Hybridisation
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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise
2 The angle between any two hybrid orbitals is always same
3 Hybrid orbitals always form sigma bonds
4 Only electrons undergo hybridisation and not orbitals.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25
2 67 and 75
3 50 and 75
4 33 and 75
JEE - 2018
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
\(\mathrm{C}-\mathrm{H}\) bond in ethyne is shorter than \(\mathrm{C}-\mathrm{H}\) bonds in ethene.
Reason :
( \(\mathbf{R})\) Carbon atom in ethene is \(\mathrm{sp}\) hybridised while it is \(\mathrm{sp}^{2}\) in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect
AIIMS - 2007
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound \({\rm{C}}{{\rm{H}}_{\rm{2}}}{\rm{ = C = C}}{{\rm{H}}_{\rm{2}}}\) is

1 \({\rm{sp,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
3 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in \({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{H}}_{\rm{4}}}\,\,{\rm{and}}\,\,{\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\) respectively is

1 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
3 \({\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
NEET DIGITAL LIBRARY
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise
2 The angle between any two hybrid orbitals is always same
3 Hybrid orbitals always form sigma bonds
4 Only electrons undergo hybridisation and not orbitals.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25
2 67 and 75
3 50 and 75
4 33 and 75
JEE - 2018
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
\(\mathrm{C}-\mathrm{H}\) bond in ethyne is shorter than \(\mathrm{C}-\mathrm{H}\) bonds in ethene.
Reason :
( \(\mathbf{R})\) Carbon atom in ethene is \(\mathrm{sp}\) hybridised while it is \(\mathrm{sp}^{2}\) in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect
AIIMS - 2007
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound \({\rm{C}}{{\rm{H}}_{\rm{2}}}{\rm{ = C = C}}{{\rm{H}}_{\rm{2}}}\) is

1 \({\rm{sp,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
3 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in \({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{H}}_{\rm{4}}}\,\,{\rm{and}}\,\,{\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\) respectively is

1 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
3 \({\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise
2 The angle between any two hybrid orbitals is always same
3 Hybrid orbitals always form sigma bonds
4 Only electrons undergo hybridisation and not orbitals.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25
2 67 and 75
3 50 and 75
4 33 and 75
JEE - 2018
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
\(\mathrm{C}-\mathrm{H}\) bond in ethyne is shorter than \(\mathrm{C}-\mathrm{H}\) bonds in ethene.
Reason :
( \(\mathbf{R})\) Carbon atom in ethene is \(\mathrm{sp}\) hybridised while it is \(\mathrm{sp}^{2}\) in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect
AIIMS - 2007
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound \({\rm{C}}{{\rm{H}}_{\rm{2}}}{\rm{ = C = C}}{{\rm{H}}_{\rm{2}}}\) is

1 \({\rm{sp,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
3 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in \({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{H}}_{\rm{4}}}\,\,{\rm{and}}\,\,{\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\) respectively is

1 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
3 \({\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
For More Updates join with Us
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise
2 The angle between any two hybrid orbitals is always same
3 Hybrid orbitals always form sigma bonds
4 Only electrons undergo hybridisation and not orbitals.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25
2 67 and 75
3 50 and 75
4 33 and 75
JEE - 2018
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
\(\mathrm{C}-\mathrm{H}\) bond in ethyne is shorter than \(\mathrm{C}-\mathrm{H}\) bonds in ethene.
Reason :
( \(\mathbf{R})\) Carbon atom in ethene is \(\mathrm{sp}\) hybridised while it is \(\mathrm{sp}^{2}\) in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect
AIIMS - 2007
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound \({\rm{C}}{{\rm{H}}_{\rm{2}}}{\rm{ = C = C}}{{\rm{H}}_{\rm{2}}}\) is

1 \({\rm{sp,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
3 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in \({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{H}}_{\rm{4}}}\,\,{\rm{and}}\,\,{\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\) respectively is

1 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
3 \({\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
NEET DIGITAL LIBRARY
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise
2 The angle between any two hybrid orbitals is always same
3 Hybrid orbitals always form sigma bonds
4 Only electrons undergo hybridisation and not orbitals.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25
2 67 and 75
3 50 and 75
4 33 and 75
JEE - 2018
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
\(\mathrm{C}-\mathrm{H}\) bond in ethyne is shorter than \(\mathrm{C}-\mathrm{H}\) bonds in ethene.
Reason :
( \(\mathbf{R})\) Carbon atom in ethene is \(\mathrm{sp}\) hybridised while it is \(\mathrm{sp}^{2}\) in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect
AIIMS - 2007
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound \({\rm{C}}{{\rm{H}}_{\rm{2}}}{\rm{ = C = C}}{{\rm{H}}_{\rm{2}}}\) is

1 \({\rm{sp,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{sp}}\)
3 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in \({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{C}}{{\rm{H}}_{\rm{4}}}\,\,{\rm{and}}\,\,{\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\) respectively is

1 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)
2 \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{,}}\,\,{\rm{sp}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
3 \({\rm{sp,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{s}}{{\rm{p}}^{\rm{2}}}\)
4 \({\rm{s}}{{\rm{p}}^{\rm{2}}}{\rm{,}}\,\,{\rm{s}}{{\rm{p}}^{\rm{3}}}\,\,{\rm{and}}\,\,{\rm{sp}}\)