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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise

2 The angle between any two hybrid orbitals is always same

3 Hybrid orbitals always form sigma bonds

4 Only electrons undergo hybridisation and not orbitals.

Explanation:

$π$ bond orbital formation is not explained
by hybridisation

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25

2 67 and 75

3 50 and 75

4 33 and 75

JEE - 2018

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
$C - H$ bond in ethyne is shorter than $C - H$ bonds in ethene.
Reason :
( $R)$ Carbon atom in ethene is $sp$ hybridised while it is ${sp}^{2}$ in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect

Explanation:

The carbon atoms in ethene is ${sp}^{2}$ hybridised due to
supporting img
t while it is sp in ethyne due to $- C \equiv C -$

Hence, Assertion is correct but Reason is incorrect.

AIIMS - 2007

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound $C H_{2} = C = C H_{2}$ is

1

s p, s p, s p

2

s p^{3}, s p, s p

3

s p^{3}, s p^{2}, s p

4

s p^{2}, s p, s p^{2}

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in $C O_{2}, C H_{4} a n d {C O}_{3}^{2 -}$ respectively is

1

s p^{3}, s p^{2} a n d s p

2

s p^{3}, s p a n d s p^{2}

3

s p, s p^{3} a n d s p^{2}

4

s p^{2}, s p^{3} a n d s p

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise

2 The angle between any two hybrid orbitals is always same

3 Hybrid orbitals always form sigma bonds

4 Only electrons undergo hybridisation and not orbitals.

Explanation:

$π$ bond orbital formation is not explained
by hybridisation

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25

2 67 and 75

3 50 and 75

4 33 and 75

JEE - 2018

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
$C - H$ bond in ethyne is shorter than $C - H$ bonds in ethene.
Reason :
( $R)$ Carbon atom in ethene is $sp$ hybridised while it is ${sp}^{2}$ in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect

Explanation:

The carbon atoms in ethene is ${sp}^{2}$ hybridised due to
supporting img
t while it is sp in ethyne due to $- C \equiv C -$

Hence, Assertion is correct but Reason is incorrect.

AIIMS - 2007

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound $C H_{2} = C = C H_{2}$ is

1

s p, s p, s p

2

s p^{3}, s p, s p

3

s p^{3}, s p^{2}, s p

4

s p^{2}, s p, s p^{2}

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in $C O_{2}, C H_{4} a n d {C O}_{3}^{2 -}$ respectively is

1

s p^{3}, s p^{2} a n d s p

2

s p^{3}, s p a n d s p^{2}

3

s p, s p^{3} a n d s p^{2}

4

s p^{2}, s p^{3} a n d s p

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise

2 The angle between any two hybrid orbitals is always same

3 Hybrid orbitals always form sigma bonds

4 Only electrons undergo hybridisation and not orbitals.

Explanation:

$π$ bond orbital formation is not explained
by hybridisation

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25

2 67 and 75

3 50 and 75

4 33 and 75

JEE - 2018

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
$C - H$ bond in ethyne is shorter than $C - H$ bonds in ethene.
Reason :
( $R)$ Carbon atom in ethene is $sp$ hybridised while it is ${sp}^{2}$ in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect

Explanation:

The carbon atoms in ethene is ${sp}^{2}$ hybridised due to
supporting img
t while it is sp in ethyne due to $- C \equiv C -$

Hence, Assertion is correct but Reason is incorrect.

AIIMS - 2007

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound $C H_{2} = C = C H_{2}$ is

1

s p, s p, s p

2

s p^{3}, s p, s p

3

s p^{3}, s p^{2}, s p

4

s p^{2}, s p, s p^{2}

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in $C O_{2}, C H_{4} a n d {C O}_{3}^{2 -}$ respectively is

1

s p^{3}, s p^{2} a n d s p

2

s p^{3}, s p a n d s p^{2}

3

s p, s p^{3} a n d s p^{2}

4

s p^{2}, s p^{3} a n d s p

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise

2 The angle between any two hybrid orbitals is always same

3 Hybrid orbitals always form sigma bonds

4 Only electrons undergo hybridisation and not orbitals.

Explanation:

$π$ bond orbital formation is not explained
by hybridisation

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25

2 67 and 75

3 50 and 75

4 33 and 75

JEE - 2018

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
$C - H$ bond in ethyne is shorter than $C - H$ bonds in ethene.
Reason :
( $R)$ Carbon atom in ethene is $sp$ hybridised while it is ${sp}^{2}$ in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect

Explanation:

The carbon atoms in ethene is ${sp}^{2}$ hybridised due to
supporting img
t while it is sp in ethyne due to $- C \equiv C -$

Hence, Assertion is correct but Reason is incorrect.

AIIMS - 2007

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound $C H_{2} = C = C H_{2}$ is

1

s p, s p, s p

2

s p^{3}, s p, s p

3

s p^{3}, s p^{2}, s p

4

s p^{2}, s p, s p^{2}

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in $C O_{2}, C H_{4} a n d {C O}_{3}^{2 -}$ respectively is

1

s p^{3}, s p^{2} a n d s p

2

s p^{3}, s p a n d s p^{2}

3

s p, s p^{3} a n d s p^{2}

4

s p^{2}, s p^{3} a n d s p

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313561 Regarding hybridisation the correct statement is

1 Orbitals of different atoms hybridise

2 The angle between any two hybrid orbitals is always same

3 Hybrid orbitals always form sigma bonds

4 Only electrons undergo hybridisation and not orbitals.

Explanation:

$π$ bond orbital formation is not explained
by hybridisation

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313562 In graphite and diamond, the percentage of p - characters of the hybrid orbitals in hybridization are respectively:

1 33 and 25

2 67 and 75

3 50 and 75

4 33 and 75

JEE - 2018

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313563 Assertion :
$C - H$ bond in ethyne is shorter than $C - H$ bonds in ethene.
Reason :
( $R)$ Carbon atom in ethene is $sp$ hybridised while it is ${sp}^{2}$ in ethyne.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect

Explanation:

The carbon atoms in ethene is ${sp}^{2}$ hybridised due to
supporting img
t while it is sp in ethyne due to $- C \equiv C -$

Hence, Assertion is correct but Reason is incorrect.

AIIMS - 2007

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313564 The correct order of hybridisation in a sequence of carbons in the given compound $C H_{2} = C = C H_{2}$ is

1

s p, s p, s p

2

s p^{3}, s p, s p

3

s p^{3}, s p^{2}, s p

4

s p^{2}, s p, s p^{2}

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313565 The state of hybrid orbitals of carbon in $C O_{2}, C H_{4} a n d {C O}_{3}^{2 -}$ respectively is

1

s p^{3}, s p^{2} a n d s p

2

s p^{3}, s p a n d s p^{2}

3

s p, s p^{3} a n d s p^{2}

4

s p^{2}, s p^{3} a n d s p

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