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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313865 supporting img
group moment is $2.3 D$ and $- {CH}_{3}$ group moment is $0.4 D$ . Determine the dipole moment of ${({CH}_{3})}_{2} CO$ in $cm \times 10^{30}$ in nearest possible integer.

1 8

2 9

3 7

4 17

Explanation:

supporting img

The resultant dipole moment of two ${CH}_{3} - C$ bonds.
$= \sqrt{(0.4)^{2} + (0.4)^{2} + 2 \times (0.4)^{2} \times \cos 120^{\circ}}$
$= \sqrt{0.32 - 0.16} = 0.4 D$
$∴$ Net dipole moment of the molecule $= 2.3 + 0.4 = 2.7 D$
$1 D = 10^{- 18}$ esu $- cm . = 10^{- 20}$ esu-m.
$4.8 \times 10^{- 10} e s u = 1.6 \times 10^{- 19} C$
$∴ 1$ esu $= \frac{1}{3} \times 10^{- 9} C$ .
$∴ 1 D = \frac{1}{3} \times 10^{- 29} cm = \frac{10}{3} \times 10^{- 30} cm$ .
$∴$ Net dipole moment of ${({CH}_{3})}_{2} CO$
$= 2.7 \times \frac{10}{3} \times 10^{- 30} cm = 9 \times 10^{- 30} cm$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313866 Which of the following set of molecules will have zero dipole moment?

1 Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene

2 Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene

3 Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene

4 Ammonia, beryllium difluoride, water, 1,4- dichlorobenzene

Explanation:

$B F_{3}, B e F_{2}, C O_{2}$ and 1,4-dichloro benzene are symmetrical structure.
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NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313867 Identify the correct answer.

1 Three resonance structures can be drawn for ozone

2

{BF}_{3}

has non-zero dipole moment

3 Dipole moment of

{NF}_{3}

is greater than that of

{NH}_{3}

4 Three canonical forms can be drawn for

{CO}_{3}^{2 -}

ion

Explanation:

(1) Two resonating structures can be drawn for ozone.
(2) ${BF}_{3}$ is symmetrical molecule, so $μ = 0$ .
(3) Dipole moment of ${NH}_{3} > {NF}_{3}$ ;
as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine.
(4)
supporting img

NEET - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313868 Which bond angle, $θ$ would result in the maximum dipole moment for the triatomic molecule $X Y_{2}$ shown below:
supporting img

1

θ = 90^{\circ}

2

θ = 120^{\circ}

3

θ = 150^{\circ}

4

θ = 180^{\circ}

Explanation:

$μ = \sqrt{μ_{1}^{2} {+ μ}_{2}^{2} + 2 μ_{1} μ_{2} c o s θ}$
If $θ = 90^{\circ}, μ$ is maximum.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313865 supporting img
group moment is $2.3 D$ and $- {CH}_{3}$ group moment is $0.4 D$ . Determine the dipole moment of ${({CH}_{3})}_{2} CO$ in $cm \times 10^{30}$ in nearest possible integer.

1 8

2 9

3 7

4 17

Explanation:

supporting img

The resultant dipole moment of two ${CH}_{3} - C$ bonds.
$= \sqrt{(0.4)^{2} + (0.4)^{2} + 2 \times (0.4)^{2} \times \cos 120^{\circ}}$
$= \sqrt{0.32 - 0.16} = 0.4 D$
$∴$ Net dipole moment of the molecule $= 2.3 + 0.4 = 2.7 D$
$1 D = 10^{- 18}$ esu $- cm . = 10^{- 20}$ esu-m.
$4.8 \times 10^{- 10} e s u = 1.6 \times 10^{- 19} C$
$∴ 1$ esu $= \frac{1}{3} \times 10^{- 9} C$ .
$∴ 1 D = \frac{1}{3} \times 10^{- 29} cm = \frac{10}{3} \times 10^{- 30} cm$ .
$∴$ Net dipole moment of ${({CH}_{3})}_{2} CO$
$= 2.7 \times \frac{10}{3} \times 10^{- 30} cm = 9 \times 10^{- 30} cm$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313866 Which of the following set of molecules will have zero dipole moment?

1 Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene

2 Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene

3 Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene

4 Ammonia, beryllium difluoride, water, 1,4- dichlorobenzene

Explanation:

$B F_{3}, B e F_{2}, C O_{2}$ and 1,4-dichloro benzene are symmetrical structure.
supporting img

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313867 Identify the correct answer.

1 Three resonance structures can be drawn for ozone

2

{BF}_{3}

has non-zero dipole moment

3 Dipole moment of

{NF}_{3}

is greater than that of

{NH}_{3}

4 Three canonical forms can be drawn for

{CO}_{3}^{2 -}

ion

Explanation:

(1) Two resonating structures can be drawn for ozone.
(2) ${BF}_{3}$ is symmetrical molecule, so $μ = 0$ .
(3) Dipole moment of ${NH}_{3} > {NF}_{3}$ ;
as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine.
(4)
supporting img

NEET - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313868 Which bond angle, $θ$ would result in the maximum dipole moment for the triatomic molecule $X Y_{2}$ shown below:
supporting img

1

θ = 90^{\circ}

2

θ = 120^{\circ}

3

θ = 150^{\circ}

4

θ = 180^{\circ}

Explanation:

$μ = \sqrt{μ_{1}^{2} {+ μ}_{2}^{2} + 2 μ_{1} μ_{2} c o s θ}$
If $θ = 90^{\circ}, μ$ is maximum.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313865 supporting img
group moment is $2.3 D$ and $- {CH}_{3}$ group moment is $0.4 D$ . Determine the dipole moment of ${({CH}_{3})}_{2} CO$ in $cm \times 10^{30}$ in nearest possible integer.

1 8

2 9

3 7

4 17

Explanation:

supporting img

The resultant dipole moment of two ${CH}_{3} - C$ bonds.
$= \sqrt{(0.4)^{2} + (0.4)^{2} + 2 \times (0.4)^{2} \times \cos 120^{\circ}}$
$= \sqrt{0.32 - 0.16} = 0.4 D$
$∴$ Net dipole moment of the molecule $= 2.3 + 0.4 = 2.7 D$
$1 D = 10^{- 18}$ esu $- cm . = 10^{- 20}$ esu-m.
$4.8 \times 10^{- 10} e s u = 1.6 \times 10^{- 19} C$
$∴ 1$ esu $= \frac{1}{3} \times 10^{- 9} C$ .
$∴ 1 D = \frac{1}{3} \times 10^{- 29} cm = \frac{10}{3} \times 10^{- 30} cm$ .
$∴$ Net dipole moment of ${({CH}_{3})}_{2} CO$
$= 2.7 \times \frac{10}{3} \times 10^{- 30} cm = 9 \times 10^{- 30} cm$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313866 Which of the following set of molecules will have zero dipole moment?

1 Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene

2 Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene

3 Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene

4 Ammonia, beryllium difluoride, water, 1,4- dichlorobenzene

Explanation:

$B F_{3}, B e F_{2}, C O_{2}$ and 1,4-dichloro benzene are symmetrical structure.
supporting img

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313867 Identify the correct answer.

1 Three resonance structures can be drawn for ozone

2

{BF}_{3}

has non-zero dipole moment

3 Dipole moment of

{NF}_{3}

is greater than that of

{NH}_{3}

4 Three canonical forms can be drawn for

{CO}_{3}^{2 -}

ion

Explanation:

(1) Two resonating structures can be drawn for ozone.
(2) ${BF}_{3}$ is symmetrical molecule, so $μ = 0$ .
(3) Dipole moment of ${NH}_{3} > {NF}_{3}$ ;
as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine.
(4)
supporting img

NEET - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313868 Which bond angle, $θ$ would result in the maximum dipole moment for the triatomic molecule $X Y_{2}$ shown below:
supporting img

1

θ = 90^{\circ}

2

θ = 120^{\circ}

3

θ = 150^{\circ}

4

θ = 180^{\circ}

Explanation:

$μ = \sqrt{μ_{1}^{2} {+ μ}_{2}^{2} + 2 μ_{1} μ_{2} c o s θ}$
If $θ = 90^{\circ}, μ$ is maximum.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313865 supporting img
group moment is $2.3 D$ and $- {CH}_{3}$ group moment is $0.4 D$ . Determine the dipole moment of ${({CH}_{3})}_{2} CO$ in $cm \times 10^{30}$ in nearest possible integer.

1 8

2 9

3 7

4 17

Explanation:

supporting img

The resultant dipole moment of two ${CH}_{3} - C$ bonds.
$= \sqrt{(0.4)^{2} + (0.4)^{2} + 2 \times (0.4)^{2} \times \cos 120^{\circ}}$
$= \sqrt{0.32 - 0.16} = 0.4 D$
$∴$ Net dipole moment of the molecule $= 2.3 + 0.4 = 2.7 D$
$1 D = 10^{- 18}$ esu $- cm . = 10^{- 20}$ esu-m.
$4.8 \times 10^{- 10} e s u = 1.6 \times 10^{- 19} C$
$∴ 1$ esu $= \frac{1}{3} \times 10^{- 9} C$ .
$∴ 1 D = \frac{1}{3} \times 10^{- 29} cm = \frac{10}{3} \times 10^{- 30} cm$ .
$∴$ Net dipole moment of ${({CH}_{3})}_{2} CO$
$= 2.7 \times \frac{10}{3} \times 10^{- 30} cm = 9 \times 10^{- 30} cm$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313866 Which of the following set of molecules will have zero dipole moment?

1 Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene

2 Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene

3 Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene

4 Ammonia, beryllium difluoride, water, 1,4- dichlorobenzene

Explanation:

$B F_{3}, B e F_{2}, C O_{2}$ and 1,4-dichloro benzene are symmetrical structure.
supporting img

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313867 Identify the correct answer.

1 Three resonance structures can be drawn for ozone

2

{BF}_{3}

has non-zero dipole moment

3 Dipole moment of

{NF}_{3}

is greater than that of

{NH}_{3}

4 Three canonical forms can be drawn for

{CO}_{3}^{2 -}

ion

Explanation:

(1) Two resonating structures can be drawn for ozone.
(2) ${BF}_{3}$ is symmetrical molecule, so $μ = 0$ .
(3) Dipole moment of ${NH}_{3} > {NF}_{3}$ ;
as nitrogen is more electronegative than hydrogen and is less electronegative than fluorine.
(4)
supporting img

NEET - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313868 Which bond angle, $θ$ would result in the maximum dipole moment for the triatomic molecule $X Y_{2}$ shown below:
supporting img

1

θ = 90^{\circ}

2

θ = 120^{\circ}

3

θ = 150^{\circ}

4

θ = 180^{\circ}

Explanation:

$μ = \sqrt{μ_{1}^{2} {+ μ}_{2}^{2} + 2 μ_{1} μ_{2} c o s θ}$
If $θ = 90^{\circ}, μ$ is maximum.

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