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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313474 The bond length of the $S - O$ bond is maximum in which of the following compound?
${SOBr}_{2}, {SOCl}_{2}, {SOF}_{2}$

1

{SOCl}_{2}

2

{SOBr}_{2}

3

{SOF}_{2}

4 All have same length

Explanation:

supporting img
In ${SOBr}_{2}, S - O$ bond has maximum bond length in comparison to $S - O$ bond lengths in ${SOF}_{2}$ and ${SOCl}_{2}$ , because in ${SOBr}_{2}$ , S-O bond has been formed by hybrid orbital containing less s-character.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313475 The correct order in which the $O - O$ bond length increases in the following:

1

H_{2} O_{2} < O_{2} < O_{3}

2

O_{3} < H_{2} O_{2} < O_{2}

3

O_{2} < H_{2} O_{2} < O_{3}

4

O_{2} < O_{3} < H_{2} O_{2}

Explanation:

In $O_{2}$ , double bond is present between O and O.
In $O_{3}$ , partial double bond is present between O and O
In $H_{2} O_{2}$ , single bond present between O and O.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313476 Which of the following bonds has maximum bond length?

1 C – O

2 C – H

3 C – C

4 C – N

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313477 Which of the following is correct order of bond length?

1

{BF}_{4}^{-} < {BF}_{3}

2

{NO}_{2}^{+} < {NO}_{2}^{-}

3

{CCl}_{4} < {CF}_{4}

4

^{+} {CH}_{3} > {CH}_{4}

Explanation:

$O = \overset{\oplus}{N} = O$ Bond order $= 2$
${NO}_{2}^{-}$ Bond order $= 1.5$
Bond order $α \frac{1}{bond length}$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313474 The bond length of the $S - O$ bond is maximum in which of the following compound?
${SOBr}_{2}, {SOCl}_{2}, {SOF}_{2}$

1

{SOCl}_{2}

2

{SOBr}_{2}

3

{SOF}_{2}

4 All have same length

Explanation:

supporting img
In ${SOBr}_{2}, S - O$ bond has maximum bond length in comparison to $S - O$ bond lengths in ${SOF}_{2}$ and ${SOCl}_{2}$ , because in ${SOBr}_{2}$ , S-O bond has been formed by hybrid orbital containing less s-character.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313475 The correct order in which the $O - O$ bond length increases in the following:

1

H_{2} O_{2} < O_{2} < O_{3}

2

O_{3} < H_{2} O_{2} < O_{2}

3

O_{2} < H_{2} O_{2} < O_{3}

4

O_{2} < O_{3} < H_{2} O_{2}

Explanation:

In $O_{2}$ , double bond is present between O and O.
In $O_{3}$ , partial double bond is present between O and O
In $H_{2} O_{2}$ , single bond present between O and O.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313476 Which of the following bonds has maximum bond length?

1 C – O

2 C – H

3 C – C

4 C – N

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313477 Which of the following is correct order of bond length?

1

{BF}_{4}^{-} < {BF}_{3}

2

{NO}_{2}^{+} < {NO}_{2}^{-}

3

{CCl}_{4} < {CF}_{4}

4

^{+} {CH}_{3} > {CH}_{4}

Explanation:

$O = \overset{\oplus}{N} = O$ Bond order $= 2$
${NO}_{2}^{-}$ Bond order $= 1.5$
Bond order $α \frac{1}{bond length}$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313474 The bond length of the $S - O$ bond is maximum in which of the following compound?
${SOBr}_{2}, {SOCl}_{2}, {SOF}_{2}$

1

{SOCl}_{2}

2

{SOBr}_{2}

3

{SOF}_{2}

4 All have same length

Explanation:

supporting img
In ${SOBr}_{2}, S - O$ bond has maximum bond length in comparison to $S - O$ bond lengths in ${SOF}_{2}$ and ${SOCl}_{2}$ , because in ${SOBr}_{2}$ , S-O bond has been formed by hybrid orbital containing less s-character.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313475 The correct order in which the $O - O$ bond length increases in the following:

1

H_{2} O_{2} < O_{2} < O_{3}

2

O_{3} < H_{2} O_{2} < O_{2}

3

O_{2} < H_{2} O_{2} < O_{3}

4

O_{2} < O_{3} < H_{2} O_{2}

Explanation:

In $O_{2}$ , double bond is present between O and O.
In $O_{3}$ , partial double bond is present between O and O
In $H_{2} O_{2}$ , single bond present between O and O.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313476 Which of the following bonds has maximum bond length?

1 C – O

2 C – H

3 C – C

4 C – N

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313477 Which of the following is correct order of bond length?

1

{BF}_{4}^{-} < {BF}_{3}

2

{NO}_{2}^{+} < {NO}_{2}^{-}

3

{CCl}_{4} < {CF}_{4}

4

^{+} {CH}_{3} > {CH}_{4}

Explanation:

$O = \overset{\oplus}{N} = O$ Bond order $= 2$
${NO}_{2}^{-}$ Bond order $= 1.5$
Bond order $α \frac{1}{bond length}$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313474 The bond length of the $S - O$ bond is maximum in which of the following compound?
${SOBr}_{2}, {SOCl}_{2}, {SOF}_{2}$

1

{SOCl}_{2}

2

{SOBr}_{2}

3

{SOF}_{2}

4 All have same length

Explanation:

supporting img
In ${SOBr}_{2}, S - O$ bond has maximum bond length in comparison to $S - O$ bond lengths in ${SOF}_{2}$ and ${SOCl}_{2}$ , because in ${SOBr}_{2}$ , S-O bond has been formed by hybrid orbital containing less s-character.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313475 The correct order in which the $O - O$ bond length increases in the following:

1

H_{2} O_{2} < O_{2} < O_{3}

2

O_{3} < H_{2} O_{2} < O_{2}

3

O_{2} < H_{2} O_{2} < O_{3}

4

O_{2} < O_{3} < H_{2} O_{2}

Explanation:

In $O_{2}$ , double bond is present between O and O.
In $O_{3}$ , partial double bond is present between O and O
In $H_{2} O_{2}$ , single bond present between O and O.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313476 Which of the following bonds has maximum bond length?

1 C – O

2 C – H

3 C – C

4 C – N

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313477 Which of the following is correct order of bond length?

1

{BF}_{4}^{-} < {BF}_{3}

2

{NO}_{2}^{+} < {NO}_{2}^{-}

3

{CCl}_{4} < {CF}_{4}

4

^{+} {CH}_{3} > {CH}_{4}

Explanation:

$O = \overset{\oplus}{N} = O$ Bond order $= 2$
${NO}_{2}^{-}$ Bond order $= 1.5$
Bond order $α \frac{1}{bond length}$