307537
The number of radial node/s for \({\mathrm{3 p}}\) orbital is / are
1 3
2 2
3 1
4 4
Explanation:
No. of radial nodes \( = {\rm{n}} - l - 1\) For ' 3 p ' orbital, \({\rm{n = 3}},l{\rm{ = 1}}\) \({\mathrm{\therefore}}\) No. of radial nodes \({\mathrm{=3-1-1=1}}\) So, the correct option is (3).
JEE Main - 2024
CHXI02:STRUCTURE OF ATOM
307538
Assertion : Shapes of the orbitals are represented by boundary surface diagrams of constant probability density. Reason : Boundary surface diagram helps in interpreting and visualizing an atomic orbital.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The boundary surface diagram corresponds to a constant probability density of \({\psi ^{\text{2}}}\). This diagram illustrates the shape of the orbital, which encloses a region or volume where the probability of finding the electron is notably high, typically around \(90 \%\). So option (1) is correct.
CHXI02:STRUCTURE OF ATOM
307540
Each orbital has a nodal plane. Which of the following statements about nodal planes are not true?
1 A plane on which there is zero probability that the electron will be found.
2 A plane on which there is maximum probability that the electron will be found.
3 Both (1) and (2)
4 None of the above
Explanation:
A plane on which there is zero probability that the electron will be found is known as nodal plane.
CHXI02:STRUCTURE OF ATOM
307541
How many spherical nodes are present in a 4s-orbital in hydrogen atom
1 \({\rm{0}}\)
2 \({\rm{1}}\)
3 \({\rm{2}}\)
4 \({\rm{3}}\)
Explanation:
Number of spherical nodes \({\rm{ = n - l - 1}}\) For 4s orbital, number of spherical nodes \({\rm{ = 4 - 0 - 1 = 3}}\)
307537
The number of radial node/s for \({\mathrm{3 p}}\) orbital is / are
1 3
2 2
3 1
4 4
Explanation:
No. of radial nodes \( = {\rm{n}} - l - 1\) For ' 3 p ' orbital, \({\rm{n = 3}},l{\rm{ = 1}}\) \({\mathrm{\therefore}}\) No. of radial nodes \({\mathrm{=3-1-1=1}}\) So, the correct option is (3).
JEE Main - 2024
CHXI02:STRUCTURE OF ATOM
307538
Assertion : Shapes of the orbitals are represented by boundary surface diagrams of constant probability density. Reason : Boundary surface diagram helps in interpreting and visualizing an atomic orbital.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The boundary surface diagram corresponds to a constant probability density of \({\psi ^{\text{2}}}\). This diagram illustrates the shape of the orbital, which encloses a region or volume where the probability of finding the electron is notably high, typically around \(90 \%\). So option (1) is correct.
CHXI02:STRUCTURE OF ATOM
307540
Each orbital has a nodal plane. Which of the following statements about nodal planes are not true?
1 A plane on which there is zero probability that the electron will be found.
2 A plane on which there is maximum probability that the electron will be found.
3 Both (1) and (2)
4 None of the above
Explanation:
A plane on which there is zero probability that the electron will be found is known as nodal plane.
CHXI02:STRUCTURE OF ATOM
307541
How many spherical nodes are present in a 4s-orbital in hydrogen atom
1 \({\rm{0}}\)
2 \({\rm{1}}\)
3 \({\rm{2}}\)
4 \({\rm{3}}\)
Explanation:
Number of spherical nodes \({\rm{ = n - l - 1}}\) For 4s orbital, number of spherical nodes \({\rm{ = 4 - 0 - 1 = 3}}\)
307537
The number of radial node/s for \({\mathrm{3 p}}\) orbital is / are
1 3
2 2
3 1
4 4
Explanation:
No. of radial nodes \( = {\rm{n}} - l - 1\) For ' 3 p ' orbital, \({\rm{n = 3}},l{\rm{ = 1}}\) \({\mathrm{\therefore}}\) No. of radial nodes \({\mathrm{=3-1-1=1}}\) So, the correct option is (3).
JEE Main - 2024
CHXI02:STRUCTURE OF ATOM
307538
Assertion : Shapes of the orbitals are represented by boundary surface diagrams of constant probability density. Reason : Boundary surface diagram helps in interpreting and visualizing an atomic orbital.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The boundary surface diagram corresponds to a constant probability density of \({\psi ^{\text{2}}}\). This diagram illustrates the shape of the orbital, which encloses a region or volume where the probability of finding the electron is notably high, typically around \(90 \%\). So option (1) is correct.
CHXI02:STRUCTURE OF ATOM
307540
Each orbital has a nodal plane. Which of the following statements about nodal planes are not true?
1 A plane on which there is zero probability that the electron will be found.
2 A plane on which there is maximum probability that the electron will be found.
3 Both (1) and (2)
4 None of the above
Explanation:
A plane on which there is zero probability that the electron will be found is known as nodal plane.
CHXI02:STRUCTURE OF ATOM
307541
How many spherical nodes are present in a 4s-orbital in hydrogen atom
1 \({\rm{0}}\)
2 \({\rm{1}}\)
3 \({\rm{2}}\)
4 \({\rm{3}}\)
Explanation:
Number of spherical nodes \({\rm{ = n - l - 1}}\) For 4s orbital, number of spherical nodes \({\rm{ = 4 - 0 - 1 = 3}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI02:STRUCTURE OF ATOM
307537
The number of radial node/s for \({\mathrm{3 p}}\) orbital is / are
1 3
2 2
3 1
4 4
Explanation:
No. of radial nodes \( = {\rm{n}} - l - 1\) For ' 3 p ' orbital, \({\rm{n = 3}},l{\rm{ = 1}}\) \({\mathrm{\therefore}}\) No. of radial nodes \({\mathrm{=3-1-1=1}}\) So, the correct option is (3).
JEE Main - 2024
CHXI02:STRUCTURE OF ATOM
307538
Assertion : Shapes of the orbitals are represented by boundary surface diagrams of constant probability density. Reason : Boundary surface diagram helps in interpreting and visualizing an atomic orbital.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
The boundary surface diagram corresponds to a constant probability density of \({\psi ^{\text{2}}}\). This diagram illustrates the shape of the orbital, which encloses a region or volume where the probability of finding the electron is notably high, typically around \(90 \%\). So option (1) is correct.
CHXI02:STRUCTURE OF ATOM
307540
Each orbital has a nodal plane. Which of the following statements about nodal planes are not true?
1 A plane on which there is zero probability that the electron will be found.
2 A plane on which there is maximum probability that the electron will be found.
3 Both (1) and (2)
4 None of the above
Explanation:
A plane on which there is zero probability that the electron will be found is known as nodal plane.
CHXI02:STRUCTURE OF ATOM
307541
How many spherical nodes are present in a 4s-orbital in hydrogen atom
1 \({\rm{0}}\)
2 \({\rm{1}}\)
3 \({\rm{2}}\)
4 \({\rm{3}}\)
Explanation:
Number of spherical nodes \({\rm{ = n - l - 1}}\) For 4s orbital, number of spherical nodes \({\rm{ = 4 - 0 - 1 = 3}}\)
