF MATTER
314091
The units of constants \(a\) in van der Waals' equation is
For ' \(\mathrm{n}\) ' moles of gas van der Waal's equation is \(\mathrm{\left(P+\dfrac{a n^{2}}{V^{2}}\right)(V-n b)=n R T}\) For \(\mathrm{0.2 \mathrm{~mol},\left(P+\dfrac{a(0.2)^{2}}{V^{2}}\right)(V-0.2 b)=0.2 R T}\)
CHXI06:STATES OF MATTER
314090
At relatively high pressure, van der Waals' equation reduces to
At high pressure, the pressure correction for 1 mole of gas is negligible. \(\therefore \;\;\;{\mkern 1mu} {\kern 1pt} \frac{{\rm{a}}}{{{{\rm{V}}^{\rm{2}}}}} = 0\) However, the volume correction cannot be neglected. Hence, van der Waals' equation reduces to \(({\rm{p}} + 0)({\rm{V}} - {\rm{b}}) = {\rm{RT}}\) \({\rm{(For}}\,{\rm{1}}\,{\rm{mole)}}\) \(\,{\rm{pV}} - {\rm{pb}} = {\rm{RT}}\) \({\rm{pV}} = {\rm{RT}} + {\rm{pb}}\)
CHXI06:STATES OF MATTER
314091
The units of constants \(a\) in van der Waals' equation is
For ' \(\mathrm{n}\) ' moles of gas van der Waal's equation is \(\mathrm{\left(P+\dfrac{a n^{2}}{V^{2}}\right)(V-n b)=n R T}\) For \(\mathrm{0.2 \mathrm{~mol},\left(P+\dfrac{a(0.2)^{2}}{V^{2}}\right)(V-0.2 b)=0.2 R T}\)
CHXI06:STATES OF MATTER
314090
At relatively high pressure, van der Waals' equation reduces to
At high pressure, the pressure correction for 1 mole of gas is negligible. \(\therefore \;\;\;{\mkern 1mu} {\kern 1pt} \frac{{\rm{a}}}{{{{\rm{V}}^{\rm{2}}}}} = 0\) However, the volume correction cannot be neglected. Hence, van der Waals' equation reduces to \(({\rm{p}} + 0)({\rm{V}} - {\rm{b}}) = {\rm{RT}}\) \({\rm{(For}}\,{\rm{1}}\,{\rm{mole)}}\) \(\,{\rm{pV}} - {\rm{pb}} = {\rm{RT}}\) \({\rm{pV}} = {\rm{RT}} + {\rm{pb}}\)
CHXI06:STATES OF MATTER
314091
The units of constants \(a\) in van der Waals' equation is
For ' \(\mathrm{n}\) ' moles of gas van der Waal's equation is \(\mathrm{\left(P+\dfrac{a n^{2}}{V^{2}}\right)(V-n b)=n R T}\) For \(\mathrm{0.2 \mathrm{~mol},\left(P+\dfrac{a(0.2)^{2}}{V^{2}}\right)(V-0.2 b)=0.2 R T}\)
CHXI06:STATES OF MATTER
314090
At relatively high pressure, van der Waals' equation reduces to
At high pressure, the pressure correction for 1 mole of gas is negligible. \(\therefore \;\;\;{\mkern 1mu} {\kern 1pt} \frac{{\rm{a}}}{{{{\rm{V}}^{\rm{2}}}}} = 0\) However, the volume correction cannot be neglected. Hence, van der Waals' equation reduces to \(({\rm{p}} + 0)({\rm{V}} - {\rm{b}}) = {\rm{RT}}\) \({\rm{(For}}\,{\rm{1}}\,{\rm{mole)}}\) \(\,{\rm{pV}} - {\rm{pb}} = {\rm{RT}}\) \({\rm{pV}} = {\rm{RT}} + {\rm{pb}}\)
CHXI06:STATES OF MATTER
314091
The units of constants \(a\) in van der Waals' equation is