307294
Assertion : The free gaseous \(\mathrm{Cr}\) atom has six unpaired electrons. Reason : Half-filled s-orbital has greater stability.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chromium's electron configuration deviates from the expected order, with one electron moving from the \(4 \mathrm{~s}\) to the \(3 \mathrm{~d}\) orbital \(\left(3 \mathrm{~d}^{5} 4 \mathrm{~s}^{1}\right)\), prioritizing the stability associated with a fullyfilled s-orbital, showcasing an exception to the typical energy-based filling order. So option (3) is correct.
CHXI02:STRUCTURE OF ATOM
307295
Magnetic moments of \({\rm{V(Z = 23),Cr(Z = 24),Mn(Z = 25)}}\) are x, y, z. Hence
1 \({\rm{x = y = z}}\)
2 \({\rm{x < y < z}}\)
3 \({\rm{x < z < y}}\)
4 \({\rm{z < y < x}}\)
Explanation:
More number of unpaired electrons, more is the magnetic moment value. Number of unpaired electrons in, \({\rm{V = 3,}}\,{\rm{Cr = 6,}}\,{\rm{Mn = 5}}\)
CHXI02:STRUCTURE OF ATOM
307311
How many d-electrons in \({\rm{C}}{{\rm{u}}^{\rm{ + }}}\)(At.no.=29) can have the spin quantum number \(\left( {{\rm{ - }}\frac{{\rm{1}}}{{\rm{2}}}} \right)\) ?
1 \({\rm{3}}\)
2 \({\rm{7}}\)
3 \({\rm{5}}\)
4 \({\rm{9}}\)
Explanation:
It has \({\rm{3}}{{\rm{d}}^{{\rm{10}}}}\) configuration
CHXI02:STRUCTURE OF ATOM
307298
The correct order of spin only magnetic moment (in BM) of \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{,C}}{{\rm{r}}^{{\rm{2 + }}}}\) and \({{\rm{V}}^{{\rm{2 + }}}}\) is
Magnetic momentum \({\rm{ = }}\sqrt {{\rm{n}}\left( {{\rm{n + 2}}} \right)} \,{\rm{B}}{\rm{.M}}\) Where, n is number of unpaired electrons. From above relation we can say that, Magnetic moment \( \propto \) Number of unpaired electrons. Number of unpaired electrons in, \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{5}}}\) is \({\rm{C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{4}}}\) is 4 \({{\rm{V}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{3}}}\) is 3 Hence, the order is \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{ > C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{ > }}{{\rm{V}}^{{\rm{2 + }}}}.\)
CHXI02:STRUCTURE OF ATOM
307299
The correct set of four quantum numbers for outermost electron of potassium \({\rm{(Z = 19)}}\) is
1 \({\rm{3,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
2 \({\rm{4,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
3 \({\rm{3,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
4 \({\rm{4,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
Explanation:
The electronic configuration of \({\rm{K(Z = 19)}}\) is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}{\rm{.}}\) Thus, the outermost configuration is \({\rm{4}}{{\rm{s}}^{\rm{1}}}\), the four quantum numbers for this \({{\rm{e}}^{\rm{ - }}}\) are : \({\rm{n = 4,l = 0,m = 0}}\) and \({\rm{s = 1/2}}\)
307294
Assertion : The free gaseous \(\mathrm{Cr}\) atom has six unpaired electrons. Reason : Half-filled s-orbital has greater stability.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chromium's electron configuration deviates from the expected order, with one electron moving from the \(4 \mathrm{~s}\) to the \(3 \mathrm{~d}\) orbital \(\left(3 \mathrm{~d}^{5} 4 \mathrm{~s}^{1}\right)\), prioritizing the stability associated with a fullyfilled s-orbital, showcasing an exception to the typical energy-based filling order. So option (3) is correct.
CHXI02:STRUCTURE OF ATOM
307295
Magnetic moments of \({\rm{V(Z = 23),Cr(Z = 24),Mn(Z = 25)}}\) are x, y, z. Hence
1 \({\rm{x = y = z}}\)
2 \({\rm{x < y < z}}\)
3 \({\rm{x < z < y}}\)
4 \({\rm{z < y < x}}\)
Explanation:
More number of unpaired electrons, more is the magnetic moment value. Number of unpaired electrons in, \({\rm{V = 3,}}\,{\rm{Cr = 6,}}\,{\rm{Mn = 5}}\)
CHXI02:STRUCTURE OF ATOM
307311
How many d-electrons in \({\rm{C}}{{\rm{u}}^{\rm{ + }}}\)(At.no.=29) can have the spin quantum number \(\left( {{\rm{ - }}\frac{{\rm{1}}}{{\rm{2}}}} \right)\) ?
1 \({\rm{3}}\)
2 \({\rm{7}}\)
3 \({\rm{5}}\)
4 \({\rm{9}}\)
Explanation:
It has \({\rm{3}}{{\rm{d}}^{{\rm{10}}}}\) configuration
CHXI02:STRUCTURE OF ATOM
307298
The correct order of spin only magnetic moment (in BM) of \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{,C}}{{\rm{r}}^{{\rm{2 + }}}}\) and \({{\rm{V}}^{{\rm{2 + }}}}\) is
Magnetic momentum \({\rm{ = }}\sqrt {{\rm{n}}\left( {{\rm{n + 2}}} \right)} \,{\rm{B}}{\rm{.M}}\) Where, n is number of unpaired electrons. From above relation we can say that, Magnetic moment \( \propto \) Number of unpaired electrons. Number of unpaired electrons in, \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{5}}}\) is \({\rm{C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{4}}}\) is 4 \({{\rm{V}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{3}}}\) is 3 Hence, the order is \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{ > C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{ > }}{{\rm{V}}^{{\rm{2 + }}}}.\)
CHXI02:STRUCTURE OF ATOM
307299
The correct set of four quantum numbers for outermost electron of potassium \({\rm{(Z = 19)}}\) is
1 \({\rm{3,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
2 \({\rm{4,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
3 \({\rm{3,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
4 \({\rm{4,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
Explanation:
The electronic configuration of \({\rm{K(Z = 19)}}\) is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}{\rm{.}}\) Thus, the outermost configuration is \({\rm{4}}{{\rm{s}}^{\rm{1}}}\), the four quantum numbers for this \({{\rm{e}}^{\rm{ - }}}\) are : \({\rm{n = 4,l = 0,m = 0}}\) and \({\rm{s = 1/2}}\)
307294
Assertion : The free gaseous \(\mathrm{Cr}\) atom has six unpaired electrons. Reason : Half-filled s-orbital has greater stability.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chromium's electron configuration deviates from the expected order, with one electron moving from the \(4 \mathrm{~s}\) to the \(3 \mathrm{~d}\) orbital \(\left(3 \mathrm{~d}^{5} 4 \mathrm{~s}^{1}\right)\), prioritizing the stability associated with a fullyfilled s-orbital, showcasing an exception to the typical energy-based filling order. So option (3) is correct.
CHXI02:STRUCTURE OF ATOM
307295
Magnetic moments of \({\rm{V(Z = 23),Cr(Z = 24),Mn(Z = 25)}}\) are x, y, z. Hence
1 \({\rm{x = y = z}}\)
2 \({\rm{x < y < z}}\)
3 \({\rm{x < z < y}}\)
4 \({\rm{z < y < x}}\)
Explanation:
More number of unpaired electrons, more is the magnetic moment value. Number of unpaired electrons in, \({\rm{V = 3,}}\,{\rm{Cr = 6,}}\,{\rm{Mn = 5}}\)
CHXI02:STRUCTURE OF ATOM
307311
How many d-electrons in \({\rm{C}}{{\rm{u}}^{\rm{ + }}}\)(At.no.=29) can have the spin quantum number \(\left( {{\rm{ - }}\frac{{\rm{1}}}{{\rm{2}}}} \right)\) ?
1 \({\rm{3}}\)
2 \({\rm{7}}\)
3 \({\rm{5}}\)
4 \({\rm{9}}\)
Explanation:
It has \({\rm{3}}{{\rm{d}}^{{\rm{10}}}}\) configuration
CHXI02:STRUCTURE OF ATOM
307298
The correct order of spin only magnetic moment (in BM) of \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{,C}}{{\rm{r}}^{{\rm{2 + }}}}\) and \({{\rm{V}}^{{\rm{2 + }}}}\) is
Magnetic momentum \({\rm{ = }}\sqrt {{\rm{n}}\left( {{\rm{n + 2}}} \right)} \,{\rm{B}}{\rm{.M}}\) Where, n is number of unpaired electrons. From above relation we can say that, Magnetic moment \( \propto \) Number of unpaired electrons. Number of unpaired electrons in, \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{5}}}\) is \({\rm{C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{4}}}\) is 4 \({{\rm{V}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{3}}}\) is 3 Hence, the order is \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{ > C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{ > }}{{\rm{V}}^{{\rm{2 + }}}}.\)
CHXI02:STRUCTURE OF ATOM
307299
The correct set of four quantum numbers for outermost electron of potassium \({\rm{(Z = 19)}}\) is
1 \({\rm{3,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
2 \({\rm{4,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
3 \({\rm{3,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
4 \({\rm{4,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
Explanation:
The electronic configuration of \({\rm{K(Z = 19)}}\) is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}{\rm{.}}\) Thus, the outermost configuration is \({\rm{4}}{{\rm{s}}^{\rm{1}}}\), the four quantum numbers for this \({{\rm{e}}^{\rm{ - }}}\) are : \({\rm{n = 4,l = 0,m = 0}}\) and \({\rm{s = 1/2}}\)
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CHXI02:STRUCTURE OF ATOM
307294
Assertion : The free gaseous \(\mathrm{Cr}\) atom has six unpaired electrons. Reason : Half-filled s-orbital has greater stability.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chromium's electron configuration deviates from the expected order, with one electron moving from the \(4 \mathrm{~s}\) to the \(3 \mathrm{~d}\) orbital \(\left(3 \mathrm{~d}^{5} 4 \mathrm{~s}^{1}\right)\), prioritizing the stability associated with a fullyfilled s-orbital, showcasing an exception to the typical energy-based filling order. So option (3) is correct.
CHXI02:STRUCTURE OF ATOM
307295
Magnetic moments of \({\rm{V(Z = 23),Cr(Z = 24),Mn(Z = 25)}}\) are x, y, z. Hence
1 \({\rm{x = y = z}}\)
2 \({\rm{x < y < z}}\)
3 \({\rm{x < z < y}}\)
4 \({\rm{z < y < x}}\)
Explanation:
More number of unpaired electrons, more is the magnetic moment value. Number of unpaired electrons in, \({\rm{V = 3,}}\,{\rm{Cr = 6,}}\,{\rm{Mn = 5}}\)
CHXI02:STRUCTURE OF ATOM
307311
How many d-electrons in \({\rm{C}}{{\rm{u}}^{\rm{ + }}}\)(At.no.=29) can have the spin quantum number \(\left( {{\rm{ - }}\frac{{\rm{1}}}{{\rm{2}}}} \right)\) ?
1 \({\rm{3}}\)
2 \({\rm{7}}\)
3 \({\rm{5}}\)
4 \({\rm{9}}\)
Explanation:
It has \({\rm{3}}{{\rm{d}}^{{\rm{10}}}}\) configuration
CHXI02:STRUCTURE OF ATOM
307298
The correct order of spin only magnetic moment (in BM) of \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{,C}}{{\rm{r}}^{{\rm{2 + }}}}\) and \({{\rm{V}}^{{\rm{2 + }}}}\) is
Magnetic momentum \({\rm{ = }}\sqrt {{\rm{n}}\left( {{\rm{n + 2}}} \right)} \,{\rm{B}}{\rm{.M}}\) Where, n is number of unpaired electrons. From above relation we can say that, Magnetic moment \( \propto \) Number of unpaired electrons. Number of unpaired electrons in, \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{5}}}\) is \({\rm{C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{4}}}\) is 4 \({{\rm{V}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{3}}}\) is 3 Hence, the order is \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{ > C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{ > }}{{\rm{V}}^{{\rm{2 + }}}}.\)
CHXI02:STRUCTURE OF ATOM
307299
The correct set of four quantum numbers for outermost electron of potassium \({\rm{(Z = 19)}}\) is
1 \({\rm{3,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
2 \({\rm{4,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
3 \({\rm{3,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
4 \({\rm{4,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
Explanation:
The electronic configuration of \({\rm{K(Z = 19)}}\) is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}{\rm{.}}\) Thus, the outermost configuration is \({\rm{4}}{{\rm{s}}^{\rm{1}}}\), the four quantum numbers for this \({{\rm{e}}^{\rm{ - }}}\) are : \({\rm{n = 4,l = 0,m = 0}}\) and \({\rm{s = 1/2}}\)
307294
Assertion : The free gaseous \(\mathrm{Cr}\) atom has six unpaired electrons. Reason : Half-filled s-orbital has greater stability.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Chromium's electron configuration deviates from the expected order, with one electron moving from the \(4 \mathrm{~s}\) to the \(3 \mathrm{~d}\) orbital \(\left(3 \mathrm{~d}^{5} 4 \mathrm{~s}^{1}\right)\), prioritizing the stability associated with a fullyfilled s-orbital, showcasing an exception to the typical energy-based filling order. So option (3) is correct.
CHXI02:STRUCTURE OF ATOM
307295
Magnetic moments of \({\rm{V(Z = 23),Cr(Z = 24),Mn(Z = 25)}}\) are x, y, z. Hence
1 \({\rm{x = y = z}}\)
2 \({\rm{x < y < z}}\)
3 \({\rm{x < z < y}}\)
4 \({\rm{z < y < x}}\)
Explanation:
More number of unpaired electrons, more is the magnetic moment value. Number of unpaired electrons in, \({\rm{V = 3,}}\,{\rm{Cr = 6,}}\,{\rm{Mn = 5}}\)
CHXI02:STRUCTURE OF ATOM
307311
How many d-electrons in \({\rm{C}}{{\rm{u}}^{\rm{ + }}}\)(At.no.=29) can have the spin quantum number \(\left( {{\rm{ - }}\frac{{\rm{1}}}{{\rm{2}}}} \right)\) ?
1 \({\rm{3}}\)
2 \({\rm{7}}\)
3 \({\rm{5}}\)
4 \({\rm{9}}\)
Explanation:
It has \({\rm{3}}{{\rm{d}}^{{\rm{10}}}}\) configuration
CHXI02:STRUCTURE OF ATOM
307298
The correct order of spin only magnetic moment (in BM) of \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{,C}}{{\rm{r}}^{{\rm{2 + }}}}\) and \({{\rm{V}}^{{\rm{2 + }}}}\) is
Magnetic momentum \({\rm{ = }}\sqrt {{\rm{n}}\left( {{\rm{n + 2}}} \right)} \,{\rm{B}}{\rm{.M}}\) Where, n is number of unpaired electrons. From above relation we can say that, Magnetic moment \( \propto \) Number of unpaired electrons. Number of unpaired electrons in, \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{5}}}\) is \({\rm{C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{4}}}\) is 4 \({{\rm{V}}^{{\rm{2 + }}}}{\rm{:[Ar]3}}{{\rm{d}}^{\rm{3}}}\) is 3 Hence, the order is \({\rm{M}}{{\rm{n}}^{{\rm{2 + }}}}{\rm{ > C}}{{\rm{r}}^{{\rm{2 + }}}}{\rm{ > }}{{\rm{V}}^{{\rm{2 + }}}}.\)
CHXI02:STRUCTURE OF ATOM
307299
The correct set of four quantum numbers for outermost electron of potassium \({\rm{(Z = 19)}}\) is
1 \({\rm{3,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
2 \({\rm{4,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
3 \({\rm{3,0,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
4 \({\rm{4,1,0,}}\frac{{\rm{1}}}{{\rm{2}}}\)
Explanation:
The electronic configuration of \({\rm{K(Z = 19)}}\) is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}{\rm{.}}\) Thus, the outermost configuration is \({\rm{4}}{{\rm{s}}^{\rm{1}}}\), the four quantum numbers for this \({{\rm{e}}^{\rm{ - }}}\) are : \({\rm{n = 4,l = 0,m = 0}}\) and \({\rm{s = 1/2}}\)