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CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307026 1 gram of a carbonate \({\rm{(}}{{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{)}}\) on treatment with excess HCl produces 0.01186 mole of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\). The molar mass of \({{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{in}}{\mkern 1mu} {\mkern 1mu} {\rm{g}}{\mkern 1mu} {\mkern 1mu} {\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\) is:

1 1186

2 84.3

3 118.6

4 11.86

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307027 What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

1 2.8 kg

2 6.4 kg

3 9.6 kg

4 96 kg

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307028 When 1.25 gm of a chalk sample \(\left( {{\rm{CaC}}{{\rm{O}}_{\rm{3}}}} \right)\) is strongly heated, 0.44 gm \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) gas is produced. Determine the percentage yield of the reaction.

1 \({\rm{40\% }}\)

2 \({\rm{60\% }}\)

3 \({\rm{80\% }}\)

4 \({\rm{90\% }}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307029 Match Column I with Column II and choose the correct combination from the given options given.
supporting img

1 \({\rm{A}} - {\rm{R}},\,\,\,\,\,\,{\rm{B}} - {\rm{P}},\,\,\,\,\,\,{\rm{C}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

2 \({\rm{A}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{B}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{C}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

3 \({\rm{A}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{B}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{Q}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{D}} - {\rm{S}}\)

4 \({\rm{A}} - {\rm{S}},\,\,\,\,\,\,\,{\rm{B}} - {\rm{P,}}\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{R,}}\,\,\,\,\,\,\,\,{\rm{D}} - {\rm{Q}}\)

Explanation:

\((1)\mathop {2{{\rm{H}}_2}}\limits_{1.0{\rm{g}}} + \mathop {{{\rm{O}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} \to 2{{\rm{H}}_2}{\rm{O}}\)
\(\,\,\,\,\,\,\,\,\frac{1}{2}{\rm{mol}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{{\,32}}\;{\rm{mol}}\)
\({{\text{O}}_2}\) is the limiting reagent :
\(1\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} = 2\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( \Rightarrow \frac{1}{{32}}{\mkern 1mu} {\mkern 1mu} \;{\text{mol}}{\mkern 1mu} \,\,{\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} \equiv \frac{1}{{16}}\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( = \frac{{18}}{{16}}\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}} = 1.125\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}}\)
\((2)\mathop {{{\rm{N}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} + \mathop {3{{\rm{H}}_2}}\limits_{{\rm{1}}{\rm{.0}}{\mkern 1mu} {\rm{g}}} \to 2{\mkern 1mu} {\rm{N}}{{\rm{H}}_3}\)
\(\,\,\,\,\,\,\,\,\frac{1}{{28}}\;\;{\rm{mol}}\;\;\,\,\,\,\,\,\,\,\;\frac{1}{2}\;\;{\rm{mol}}\)
\({{\text{N}}_2}\) is the limiting reagent.
\(\therefore \frac{1}{{28}}\;{\rm{mol}}\;{\mkern 1mu} {{\rm{N}}_{\rm{2}}} \equiv \frac{1}{{14}}\;{\rm{mol}}{\mkern 1mu} {\mkern 1mu} \)
\({\rm{N}}{{\rm{H}}_{\rm{3}}} \equiv \frac{1}{{14}} \times 17\;{\rm{g}} = 1.214{\mkern 1mu} \;{\rm{g}}\)
\((3)\,\,\mathop {{\text{CaC}}{{\text{O}}_{\text{3}}}}\limits_{{\text{1}}{\text{.0}}\,\,{\text{g}}} \xrightarrow{\Delta }\mathop {{\text{CaO}}}\limits_{\text{?}} + {\text{C}}{{\text{O}}_{\text{2}}}\)
\(\frac{1}{{100}}\,\,\,{\text{mol}}\,\,\,\,{\text{CaC}}{{\text{O}}_{\text{3}}}\)
\(\frac{1}{{100}} \times 56\,\,{\text{g}}\,\,{\text{CaO}} = 0.56\,\,{\text{g}}\,\,{\text{CaO}}\)
\((4){\mkern 1mu} {\mkern 1mu} \mathop {\rm{C}}\limits_{1.0{\mkern 1mu} {\rm{g}}} + \mathop {{\rm{2}}{{\rm{H}}_{\rm{2}}}}\limits_{1.0{\mkern 1mu} {\rm{g}}} \to {\rm{C}}{{\rm{H}}_{\rm{4}}}\)
\(\,\,\,\,\,\,\,\frac{1}{{12}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}{\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \frac{1}{2}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}\)
C is the limiting reagent.
\(\therefore \,\,\frac{1}{{12}}\,\,\,\,{\text{mol}}\,\,{\text{C}} \equiv \frac{1}{{12}}\,\,{\text{mol}}\)
\(\,\,{\text{C}}{{\text{H}}_{\text{4}}} \equiv \frac{{16}}{{12}}\,\,\,{\text{g}} = 1.333\,\,{\text{g}}\,\,{\text{C}}{{\text{H}}_{\text{4}}}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307030 A metal oxide has the formula \({{\rm{Z}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\). It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

1 27.9

2 159.6

3 79.8

4 55.8

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307026 1 gram of a carbonate \({\rm{(}}{{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{)}}\) on treatment with excess HCl produces 0.01186 mole of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\). The molar mass of \({{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{in}}{\mkern 1mu} {\mkern 1mu} {\rm{g}}{\mkern 1mu} {\mkern 1mu} {\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\) is:

1 1186

2 84.3

3 118.6

4 11.86

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307027 What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

1 2.8 kg

2 6.4 kg

3 9.6 kg

4 96 kg

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307028 When 1.25 gm of a chalk sample \(\left( {{\rm{CaC}}{{\rm{O}}_{\rm{3}}}} \right)\) is strongly heated, 0.44 gm \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) gas is produced. Determine the percentage yield of the reaction.

1 \({\rm{40\% }}\)

2 \({\rm{60\% }}\)

3 \({\rm{80\% }}\)

4 \({\rm{90\% }}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307029 Match Column I with Column II and choose the correct combination from the given options given.
supporting img

1 \({\rm{A}} - {\rm{R}},\,\,\,\,\,\,{\rm{B}} - {\rm{P}},\,\,\,\,\,\,{\rm{C}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

2 \({\rm{A}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{B}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{C}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

3 \({\rm{A}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{B}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{Q}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{D}} - {\rm{S}}\)

4 \({\rm{A}} - {\rm{S}},\,\,\,\,\,\,\,{\rm{B}} - {\rm{P,}}\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{R,}}\,\,\,\,\,\,\,\,{\rm{D}} - {\rm{Q}}\)

Explanation:

\((1)\mathop {2{{\rm{H}}_2}}\limits_{1.0{\rm{g}}} + \mathop {{{\rm{O}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} \to 2{{\rm{H}}_2}{\rm{O}}\)
\(\,\,\,\,\,\,\,\,\frac{1}{2}{\rm{mol}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{{\,32}}\;{\rm{mol}}\)
\({{\text{O}}_2}\) is the limiting reagent :
\(1\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} = 2\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( \Rightarrow \frac{1}{{32}}{\mkern 1mu} {\mkern 1mu} \;{\text{mol}}{\mkern 1mu} \,\,{\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} \equiv \frac{1}{{16}}\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( = \frac{{18}}{{16}}\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}} = 1.125\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}}\)
\((2)\mathop {{{\rm{N}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} + \mathop {3{{\rm{H}}_2}}\limits_{{\rm{1}}{\rm{.0}}{\mkern 1mu} {\rm{g}}} \to 2{\mkern 1mu} {\rm{N}}{{\rm{H}}_3}\)
\(\,\,\,\,\,\,\,\,\frac{1}{{28}}\;\;{\rm{mol}}\;\;\,\,\,\,\,\,\,\,\;\frac{1}{2}\;\;{\rm{mol}}\)
\({{\text{N}}_2}\) is the limiting reagent.
\(\therefore \frac{1}{{28}}\;{\rm{mol}}\;{\mkern 1mu} {{\rm{N}}_{\rm{2}}} \equiv \frac{1}{{14}}\;{\rm{mol}}{\mkern 1mu} {\mkern 1mu} \)
\({\rm{N}}{{\rm{H}}_{\rm{3}}} \equiv \frac{1}{{14}} \times 17\;{\rm{g}} = 1.214{\mkern 1mu} \;{\rm{g}}\)
\((3)\,\,\mathop {{\text{CaC}}{{\text{O}}_{\text{3}}}}\limits_{{\text{1}}{\text{.0}}\,\,{\text{g}}} \xrightarrow{\Delta }\mathop {{\text{CaO}}}\limits_{\text{?}} + {\text{C}}{{\text{O}}_{\text{2}}}\)
\(\frac{1}{{100}}\,\,\,{\text{mol}}\,\,\,\,{\text{CaC}}{{\text{O}}_{\text{3}}}\)
\(\frac{1}{{100}} \times 56\,\,{\text{g}}\,\,{\text{CaO}} = 0.56\,\,{\text{g}}\,\,{\text{CaO}}\)
\((4){\mkern 1mu} {\mkern 1mu} \mathop {\rm{C}}\limits_{1.0{\mkern 1mu} {\rm{g}}} + \mathop {{\rm{2}}{{\rm{H}}_{\rm{2}}}}\limits_{1.0{\mkern 1mu} {\rm{g}}} \to {\rm{C}}{{\rm{H}}_{\rm{4}}}\)
\(\,\,\,\,\,\,\,\frac{1}{{12}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}{\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \frac{1}{2}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}\)
C is the limiting reagent.
\(\therefore \,\,\frac{1}{{12}}\,\,\,\,{\text{mol}}\,\,{\text{C}} \equiv \frac{1}{{12}}\,\,{\text{mol}}\)
\(\,\,{\text{C}}{{\text{H}}_{\text{4}}} \equiv \frac{{16}}{{12}}\,\,\,{\text{g}} = 1.333\,\,{\text{g}}\,\,{\text{C}}{{\text{H}}_{\text{4}}}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307030 A metal oxide has the formula \({{\rm{Z}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\). It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

1 27.9

2 159.6

3 79.8

4 55.8

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307026 1 gram of a carbonate \({\rm{(}}{{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{)}}\) on treatment with excess HCl produces 0.01186 mole of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\). The molar mass of \({{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{in}}{\mkern 1mu} {\mkern 1mu} {\rm{g}}{\mkern 1mu} {\mkern 1mu} {\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\) is:

1 1186

2 84.3

3 118.6

4 11.86

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307027 What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

1 2.8 kg

2 6.4 kg

3 9.6 kg

4 96 kg

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307028 When 1.25 gm of a chalk sample \(\left( {{\rm{CaC}}{{\rm{O}}_{\rm{3}}}} \right)\) is strongly heated, 0.44 gm \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) gas is produced. Determine the percentage yield of the reaction.

1 \({\rm{40\% }}\)

2 \({\rm{60\% }}\)

3 \({\rm{80\% }}\)

4 \({\rm{90\% }}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307029 Match Column I with Column II and choose the correct combination from the given options given.
supporting img

1 \({\rm{A}} - {\rm{R}},\,\,\,\,\,\,{\rm{B}} - {\rm{P}},\,\,\,\,\,\,{\rm{C}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

2 \({\rm{A}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{B}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{C}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

3 \({\rm{A}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{B}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{Q}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{D}} - {\rm{S}}\)

4 \({\rm{A}} - {\rm{S}},\,\,\,\,\,\,\,{\rm{B}} - {\rm{P,}}\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{R,}}\,\,\,\,\,\,\,\,{\rm{D}} - {\rm{Q}}\)

Explanation:

\((1)\mathop {2{{\rm{H}}_2}}\limits_{1.0{\rm{g}}} + \mathop {{{\rm{O}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} \to 2{{\rm{H}}_2}{\rm{O}}\)
\(\,\,\,\,\,\,\,\,\frac{1}{2}{\rm{mol}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{{\,32}}\;{\rm{mol}}\)
\({{\text{O}}_2}\) is the limiting reagent :
\(1\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} = 2\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( \Rightarrow \frac{1}{{32}}{\mkern 1mu} {\mkern 1mu} \;{\text{mol}}{\mkern 1mu} \,\,{\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} \equiv \frac{1}{{16}}\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( = \frac{{18}}{{16}}\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}} = 1.125\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}}\)
\((2)\mathop {{{\rm{N}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} + \mathop {3{{\rm{H}}_2}}\limits_{{\rm{1}}{\rm{.0}}{\mkern 1mu} {\rm{g}}} \to 2{\mkern 1mu} {\rm{N}}{{\rm{H}}_3}\)
\(\,\,\,\,\,\,\,\,\frac{1}{{28}}\;\;{\rm{mol}}\;\;\,\,\,\,\,\,\,\,\;\frac{1}{2}\;\;{\rm{mol}}\)
\({{\text{N}}_2}\) is the limiting reagent.
\(\therefore \frac{1}{{28}}\;{\rm{mol}}\;{\mkern 1mu} {{\rm{N}}_{\rm{2}}} \equiv \frac{1}{{14}}\;{\rm{mol}}{\mkern 1mu} {\mkern 1mu} \)
\({\rm{N}}{{\rm{H}}_{\rm{3}}} \equiv \frac{1}{{14}} \times 17\;{\rm{g}} = 1.214{\mkern 1mu} \;{\rm{g}}\)
\((3)\,\,\mathop {{\text{CaC}}{{\text{O}}_{\text{3}}}}\limits_{{\text{1}}{\text{.0}}\,\,{\text{g}}} \xrightarrow{\Delta }\mathop {{\text{CaO}}}\limits_{\text{?}} + {\text{C}}{{\text{O}}_{\text{2}}}\)
\(\frac{1}{{100}}\,\,\,{\text{mol}}\,\,\,\,{\text{CaC}}{{\text{O}}_{\text{3}}}\)
\(\frac{1}{{100}} \times 56\,\,{\text{g}}\,\,{\text{CaO}} = 0.56\,\,{\text{g}}\,\,{\text{CaO}}\)
\((4){\mkern 1mu} {\mkern 1mu} \mathop {\rm{C}}\limits_{1.0{\mkern 1mu} {\rm{g}}} + \mathop {{\rm{2}}{{\rm{H}}_{\rm{2}}}}\limits_{1.0{\mkern 1mu} {\rm{g}}} \to {\rm{C}}{{\rm{H}}_{\rm{4}}}\)
\(\,\,\,\,\,\,\,\frac{1}{{12}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}{\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \frac{1}{2}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}\)
C is the limiting reagent.
\(\therefore \,\,\frac{1}{{12}}\,\,\,\,{\text{mol}}\,\,{\text{C}} \equiv \frac{1}{{12}}\,\,{\text{mol}}\)
\(\,\,{\text{C}}{{\text{H}}_{\text{4}}} \equiv \frac{{16}}{{12}}\,\,\,{\text{g}} = 1.333\,\,{\text{g}}\,\,{\text{C}}{{\text{H}}_{\text{4}}}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307030 A metal oxide has the formula \({{\rm{Z}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\). It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

1 27.9

2 159.6

3 79.8

4 55.8

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307026 1 gram of a carbonate \({\rm{(}}{{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{)}}\) on treatment with excess HCl produces 0.01186 mole of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\). The molar mass of \({{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{in}}{\mkern 1mu} {\mkern 1mu} {\rm{g}}{\mkern 1mu} {\mkern 1mu} {\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\) is:

1 1186

2 84.3

3 118.6

4 11.86

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307027 What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

1 2.8 kg

2 6.4 kg

3 9.6 kg

4 96 kg

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307028 When 1.25 gm of a chalk sample \(\left( {{\rm{CaC}}{{\rm{O}}_{\rm{3}}}} \right)\) is strongly heated, 0.44 gm \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) gas is produced. Determine the percentage yield of the reaction.

1 \({\rm{40\% }}\)

2 \({\rm{60\% }}\)

3 \({\rm{80\% }}\)

4 \({\rm{90\% }}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307029 Match Column I with Column II and choose the correct combination from the given options given.
supporting img

1 \({\rm{A}} - {\rm{R}},\,\,\,\,\,\,{\rm{B}} - {\rm{P}},\,\,\,\,\,\,{\rm{C}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

2 \({\rm{A}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{B}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{C}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

3 \({\rm{A}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{B}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{Q}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{D}} - {\rm{S}}\)

4 \({\rm{A}} - {\rm{S}},\,\,\,\,\,\,\,{\rm{B}} - {\rm{P,}}\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{R,}}\,\,\,\,\,\,\,\,{\rm{D}} - {\rm{Q}}\)

Explanation:

\((1)\mathop {2{{\rm{H}}_2}}\limits_{1.0{\rm{g}}} + \mathop {{{\rm{O}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} \to 2{{\rm{H}}_2}{\rm{O}}\)
\(\,\,\,\,\,\,\,\,\frac{1}{2}{\rm{mol}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{{\,32}}\;{\rm{mol}}\)
\({{\text{O}}_2}\) is the limiting reagent :
\(1\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} = 2\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( \Rightarrow \frac{1}{{32}}{\mkern 1mu} {\mkern 1mu} \;{\text{mol}}{\mkern 1mu} \,\,{\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} \equiv \frac{1}{{16}}\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( = \frac{{18}}{{16}}\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}} = 1.125\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}}\)
\((2)\mathop {{{\rm{N}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} + \mathop {3{{\rm{H}}_2}}\limits_{{\rm{1}}{\rm{.0}}{\mkern 1mu} {\rm{g}}} \to 2{\mkern 1mu} {\rm{N}}{{\rm{H}}_3}\)
\(\,\,\,\,\,\,\,\,\frac{1}{{28}}\;\;{\rm{mol}}\;\;\,\,\,\,\,\,\,\,\;\frac{1}{2}\;\;{\rm{mol}}\)
\({{\text{N}}_2}\) is the limiting reagent.
\(\therefore \frac{1}{{28}}\;{\rm{mol}}\;{\mkern 1mu} {{\rm{N}}_{\rm{2}}} \equiv \frac{1}{{14}}\;{\rm{mol}}{\mkern 1mu} {\mkern 1mu} \)
\({\rm{N}}{{\rm{H}}_{\rm{3}}} \equiv \frac{1}{{14}} \times 17\;{\rm{g}} = 1.214{\mkern 1mu} \;{\rm{g}}\)
\((3)\,\,\mathop {{\text{CaC}}{{\text{O}}_{\text{3}}}}\limits_{{\text{1}}{\text{.0}}\,\,{\text{g}}} \xrightarrow{\Delta }\mathop {{\text{CaO}}}\limits_{\text{?}} + {\text{C}}{{\text{O}}_{\text{2}}}\)
\(\frac{1}{{100}}\,\,\,{\text{mol}}\,\,\,\,{\text{CaC}}{{\text{O}}_{\text{3}}}\)
\(\frac{1}{{100}} \times 56\,\,{\text{g}}\,\,{\text{CaO}} = 0.56\,\,{\text{g}}\,\,{\text{CaO}}\)
\((4){\mkern 1mu} {\mkern 1mu} \mathop {\rm{C}}\limits_{1.0{\mkern 1mu} {\rm{g}}} + \mathop {{\rm{2}}{{\rm{H}}_{\rm{2}}}}\limits_{1.0{\mkern 1mu} {\rm{g}}} \to {\rm{C}}{{\rm{H}}_{\rm{4}}}\)
\(\,\,\,\,\,\,\,\frac{1}{{12}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}{\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \frac{1}{2}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}\)
C is the limiting reagent.
\(\therefore \,\,\frac{1}{{12}}\,\,\,\,{\text{mol}}\,\,{\text{C}} \equiv \frac{1}{{12}}\,\,{\text{mol}}\)
\(\,\,{\text{C}}{{\text{H}}_{\text{4}}} \equiv \frac{{16}}{{12}}\,\,\,{\text{g}} = 1.333\,\,{\text{g}}\,\,{\text{C}}{{\text{H}}_{\text{4}}}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307030 A metal oxide has the formula \({{\rm{Z}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\). It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

1 27.9

2 159.6

3 79.8

4 55.8

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307026 1 gram of a carbonate \({\rm{(}}{{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\rm{)}}\) on treatment with excess HCl produces 0.01186 mole of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\). The molar mass of \({{\rm{M}}_{\rm{2}}}{\rm{C}}{{\rm{O}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{in}}{\mkern 1mu} {\mkern 1mu} {\rm{g}}{\mkern 1mu} {\mkern 1mu} {\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\) is:

1 1186

2 84.3

3 118.6

4 11.86

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307027 What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

1 2.8 kg

2 6.4 kg

3 9.6 kg

4 96 kg

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307028 When 1.25 gm of a chalk sample \(\left( {{\rm{CaC}}{{\rm{O}}_{\rm{3}}}} \right)\) is strongly heated, 0.44 gm \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) gas is produced. Determine the percentage yield of the reaction.

1 \({\rm{40\% }}\)

2 \({\rm{60\% }}\)

3 \({\rm{80\% }}\)

4 \({\rm{90\% }}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307029 Match Column I with Column II and choose the correct combination from the given options given.
supporting img

1 \({\rm{A}} - {\rm{R}},\,\,\,\,\,\,{\rm{B}} - {\rm{P}},\,\,\,\,\,\,{\rm{C}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

2 \({\rm{A}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{B}} - {\rm{S}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{C}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,\,{\rm{D}} - {\rm{Q}}\)

3 \({\rm{A}} - {\rm{P}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{B}} - {\rm{R}},\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{Q}},\;\;\;{\mkern 1mu} {\kern 1pt} \,{\rm{D}} - {\rm{S}}\)

4 \({\rm{A}} - {\rm{S}},\,\,\,\,\,\,\,{\rm{B}} - {\rm{P,}}\;\;\;{\mkern 1mu} {\kern 1pt} {\rm{C}} - {\rm{R,}}\,\,\,\,\,\,\,\,{\rm{D}} - {\rm{Q}}\)

Explanation:

\((1)\mathop {2{{\rm{H}}_2}}\limits_{1.0{\rm{g}}} + \mathop {{{\rm{O}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} \to 2{{\rm{H}}_2}{\rm{O}}\)
\(\,\,\,\,\,\,\,\,\frac{1}{2}{\rm{mol}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{{\,32}}\;{\rm{mol}}\)
\({{\text{O}}_2}\) is the limiting reagent :
\(1\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} = 2\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( \Rightarrow \frac{1}{{32}}{\mkern 1mu} {\mkern 1mu} \;{\text{mol}}{\mkern 1mu} \,\,{\mkern 1mu} {\mkern 1mu} {{\text{O}}_2} \equiv \frac{1}{{16}}\;{\text{mol}}{\mkern 1mu} {\mkern 1mu} {{\text{H}}_2}{\text{O}}\)
\( = \frac{{18}}{{16}}\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}} = 1.125\;{\text{g}}\,\,{{\text{H}}_2}{\text{O}}\)
\((2)\mathop {{{\rm{N}}_2}}\limits_{{\rm{1}}{\rm{.0g}}} + \mathop {3{{\rm{H}}_2}}\limits_{{\rm{1}}{\rm{.0}}{\mkern 1mu} {\rm{g}}} \to 2{\mkern 1mu} {\rm{N}}{{\rm{H}}_3}\)
\(\,\,\,\,\,\,\,\,\frac{1}{{28}}\;\;{\rm{mol}}\;\;\,\,\,\,\,\,\,\,\;\frac{1}{2}\;\;{\rm{mol}}\)
\({{\text{N}}_2}\) is the limiting reagent.
\(\therefore \frac{1}{{28}}\;{\rm{mol}}\;{\mkern 1mu} {{\rm{N}}_{\rm{2}}} \equiv \frac{1}{{14}}\;{\rm{mol}}{\mkern 1mu} {\mkern 1mu} \)
\({\rm{N}}{{\rm{H}}_{\rm{3}}} \equiv \frac{1}{{14}} \times 17\;{\rm{g}} = 1.214{\mkern 1mu} \;{\rm{g}}\)
\((3)\,\,\mathop {{\text{CaC}}{{\text{O}}_{\text{3}}}}\limits_{{\text{1}}{\text{.0}}\,\,{\text{g}}} \xrightarrow{\Delta }\mathop {{\text{CaO}}}\limits_{\text{?}} + {\text{C}}{{\text{O}}_{\text{2}}}\)
\(\frac{1}{{100}}\,\,\,{\text{mol}}\,\,\,\,{\text{CaC}}{{\text{O}}_{\text{3}}}\)
\(\frac{1}{{100}} \times 56\,\,{\text{g}}\,\,{\text{CaO}} = 0.56\,\,{\text{g}}\,\,{\text{CaO}}\)
\((4){\mkern 1mu} {\mkern 1mu} \mathop {\rm{C}}\limits_{1.0{\mkern 1mu} {\rm{g}}} + \mathop {{\rm{2}}{{\rm{H}}_{\rm{2}}}}\limits_{1.0{\mkern 1mu} {\rm{g}}} \to {\rm{C}}{{\rm{H}}_{\rm{4}}}\)
\(\,\,\,\,\,\,\,\frac{1}{{12}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}{\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} \frac{1}{2}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\rm{mol}}\)
C is the limiting reagent.
\(\therefore \,\,\frac{1}{{12}}\,\,\,\,{\text{mol}}\,\,{\text{C}} \equiv \frac{1}{{12}}\,\,{\text{mol}}\)
\(\,\,{\text{C}}{{\text{H}}_{\text{4}}} \equiv \frac{{16}}{{12}}\,\,\,{\text{g}} = 1.333\,\,{\text{g}}\,\,{\text{C}}{{\text{H}}_{\text{4}}}\)

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307030 A metal oxide has the formula \({{\rm{Z}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\). It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

1 27.9

2 159.6

3 79.8

4 55.8

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