307296
The maximum number of electrons in an atom with the following quantum numbers is \({\rm{n = 4}},l{\rm{ = 3}},\;{{\rm{m}}_l}{\rm{ = }} - {\rm{1}},\;{{\rm{m}}_{\rm{s}}}{\rm{ = }}{\mkern 1mu} {\rm{ + 1/2}}\)
1 1
2 2
3 4
4 3
Explanation:
According to the Pauli's exclusion principle, in an atom, no two electrons can have the same four electronic quantum numbers.
CHXI02:STRUCTURE OF ATOM
307297
The ground state electronic configuration of \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{(Z = 26)}}\) is
Atomic number of iron = 26 Number of electrons in \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{ = 23}}\) Electronic configuration \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{0}}}\) i.e., \({\rm{[Ar]3}}{{\rm{d}}^{\rm{5}}}\)
CHXI02:STRUCTURE OF ATOM
307264
The number of unpaired electrons in ferrous ion is
1 3
2 2
3 4
4 5
Explanation:
Suffix 'ous' with the name of iron shows that it is in +2 oxidation state. \(\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{0}\). Its orbital diagram can be represented as,
CHXI02:STRUCTURE OF ATOM
307265
Calculate total no. of \({{\rm{e}}^{\rm{ - }}}\) having \({\rm{m = 0}}\) in Cr atom
1 \({\rm{12}}\)
2 \({\rm{13}}\)
3 \({\rm{5}}\)
4 \({\rm{24}}\)
Explanation:
Chromium electronic configuration is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}\) Number of electrons with \({\rm{m = 0}}\) is calculated as follows: 2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons
CHXI02:STRUCTURE OF ATOM
307266
This electronic configuration shows element of
1 Oxygen
2 Neon
3 Fluorine
4 Nitrogen
Explanation:
This element has 9 electrons \(\left( {{\text{1}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{p}}^{\text{5}}}} \right)\). So, it is the electronic configuration of fluorine.
307296
The maximum number of electrons in an atom with the following quantum numbers is \({\rm{n = 4}},l{\rm{ = 3}},\;{{\rm{m}}_l}{\rm{ = }} - {\rm{1}},\;{{\rm{m}}_{\rm{s}}}{\rm{ = }}{\mkern 1mu} {\rm{ + 1/2}}\)
1 1
2 2
3 4
4 3
Explanation:
According to the Pauli's exclusion principle, in an atom, no two electrons can have the same four electronic quantum numbers.
CHXI02:STRUCTURE OF ATOM
307297
The ground state electronic configuration of \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{(Z = 26)}}\) is
Atomic number of iron = 26 Number of electrons in \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{ = 23}}\) Electronic configuration \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{0}}}\) i.e., \({\rm{[Ar]3}}{{\rm{d}}^{\rm{5}}}\)
CHXI02:STRUCTURE OF ATOM
307264
The number of unpaired electrons in ferrous ion is
1 3
2 2
3 4
4 5
Explanation:
Suffix 'ous' with the name of iron shows that it is in +2 oxidation state. \(\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{0}\). Its orbital diagram can be represented as,
CHXI02:STRUCTURE OF ATOM
307265
Calculate total no. of \({{\rm{e}}^{\rm{ - }}}\) having \({\rm{m = 0}}\) in Cr atom
1 \({\rm{12}}\)
2 \({\rm{13}}\)
3 \({\rm{5}}\)
4 \({\rm{24}}\)
Explanation:
Chromium electronic configuration is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}\) Number of electrons with \({\rm{m = 0}}\) is calculated as follows: 2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons
CHXI02:STRUCTURE OF ATOM
307266
This electronic configuration shows element of
1 Oxygen
2 Neon
3 Fluorine
4 Nitrogen
Explanation:
This element has 9 electrons \(\left( {{\text{1}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{p}}^{\text{5}}}} \right)\). So, it is the electronic configuration of fluorine.
307296
The maximum number of electrons in an atom with the following quantum numbers is \({\rm{n = 4}},l{\rm{ = 3}},\;{{\rm{m}}_l}{\rm{ = }} - {\rm{1}},\;{{\rm{m}}_{\rm{s}}}{\rm{ = }}{\mkern 1mu} {\rm{ + 1/2}}\)
1 1
2 2
3 4
4 3
Explanation:
According to the Pauli's exclusion principle, in an atom, no two electrons can have the same four electronic quantum numbers.
CHXI02:STRUCTURE OF ATOM
307297
The ground state electronic configuration of \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{(Z = 26)}}\) is
Atomic number of iron = 26 Number of electrons in \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{ = 23}}\) Electronic configuration \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{0}}}\) i.e., \({\rm{[Ar]3}}{{\rm{d}}^{\rm{5}}}\)
CHXI02:STRUCTURE OF ATOM
307264
The number of unpaired electrons in ferrous ion is
1 3
2 2
3 4
4 5
Explanation:
Suffix 'ous' with the name of iron shows that it is in +2 oxidation state. \(\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{0}\). Its orbital diagram can be represented as,
CHXI02:STRUCTURE OF ATOM
307265
Calculate total no. of \({{\rm{e}}^{\rm{ - }}}\) having \({\rm{m = 0}}\) in Cr atom
1 \({\rm{12}}\)
2 \({\rm{13}}\)
3 \({\rm{5}}\)
4 \({\rm{24}}\)
Explanation:
Chromium electronic configuration is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}\) Number of electrons with \({\rm{m = 0}}\) is calculated as follows: 2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons
CHXI02:STRUCTURE OF ATOM
307266
This electronic configuration shows element of
1 Oxygen
2 Neon
3 Fluorine
4 Nitrogen
Explanation:
This element has 9 electrons \(\left( {{\text{1}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{p}}^{\text{5}}}} \right)\). So, it is the electronic configuration of fluorine.
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CHXI02:STRUCTURE OF ATOM
307296
The maximum number of electrons in an atom with the following quantum numbers is \({\rm{n = 4}},l{\rm{ = 3}},\;{{\rm{m}}_l}{\rm{ = }} - {\rm{1}},\;{{\rm{m}}_{\rm{s}}}{\rm{ = }}{\mkern 1mu} {\rm{ + 1/2}}\)
1 1
2 2
3 4
4 3
Explanation:
According to the Pauli's exclusion principle, in an atom, no two electrons can have the same four electronic quantum numbers.
CHXI02:STRUCTURE OF ATOM
307297
The ground state electronic configuration of \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{(Z = 26)}}\) is
Atomic number of iron = 26 Number of electrons in \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{ = 23}}\) Electronic configuration \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{0}}}\) i.e., \({\rm{[Ar]3}}{{\rm{d}}^{\rm{5}}}\)
CHXI02:STRUCTURE OF ATOM
307264
The number of unpaired electrons in ferrous ion is
1 3
2 2
3 4
4 5
Explanation:
Suffix 'ous' with the name of iron shows that it is in +2 oxidation state. \(\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{0}\). Its orbital diagram can be represented as,
CHXI02:STRUCTURE OF ATOM
307265
Calculate total no. of \({{\rm{e}}^{\rm{ - }}}\) having \({\rm{m = 0}}\) in Cr atom
1 \({\rm{12}}\)
2 \({\rm{13}}\)
3 \({\rm{5}}\)
4 \({\rm{24}}\)
Explanation:
Chromium electronic configuration is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}\) Number of electrons with \({\rm{m = 0}}\) is calculated as follows: 2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons
CHXI02:STRUCTURE OF ATOM
307266
This electronic configuration shows element of
1 Oxygen
2 Neon
3 Fluorine
4 Nitrogen
Explanation:
This element has 9 electrons \(\left( {{\text{1}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{p}}^{\text{5}}}} \right)\). So, it is the electronic configuration of fluorine.
307296
The maximum number of electrons in an atom with the following quantum numbers is \({\rm{n = 4}},l{\rm{ = 3}},\;{{\rm{m}}_l}{\rm{ = }} - {\rm{1}},\;{{\rm{m}}_{\rm{s}}}{\rm{ = }}{\mkern 1mu} {\rm{ + 1/2}}\)
1 1
2 2
3 4
4 3
Explanation:
According to the Pauli's exclusion principle, in an atom, no two electrons can have the same four electronic quantum numbers.
CHXI02:STRUCTURE OF ATOM
307297
The ground state electronic configuration of \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{(Z = 26)}}\) is
Atomic number of iron = 26 Number of electrons in \({\rm{F}}{{\rm{e}}^{{\rm{3 + }}}}{\rm{ = 23}}\) Electronic configuration \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{0}}}\) i.e., \({\rm{[Ar]3}}{{\rm{d}}^{\rm{5}}}\)
CHXI02:STRUCTURE OF ATOM
307264
The number of unpaired electrons in ferrous ion is
1 3
2 2
3 4
4 5
Explanation:
Suffix 'ous' with the name of iron shows that it is in +2 oxidation state. \(\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{0}\). Its orbital diagram can be represented as,
CHXI02:STRUCTURE OF ATOM
307265
Calculate total no. of \({{\rm{e}}^{\rm{ - }}}\) having \({\rm{m = 0}}\) in Cr atom
1 \({\rm{12}}\)
2 \({\rm{13}}\)
3 \({\rm{5}}\)
4 \({\rm{24}}\)
Explanation:
Chromium electronic configuration is \({\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{6}}}{\rm{3}}{{\rm{d}}^{\rm{5}}}{\rm{4}}{{\rm{s}}^{\rm{1}}}\) Number of electrons with \({\rm{m = 0}}\) is calculated as follows: 2 (from 1s) + 2(from 2s) + 2 (from 2p) + 2 (from 3s) + 2 (from 3p) + 1 (from 3d) + 1 (from 4s) = 12 electrons
CHXI02:STRUCTURE OF ATOM
307266
This electronic configuration shows element of
1 Oxygen
2 Neon
3 Fluorine
4 Nitrogen
Explanation:
This element has 9 electrons \(\left( {{\text{1}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{s}}^{\text{2}}}{\text{ 2}}{{\text{p}}^{\text{5}}}} \right)\). So, it is the electronic configuration of fluorine.
