313474
The bond length of the \(\mathrm{S}-\mathrm{O}\) bond is maximum in which of the following compound? \(\mathrm{SOBr}_{2}, \mathrm{SOCl}_{2}, \mathrm{SOF}_{2}\)
1 \(\mathrm{SOCl}_{2}\)
2 \(\mathrm{SOBr}_{2}\)
3 \(\mathrm{SOF}_{2}\)
4 All have same length
Explanation:
In \(\mathrm{SOBr}_{2}, \mathrm{~S}-\mathrm{O}\) bond has maximum bond length in comparison to \(\mathrm{S}-\mathrm{O}\) bond lengths in \(\mathrm{SOF}_{2}\) and \(\mathrm{SOCl}_{2}\), because in \(\mathrm{SOBr}_{2}\), S-O bond has been formed by hybrid orbital containing less s-character.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313475
The correct order in which the \({\rm{O}}\, - \,{\rm{O}}\) bond length increases in the following:
In \({{\rm{O}}_{\rm{2}}}\), double bond is present between O and O. In \({{\rm{O}}_{\rm{3}}}\), partial double bond is present between O and O In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\), single bond present between O and O.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313476
Which of the following bonds has maximum bond length?
1 C – O
2 C – H
3 C – C
4 C – N
Explanation:
Since, C – H bond have less difference in their electronegatives as compared to C – O, C – C and C – N bonds. This results in less polarity of C – H bond and thus, have maximum bond length.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313477
Which of the following is correct order of bond length?
1 \(\mathrm{BF}_{4}^{-} < \mathrm{BF}_{3}\)
2 \(\mathrm{NO}_{2}^{+} < \mathrm{NO}_{2}^{-}\)
3 \(\mathrm{CCl}_{4} < \mathrm{CF}_{4}\)
4 \({ }^{+} \mathrm{CH}_{3}>\mathrm{CH}_{4}\)
Explanation:
\(\mathrm{O}=\stackrel{\oplus}{\mathrm{N}}=\mathrm{O} \quad\) Bond order \(=2\) \(\mathrm{NO}_{2}^{-}\)Bond order \(=1.5\) Bond order \(\alpha \dfrac{1}{\text { bond length }}\)
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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313474
The bond length of the \(\mathrm{S}-\mathrm{O}\) bond is maximum in which of the following compound? \(\mathrm{SOBr}_{2}, \mathrm{SOCl}_{2}, \mathrm{SOF}_{2}\)
1 \(\mathrm{SOCl}_{2}\)
2 \(\mathrm{SOBr}_{2}\)
3 \(\mathrm{SOF}_{2}\)
4 All have same length
Explanation:
In \(\mathrm{SOBr}_{2}, \mathrm{~S}-\mathrm{O}\) bond has maximum bond length in comparison to \(\mathrm{S}-\mathrm{O}\) bond lengths in \(\mathrm{SOF}_{2}\) and \(\mathrm{SOCl}_{2}\), because in \(\mathrm{SOBr}_{2}\), S-O bond has been formed by hybrid orbital containing less s-character.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313475
The correct order in which the \({\rm{O}}\, - \,{\rm{O}}\) bond length increases in the following:
In \({{\rm{O}}_{\rm{2}}}\), double bond is present between O and O. In \({{\rm{O}}_{\rm{3}}}\), partial double bond is present between O and O In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\), single bond present between O and O.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313476
Which of the following bonds has maximum bond length?
1 C – O
2 C – H
3 C – C
4 C – N
Explanation:
Since, C – H bond have less difference in their electronegatives as compared to C – O, C – C and C – N bonds. This results in less polarity of C – H bond and thus, have maximum bond length.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313477
Which of the following is correct order of bond length?
1 \(\mathrm{BF}_{4}^{-} < \mathrm{BF}_{3}\)
2 \(\mathrm{NO}_{2}^{+} < \mathrm{NO}_{2}^{-}\)
3 \(\mathrm{CCl}_{4} < \mathrm{CF}_{4}\)
4 \({ }^{+} \mathrm{CH}_{3}>\mathrm{CH}_{4}\)
Explanation:
\(\mathrm{O}=\stackrel{\oplus}{\mathrm{N}}=\mathrm{O} \quad\) Bond order \(=2\) \(\mathrm{NO}_{2}^{-}\)Bond order \(=1.5\) Bond order \(\alpha \dfrac{1}{\text { bond length }}\)
313474
The bond length of the \(\mathrm{S}-\mathrm{O}\) bond is maximum in which of the following compound? \(\mathrm{SOBr}_{2}, \mathrm{SOCl}_{2}, \mathrm{SOF}_{2}\)
1 \(\mathrm{SOCl}_{2}\)
2 \(\mathrm{SOBr}_{2}\)
3 \(\mathrm{SOF}_{2}\)
4 All have same length
Explanation:
In \(\mathrm{SOBr}_{2}, \mathrm{~S}-\mathrm{O}\) bond has maximum bond length in comparison to \(\mathrm{S}-\mathrm{O}\) bond lengths in \(\mathrm{SOF}_{2}\) and \(\mathrm{SOCl}_{2}\), because in \(\mathrm{SOBr}_{2}\), S-O bond has been formed by hybrid orbital containing less s-character.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313475
The correct order in which the \({\rm{O}}\, - \,{\rm{O}}\) bond length increases in the following:
In \({{\rm{O}}_{\rm{2}}}\), double bond is present between O and O. In \({{\rm{O}}_{\rm{3}}}\), partial double bond is present between O and O In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\), single bond present between O and O.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313476
Which of the following bonds has maximum bond length?
1 C – O
2 C – H
3 C – C
4 C – N
Explanation:
Since, C – H bond have less difference in their electronegatives as compared to C – O, C – C and C – N bonds. This results in less polarity of C – H bond and thus, have maximum bond length.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313477
Which of the following is correct order of bond length?
1 \(\mathrm{BF}_{4}^{-} < \mathrm{BF}_{3}\)
2 \(\mathrm{NO}_{2}^{+} < \mathrm{NO}_{2}^{-}\)
3 \(\mathrm{CCl}_{4} < \mathrm{CF}_{4}\)
4 \({ }^{+} \mathrm{CH}_{3}>\mathrm{CH}_{4}\)
Explanation:
\(\mathrm{O}=\stackrel{\oplus}{\mathrm{N}}=\mathrm{O} \quad\) Bond order \(=2\) \(\mathrm{NO}_{2}^{-}\)Bond order \(=1.5\) Bond order \(\alpha \dfrac{1}{\text { bond length }}\)
313474
The bond length of the \(\mathrm{S}-\mathrm{O}\) bond is maximum in which of the following compound? \(\mathrm{SOBr}_{2}, \mathrm{SOCl}_{2}, \mathrm{SOF}_{2}\)
1 \(\mathrm{SOCl}_{2}\)
2 \(\mathrm{SOBr}_{2}\)
3 \(\mathrm{SOF}_{2}\)
4 All have same length
Explanation:
In \(\mathrm{SOBr}_{2}, \mathrm{~S}-\mathrm{O}\) bond has maximum bond length in comparison to \(\mathrm{S}-\mathrm{O}\) bond lengths in \(\mathrm{SOF}_{2}\) and \(\mathrm{SOCl}_{2}\), because in \(\mathrm{SOBr}_{2}\), S-O bond has been formed by hybrid orbital containing less s-character.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313475
The correct order in which the \({\rm{O}}\, - \,{\rm{O}}\) bond length increases in the following:
In \({{\rm{O}}_{\rm{2}}}\), double bond is present between O and O. In \({{\rm{O}}_{\rm{3}}}\), partial double bond is present between O and O In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\), single bond present between O and O.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313476
Which of the following bonds has maximum bond length?
1 C – O
2 C – H
3 C – C
4 C – N
Explanation:
Since, C – H bond have less difference in their electronegatives as compared to C – O, C – C and C – N bonds. This results in less polarity of C – H bond and thus, have maximum bond length.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313477
Which of the following is correct order of bond length?
1 \(\mathrm{BF}_{4}^{-} < \mathrm{BF}_{3}\)
2 \(\mathrm{NO}_{2}^{+} < \mathrm{NO}_{2}^{-}\)
3 \(\mathrm{CCl}_{4} < \mathrm{CF}_{4}\)
4 \({ }^{+} \mathrm{CH}_{3}>\mathrm{CH}_{4}\)
Explanation:
\(\mathrm{O}=\stackrel{\oplus}{\mathrm{N}}=\mathrm{O} \quad\) Bond order \(=2\) \(\mathrm{NO}_{2}^{-}\)Bond order \(=1.5\) Bond order \(\alpha \dfrac{1}{\text { bond length }}\)
