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CHXI02:STRUCTURE OF ATOM

307296 The maximum number of electrons in an atom with the following quantum numbers is
$n = 4, l = 3, m_{l} = - 1, m_{s} = + 1 / 2$

1 1

2 2

3 4

4 3

CHXI02:STRUCTURE OF ATOM

307297 The ground state electronic configuration of $F e^{3 +} (Z = 26)$ is

1

[A r] 3 d^{3} s^{2}

2

[A r] 3 d^{6} 4 s^{2}

3

[A r] 3 d^{5}

4

[A r] 3 d^{6}

Explanation:

Atomic number of iron = 26
Number of electrons in $F e^{3 +} = 23$
Electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$ i.e., $[A r] 3 d^{5}$

CHXI02:STRUCTURE OF ATOM

307264 The number of unpaired electrons in ferrous ion is

1 3

2 2

3 4

4 5

Explanation:

Suffix 'ous' with the name of iron shows that it is in +2 oxidation state.
${Fe}^{2 +} = [Ar] 3 d^{6}, 4 s^{0}$ . Its orbital diagram can be represented as,

supporting img

CHXI02:STRUCTURE OF ATOM

307265 Calculate total no. of $e^{-}$ having $m = 0$ in Cr atom

1

12

2

13

3

5

4

24

Explanation:

Chromium electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Number of electrons with $m = 0$ is calculated as follows:
2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons

CHXI02:STRUCTURE OF ATOM

307266 This electronic configuration shows element of
supporting img

1 Oxygen

2 Neon

3 Fluorine

4 Nitrogen

Explanation:

This element has 9 electrons $(1 s^{2} 2 s^{2} 2 p^{5})$ . So, it is the electronic configuration of fluorine.

CHXI02:STRUCTURE OF ATOM

307296 The maximum number of electrons in an atom with the following quantum numbers is
$n = 4, l = 3, m_{l} = - 1, m_{s} = + 1 / 2$

1 1

2 2

3 4

4 3

CHXI02:STRUCTURE OF ATOM

307297 The ground state electronic configuration of $F e^{3 +} (Z = 26)$ is

1

[A r] 3 d^{3} s^{2}

2

[A r] 3 d^{6} 4 s^{2}

3

[A r] 3 d^{5}

4

[A r] 3 d^{6}

Explanation:

Atomic number of iron = 26
Number of electrons in $F e^{3 +} = 23$
Electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$ i.e., $[A r] 3 d^{5}$

CHXI02:STRUCTURE OF ATOM

307264 The number of unpaired electrons in ferrous ion is

1 3

2 2

3 4

4 5

Explanation:

Suffix 'ous' with the name of iron shows that it is in +2 oxidation state.
${Fe}^{2 +} = [Ar] 3 d^{6}, 4 s^{0}$ . Its orbital diagram can be represented as,

supporting img

CHXI02:STRUCTURE OF ATOM

307265 Calculate total no. of $e^{-}$ having $m = 0$ in Cr atom

1

12

2

13

3

5

4

24

Explanation:

Chromium electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Number of electrons with $m = 0$ is calculated as follows:
2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons

CHXI02:STRUCTURE OF ATOM

307266 This electronic configuration shows element of
supporting img

1 Oxygen

2 Neon

3 Fluorine

4 Nitrogen

Explanation:

This element has 9 electrons $(1 s^{2} 2 s^{2} 2 p^{5})$ . So, it is the electronic configuration of fluorine.

CHXI02:STRUCTURE OF ATOM

307296 The maximum number of electrons in an atom with the following quantum numbers is
$n = 4, l = 3, m_{l} = - 1, m_{s} = + 1 / 2$

1 1

2 2

3 4

4 3

CHXI02:STRUCTURE OF ATOM

307297 The ground state electronic configuration of $F e^{3 +} (Z = 26)$ is

1

[A r] 3 d^{3} s^{2}

2

[A r] 3 d^{6} 4 s^{2}

3

[A r] 3 d^{5}

4

[A r] 3 d^{6}

Explanation:

Atomic number of iron = 26
Number of electrons in $F e^{3 +} = 23$
Electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$ i.e., $[A r] 3 d^{5}$

CHXI02:STRUCTURE OF ATOM

307264 The number of unpaired electrons in ferrous ion is

1 3

2 2

3 4

4 5

Explanation:

Suffix 'ous' with the name of iron shows that it is in +2 oxidation state.
${Fe}^{2 +} = [Ar] 3 d^{6}, 4 s^{0}$ . Its orbital diagram can be represented as,

supporting img

CHXI02:STRUCTURE OF ATOM

307265 Calculate total no. of $e^{-}$ having $m = 0$ in Cr atom

1

12

2

13

3

5

4

24

Explanation:

Chromium electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Number of electrons with $m = 0$ is calculated as follows:
2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons

CHXI02:STRUCTURE OF ATOM

307266 This electronic configuration shows element of
supporting img

1 Oxygen

2 Neon

3 Fluorine

4 Nitrogen

Explanation:

This element has 9 electrons $(1 s^{2} 2 s^{2} 2 p^{5})$ . So, it is the electronic configuration of fluorine.

CHXI02:STRUCTURE OF ATOM

307296 The maximum number of electrons in an atom with the following quantum numbers is
$n = 4, l = 3, m_{l} = - 1, m_{s} = + 1 / 2$

1 1

2 2

3 4

4 3

CHXI02:STRUCTURE OF ATOM

307297 The ground state electronic configuration of $F e^{3 +} (Z = 26)$ is

1

[A r] 3 d^{3} s^{2}

2

[A r] 3 d^{6} 4 s^{2}

3

[A r] 3 d^{5}

4

[A r] 3 d^{6}

Explanation:

Atomic number of iron = 26
Number of electrons in $F e^{3 +} = 23$
Electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$ i.e., $[A r] 3 d^{5}$

CHXI02:STRUCTURE OF ATOM

307264 The number of unpaired electrons in ferrous ion is

1 3

2 2

3 4

4 5

Explanation:

Suffix 'ous' with the name of iron shows that it is in +2 oxidation state.
${Fe}^{2 +} = [Ar] 3 d^{6}, 4 s^{0}$ . Its orbital diagram can be represented as,

supporting img

CHXI02:STRUCTURE OF ATOM

307265 Calculate total no. of $e^{-}$ having $m = 0$ in Cr atom

1

12

2

13

3

5

4

24

Explanation:

Chromium electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Number of electrons with $m = 0$ is calculated as follows:
2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons

CHXI02:STRUCTURE OF ATOM

307266 This electronic configuration shows element of
supporting img

1 Oxygen

2 Neon

3 Fluorine

4 Nitrogen

Explanation:

This element has 9 electrons $(1 s^{2} 2 s^{2} 2 p^{5})$ . So, it is the electronic configuration of fluorine.

CHXI02:STRUCTURE OF ATOM

307296 The maximum number of electrons in an atom with the following quantum numbers is
$n = 4, l = 3, m_{l} = - 1, m_{s} = + 1 / 2$

1 1

2 2

3 4

4 3

CHXI02:STRUCTURE OF ATOM

307297 The ground state electronic configuration of $F e^{3 +} (Z = 26)$ is

1

[A r] 3 d^{3} s^{2}

2

[A r] 3 d^{6} 4 s^{2}

3

[A r] 3 d^{5}

4

[A r] 3 d^{6}

Explanation:

Atomic number of iron = 26
Number of electrons in $F e^{3 +} = 23$
Electronic configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$ i.e., $[A r] 3 d^{5}$

CHXI02:STRUCTURE OF ATOM

307264 The number of unpaired electrons in ferrous ion is

1 3

2 2

3 4

4 5

Explanation:

Suffix 'ous' with the name of iron shows that it is in +2 oxidation state.
${Fe}^{2 +} = [Ar] 3 d^{6}, 4 s^{0}$ . Its orbital diagram can be represented as,

supporting img

CHXI02:STRUCTURE OF ATOM

307265 Calculate total no. of $e^{-}$ having $m = 0$ in Cr atom

1

12

2

13

3

5

4

24

Explanation:

Chromium electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Number of electrons with $m = 0$ is calculated as follows:
2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons

CHXI02:STRUCTURE OF ATOM

307266 This electronic configuration shows element of
supporting img

1 Oxygen

2 Neon

3 Fluorine

4 Nitrogen

Explanation:

This element has 9 electrons $(1 s^{2} 2 s^{2} 2 p^{5})$ . So, it is the electronic configuration of fluorine.