313865 group moment is \(2.3 \,\mathrm{D}\) and \(-\mathrm{CH}_{3}\) group moment is \(0.4 \,\mathrm{D}\). Determine the dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) in \(\mathrm{cm} \times 10^{30}\) in nearest possible integer.
1 8
2 9
3 7
4 17
Explanation:
The resultant dipole moment of two \(\mathrm{CH}_{3}-\mathrm{C}\) bonds. \(=\sqrt{(0.4)^{2}+(0.4)^{2}+2 \times(0.4)^{2} \times \cos 120^{\circ}}\) \( = \sqrt {0.32 - 0.16} = 0.4\,\,{\rm{D}}\) \(\therefore\) Net dipole moment of the molecule \( = 2.3 + 0.4 = 2.7\,\,{\rm{D}}\) \(1 \mathrm{D}=10^{-18}\) esu \(-\mathrm{cm} .=10^{-20}\) esu-m. \(4.8 \times {10^{ - 10}}\,\,{\rm{esu}} = 1.6 \times {10^{ - 19}}{\rm{C}}\) \(\therefore 1\) esu \(=\dfrac{1}{3} \times 10^{-9} \mathrm{C}\). \(\therefore 1 \mathrm{D}=\dfrac{1}{3} \times 10^{-29} \mathrm{cm}=\dfrac{10}{3} \times 10^{-30} \mathrm{cm}\). \(\therefore\) Net dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) \(=2.7 \times \dfrac{10}{3} \times 10^{-30} \mathrm{cm}=9 \times 10^{-30} \mathrm{cm}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313866
Which of the following set of molecules will have zero dipole moment?
\({\rm{B}}{{\rm{F}}_{\rm{3}}}{\rm{,}}\,\,{\rm{Be}}{{\rm{F}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{O}}_{\rm{2}}}\) and 1,4-dichloro benzene are symmetrical structure.
NEET - 2020
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313867
Identify the correct answer.
1 Three resonance structures can be drawn for ozone
2 \({\mathrm{\mathrm{BF}_{3}}}\) has non-zero dipole moment
3 Dipole moment of \({\mathrm{\mathrm{NF}_{3}}}\) is greater than that of \({\mathrm{\mathrm{NH}_{3}}}\)
4 Three canonical forms can be drawn for \({\mathrm{\mathrm{CO}_{3}^{2-}}}\) ion
Explanation:
(1) Two resonating structures can be drawn for ozone. (2) \({\mathrm{\mathrm{BF}_{3}}}\) is symmetrical molecule, so \({\mathrm{\mu=0}}\). (3) Dipole moment of \({\mathrm{\mathrm{NH}_{3}>\mathrm{NF}_{3}}}\); as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine. (4)
NEET - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313868
Which bond angle, \({\rm{\theta }}\) would result in the maximum dipole moment for the triatomic molecule \({\rm{X}}{{\rm{Y}}_{\rm{2}}}\) shown below:
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313865 group moment is \(2.3 \,\mathrm{D}\) and \(-\mathrm{CH}_{3}\) group moment is \(0.4 \,\mathrm{D}\). Determine the dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) in \(\mathrm{cm} \times 10^{30}\) in nearest possible integer.
1 8
2 9
3 7
4 17
Explanation:
The resultant dipole moment of two \(\mathrm{CH}_{3}-\mathrm{C}\) bonds. \(=\sqrt{(0.4)^{2}+(0.4)^{2}+2 \times(0.4)^{2} \times \cos 120^{\circ}}\) \( = \sqrt {0.32 - 0.16} = 0.4\,\,{\rm{D}}\) \(\therefore\) Net dipole moment of the molecule \( = 2.3 + 0.4 = 2.7\,\,{\rm{D}}\) \(1 \mathrm{D}=10^{-18}\) esu \(-\mathrm{cm} .=10^{-20}\) esu-m. \(4.8 \times {10^{ - 10}}\,\,{\rm{esu}} = 1.6 \times {10^{ - 19}}{\rm{C}}\) \(\therefore 1\) esu \(=\dfrac{1}{3} \times 10^{-9} \mathrm{C}\). \(\therefore 1 \mathrm{D}=\dfrac{1}{3} \times 10^{-29} \mathrm{cm}=\dfrac{10}{3} \times 10^{-30} \mathrm{cm}\). \(\therefore\) Net dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) \(=2.7 \times \dfrac{10}{3} \times 10^{-30} \mathrm{cm}=9 \times 10^{-30} \mathrm{cm}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313866
Which of the following set of molecules will have zero dipole moment?
\({\rm{B}}{{\rm{F}}_{\rm{3}}}{\rm{,}}\,\,{\rm{Be}}{{\rm{F}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{O}}_{\rm{2}}}\) and 1,4-dichloro benzene are symmetrical structure.
NEET - 2020
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313867
Identify the correct answer.
1 Three resonance structures can be drawn for ozone
2 \({\mathrm{\mathrm{BF}_{3}}}\) has non-zero dipole moment
3 Dipole moment of \({\mathrm{\mathrm{NF}_{3}}}\) is greater than that of \({\mathrm{\mathrm{NH}_{3}}}\)
4 Three canonical forms can be drawn for \({\mathrm{\mathrm{CO}_{3}^{2-}}}\) ion
Explanation:
(1) Two resonating structures can be drawn for ozone. (2) \({\mathrm{\mathrm{BF}_{3}}}\) is symmetrical molecule, so \({\mathrm{\mu=0}}\). (3) Dipole moment of \({\mathrm{\mathrm{NH}_{3}>\mathrm{NF}_{3}}}\); as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine. (4)
NEET - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313868
Which bond angle, \({\rm{\theta }}\) would result in the maximum dipole moment for the triatomic molecule \({\rm{X}}{{\rm{Y}}_{\rm{2}}}\) shown below:
313865 group moment is \(2.3 \,\mathrm{D}\) and \(-\mathrm{CH}_{3}\) group moment is \(0.4 \,\mathrm{D}\). Determine the dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) in \(\mathrm{cm} \times 10^{30}\) in nearest possible integer.
1 8
2 9
3 7
4 17
Explanation:
The resultant dipole moment of two \(\mathrm{CH}_{3}-\mathrm{C}\) bonds. \(=\sqrt{(0.4)^{2}+(0.4)^{2}+2 \times(0.4)^{2} \times \cos 120^{\circ}}\) \( = \sqrt {0.32 - 0.16} = 0.4\,\,{\rm{D}}\) \(\therefore\) Net dipole moment of the molecule \( = 2.3 + 0.4 = 2.7\,\,{\rm{D}}\) \(1 \mathrm{D}=10^{-18}\) esu \(-\mathrm{cm} .=10^{-20}\) esu-m. \(4.8 \times {10^{ - 10}}\,\,{\rm{esu}} = 1.6 \times {10^{ - 19}}{\rm{C}}\) \(\therefore 1\) esu \(=\dfrac{1}{3} \times 10^{-9} \mathrm{C}\). \(\therefore 1 \mathrm{D}=\dfrac{1}{3} \times 10^{-29} \mathrm{cm}=\dfrac{10}{3} \times 10^{-30} \mathrm{cm}\). \(\therefore\) Net dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) \(=2.7 \times \dfrac{10}{3} \times 10^{-30} \mathrm{cm}=9 \times 10^{-30} \mathrm{cm}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313866
Which of the following set of molecules will have zero dipole moment?
\({\rm{B}}{{\rm{F}}_{\rm{3}}}{\rm{,}}\,\,{\rm{Be}}{{\rm{F}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{O}}_{\rm{2}}}\) and 1,4-dichloro benzene are symmetrical structure.
NEET - 2020
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313867
Identify the correct answer.
1 Three resonance structures can be drawn for ozone
2 \({\mathrm{\mathrm{BF}_{3}}}\) has non-zero dipole moment
3 Dipole moment of \({\mathrm{\mathrm{NF}_{3}}}\) is greater than that of \({\mathrm{\mathrm{NH}_{3}}}\)
4 Three canonical forms can be drawn for \({\mathrm{\mathrm{CO}_{3}^{2-}}}\) ion
Explanation:
(1) Two resonating structures can be drawn for ozone. (2) \({\mathrm{\mathrm{BF}_{3}}}\) is symmetrical molecule, so \({\mathrm{\mu=0}}\). (3) Dipole moment of \({\mathrm{\mathrm{NH}_{3}>\mathrm{NF}_{3}}}\); as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine. (4)
NEET - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313868
Which bond angle, \({\rm{\theta }}\) would result in the maximum dipole moment for the triatomic molecule \({\rm{X}}{{\rm{Y}}_{\rm{2}}}\) shown below:
313865 group moment is \(2.3 \,\mathrm{D}\) and \(-\mathrm{CH}_{3}\) group moment is \(0.4 \,\mathrm{D}\). Determine the dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) in \(\mathrm{cm} \times 10^{30}\) in nearest possible integer.
1 8
2 9
3 7
4 17
Explanation:
The resultant dipole moment of two \(\mathrm{CH}_{3}-\mathrm{C}\) bonds. \(=\sqrt{(0.4)^{2}+(0.4)^{2}+2 \times(0.4)^{2} \times \cos 120^{\circ}}\) \( = \sqrt {0.32 - 0.16} = 0.4\,\,{\rm{D}}\) \(\therefore\) Net dipole moment of the molecule \( = 2.3 + 0.4 = 2.7\,\,{\rm{D}}\) \(1 \mathrm{D}=10^{-18}\) esu \(-\mathrm{cm} .=10^{-20}\) esu-m. \(4.8 \times {10^{ - 10}}\,\,{\rm{esu}} = 1.6 \times {10^{ - 19}}{\rm{C}}\) \(\therefore 1\) esu \(=\dfrac{1}{3} \times 10^{-9} \mathrm{C}\). \(\therefore 1 \mathrm{D}=\dfrac{1}{3} \times 10^{-29} \mathrm{cm}=\dfrac{10}{3} \times 10^{-30} \mathrm{cm}\). \(\therefore\) Net dipole moment of \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) \(=2.7 \times \dfrac{10}{3} \times 10^{-30} \mathrm{cm}=9 \times 10^{-30} \mathrm{cm}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313866
Which of the following set of molecules will have zero dipole moment?
\({\rm{B}}{{\rm{F}}_{\rm{3}}}{\rm{,}}\,\,{\rm{Be}}{{\rm{F}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{O}}_{\rm{2}}}\) and 1,4-dichloro benzene are symmetrical structure.
NEET - 2020
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313867
Identify the correct answer.
1 Three resonance structures can be drawn for ozone
2 \({\mathrm{\mathrm{BF}_{3}}}\) has non-zero dipole moment
3 Dipole moment of \({\mathrm{\mathrm{NF}_{3}}}\) is greater than that of \({\mathrm{\mathrm{NH}_{3}}}\)
4 Three canonical forms can be drawn for \({\mathrm{\mathrm{CO}_{3}^{2-}}}\) ion
Explanation:
(1) Two resonating structures can be drawn for ozone. (2) \({\mathrm{\mathrm{BF}_{3}}}\) is symmetrical molecule, so \({\mathrm{\mu=0}}\). (3) Dipole moment of \({\mathrm{\mathrm{NH}_{3}>\mathrm{NF}_{3}}}\); as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine. (4)
NEET - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313868
Which bond angle, \({\rm{\theta }}\) would result in the maximum dipole moment for the triatomic molecule \({\rm{X}}{{\rm{Y}}_{\rm{2}}}\) shown below:
