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CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307022 \(100\;{\rm{mL}}\) of \({\rm{P}}{{\rm{H}}_{\rm{3}}}\) when completely decomposed produced phosphorus and hydrogen. The change in volume of the gas is \(\mathrm{PH}_{3}(\mathrm{~g}) \longrightarrow \mathrm{P}(\mathrm{s})+3 / 2 \mathrm{H}_{2}(\mathrm{~g})\)

1 50 mL increase

2 500 mL decrease

3 900 mL decrease

4 Does not change

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307023 \(\mathrm{3.5 \mathrm{~g}}\) of mixture of \(\mathrm{\mathrm{NaOH}}\) and \(\mathrm{\mathrm{KOH}}\) were dissolved and made up to \(\mathrm{250 \mathrm{~mL} .25 \mathrm{~mL}}\) of this solution were completely neutralised by \(\mathrm{17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\) solution. Then, the percentage of \(\mathrm{\mathrm{KOH}}\) in mixture is

1 80

2 10

3 34

4 56

Explanation:

Suppose the amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{=\mathrm{xg}}\)
\(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-\mathrm{x}) \mathrm{g}}\)
\(\mathrm{25 \mathrm{~mL}}\) of alkali solution \(\mathrm{=17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
or \(\mathrm{250 \mathrm{~mL}}\) of alkali solution \(\mathrm{=170 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
\(\mathrm{1000 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N}) \mathrm{HCl}}\) contains \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{170 \mathrm{~mL}}\) of \(\mathrm{\mathrm{N} / 2 \mathrm{HCl}}\) will contain
\(\mathrm{\dfrac{36.5 \times 170}{1000 \times 2}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) Eq. mass of \(\mathrm{\mathrm{NaOH}=40 \mathrm{geq} \mathrm{mol}^{-1}}\)
and that of \(\mathrm{\mathrm{KOH}=56{\mathrm{~g} \mathrm{eq} \mathrm{mol}^{-1}}^{-1}}\)
\(\mathrm{40 \mathrm{~g}}\) of \(\mathrm{\mathrm{NaOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{\mathrm{xg}}\) of \(\mathrm{\mathrm{NaOH}}\) will require \(\mathrm{\dfrac{36.5 \times \mathrm{x}}{40} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Similarly, \(\mathrm{56 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
(3.5-x) of \(\mathrm{\mathrm{KOH}}\) will require
\(\mathrm{=\dfrac{36.5(3.5-\mathrm{x})}{56} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Thus, \(\mathrm{\dfrac{36.5 \mathrm{x}}{40}+\dfrac{36.5(3.5-\mathrm{x})}{56}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) or \(\mathrm{\mathrm{x}=3.15 \mathrm{~g}}\)
\(\mathrm{=}\) Amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-3.15) \mathrm{g}=0.35 \mathrm{~g}}\)
\(\mathrm{3.5 \mathrm{~g}}\) of the mixture contain \(\mathrm{0.35 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
\(\mathrm{100 \mathrm{~g}}\) of the mixture contain \(\mathrm{=\dfrac{0.35 \mathrm{~g} \times 100}{3.5}}\)
\(\mathrm{=10 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
Hence, \(\mathrm{\%}\) of \(\mathrm{\mathrm{KOH}=10 \%}\)

AIIMS - 2017

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307024 Ethane reacts with oxygen gas to produce \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) and \({{\rm{H}}_{\rm{2}}}{\rm{O}}\). To produce 0.25 mol of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) the mass of ethane required is

1 1.75 g

2 7 g

3 3.75 g

4 2.8 g

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307025 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

1 1 mole

2 2 moles

3 3 moles

4 4 moles

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307022 \(100\;{\rm{mL}}\) of \({\rm{P}}{{\rm{H}}_{\rm{3}}}\) when completely decomposed produced phosphorus and hydrogen. The change in volume of the gas is \(\mathrm{PH}_{3}(\mathrm{~g}) \longrightarrow \mathrm{P}(\mathrm{s})+3 / 2 \mathrm{H}_{2}(\mathrm{~g})\)

1 50 mL increase

2 500 mL decrease

3 900 mL decrease

4 Does not change

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307023 \(\mathrm{3.5 \mathrm{~g}}\) of mixture of \(\mathrm{\mathrm{NaOH}}\) and \(\mathrm{\mathrm{KOH}}\) were dissolved and made up to \(\mathrm{250 \mathrm{~mL} .25 \mathrm{~mL}}\) of this solution were completely neutralised by \(\mathrm{17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\) solution. Then, the percentage of \(\mathrm{\mathrm{KOH}}\) in mixture is

1 80

2 10

3 34

4 56

Explanation:

Suppose the amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{=\mathrm{xg}}\)
\(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-\mathrm{x}) \mathrm{g}}\)
\(\mathrm{25 \mathrm{~mL}}\) of alkali solution \(\mathrm{=17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
or \(\mathrm{250 \mathrm{~mL}}\) of alkali solution \(\mathrm{=170 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
\(\mathrm{1000 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N}) \mathrm{HCl}}\) contains \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{170 \mathrm{~mL}}\) of \(\mathrm{\mathrm{N} / 2 \mathrm{HCl}}\) will contain
\(\mathrm{\dfrac{36.5 \times 170}{1000 \times 2}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) Eq. mass of \(\mathrm{\mathrm{NaOH}=40 \mathrm{geq} \mathrm{mol}^{-1}}\)
and that of \(\mathrm{\mathrm{KOH}=56{\mathrm{~g} \mathrm{eq} \mathrm{mol}^{-1}}^{-1}}\)
\(\mathrm{40 \mathrm{~g}}\) of \(\mathrm{\mathrm{NaOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{\mathrm{xg}}\) of \(\mathrm{\mathrm{NaOH}}\) will require \(\mathrm{\dfrac{36.5 \times \mathrm{x}}{40} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Similarly, \(\mathrm{56 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
(3.5-x) of \(\mathrm{\mathrm{KOH}}\) will require
\(\mathrm{=\dfrac{36.5(3.5-\mathrm{x})}{56} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Thus, \(\mathrm{\dfrac{36.5 \mathrm{x}}{40}+\dfrac{36.5(3.5-\mathrm{x})}{56}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) or \(\mathrm{\mathrm{x}=3.15 \mathrm{~g}}\)
\(\mathrm{=}\) Amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-3.15) \mathrm{g}=0.35 \mathrm{~g}}\)
\(\mathrm{3.5 \mathrm{~g}}\) of the mixture contain \(\mathrm{0.35 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
\(\mathrm{100 \mathrm{~g}}\) of the mixture contain \(\mathrm{=\dfrac{0.35 \mathrm{~g} \times 100}{3.5}}\)
\(\mathrm{=10 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
Hence, \(\mathrm{\%}\) of \(\mathrm{\mathrm{KOH}=10 \%}\)

AIIMS - 2017

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307024 Ethane reacts with oxygen gas to produce \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) and \({{\rm{H}}_{\rm{2}}}{\rm{O}}\). To produce 0.25 mol of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) the mass of ethane required is

1 1.75 g

2 7 g

3 3.75 g

4 2.8 g

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307025 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

1 1 mole

2 2 moles

3 3 moles

4 4 moles

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307022 \(100\;{\rm{mL}}\) of \({\rm{P}}{{\rm{H}}_{\rm{3}}}\) when completely decomposed produced phosphorus and hydrogen. The change in volume of the gas is \(\mathrm{PH}_{3}(\mathrm{~g}) \longrightarrow \mathrm{P}(\mathrm{s})+3 / 2 \mathrm{H}_{2}(\mathrm{~g})\)

1 50 mL increase

2 500 mL decrease

3 900 mL decrease

4 Does not change

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307023 \(\mathrm{3.5 \mathrm{~g}}\) of mixture of \(\mathrm{\mathrm{NaOH}}\) and \(\mathrm{\mathrm{KOH}}\) were dissolved and made up to \(\mathrm{250 \mathrm{~mL} .25 \mathrm{~mL}}\) of this solution were completely neutralised by \(\mathrm{17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\) solution. Then, the percentage of \(\mathrm{\mathrm{KOH}}\) in mixture is

1 80

2 10

3 34

4 56

Explanation:

Suppose the amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{=\mathrm{xg}}\)
\(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-\mathrm{x}) \mathrm{g}}\)
\(\mathrm{25 \mathrm{~mL}}\) of alkali solution \(\mathrm{=17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
or \(\mathrm{250 \mathrm{~mL}}\) of alkali solution \(\mathrm{=170 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
\(\mathrm{1000 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N}) \mathrm{HCl}}\) contains \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{170 \mathrm{~mL}}\) of \(\mathrm{\mathrm{N} / 2 \mathrm{HCl}}\) will contain
\(\mathrm{\dfrac{36.5 \times 170}{1000 \times 2}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) Eq. mass of \(\mathrm{\mathrm{NaOH}=40 \mathrm{geq} \mathrm{mol}^{-1}}\)
and that of \(\mathrm{\mathrm{KOH}=56{\mathrm{~g} \mathrm{eq} \mathrm{mol}^{-1}}^{-1}}\)
\(\mathrm{40 \mathrm{~g}}\) of \(\mathrm{\mathrm{NaOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{\mathrm{xg}}\) of \(\mathrm{\mathrm{NaOH}}\) will require \(\mathrm{\dfrac{36.5 \times \mathrm{x}}{40} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Similarly, \(\mathrm{56 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
(3.5-x) of \(\mathrm{\mathrm{KOH}}\) will require
\(\mathrm{=\dfrac{36.5(3.5-\mathrm{x})}{56} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Thus, \(\mathrm{\dfrac{36.5 \mathrm{x}}{40}+\dfrac{36.5(3.5-\mathrm{x})}{56}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) or \(\mathrm{\mathrm{x}=3.15 \mathrm{~g}}\)
\(\mathrm{=}\) Amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-3.15) \mathrm{g}=0.35 \mathrm{~g}}\)
\(\mathrm{3.5 \mathrm{~g}}\) of the mixture contain \(\mathrm{0.35 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
\(\mathrm{100 \mathrm{~g}}\) of the mixture contain \(\mathrm{=\dfrac{0.35 \mathrm{~g} \times 100}{3.5}}\)
\(\mathrm{=10 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
Hence, \(\mathrm{\%}\) of \(\mathrm{\mathrm{KOH}=10 \%}\)

AIIMS - 2017

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307024 Ethane reacts with oxygen gas to produce \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) and \({{\rm{H}}_{\rm{2}}}{\rm{O}}\). To produce 0.25 mol of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) the mass of ethane required is

1 1.75 g

2 7 g

3 3.75 g

4 2.8 g

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307025 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

1 1 mole

2 2 moles

3 3 moles

4 4 moles

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307022 \(100\;{\rm{mL}}\) of \({\rm{P}}{{\rm{H}}_{\rm{3}}}\) when completely decomposed produced phosphorus and hydrogen. The change in volume of the gas is \(\mathrm{PH}_{3}(\mathrm{~g}) \longrightarrow \mathrm{P}(\mathrm{s})+3 / 2 \mathrm{H}_{2}(\mathrm{~g})\)

1 50 mL increase

2 500 mL decrease

3 900 mL decrease

4 Does not change

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307023 \(\mathrm{3.5 \mathrm{~g}}\) of mixture of \(\mathrm{\mathrm{NaOH}}\) and \(\mathrm{\mathrm{KOH}}\) were dissolved and made up to \(\mathrm{250 \mathrm{~mL} .25 \mathrm{~mL}}\) of this solution were completely neutralised by \(\mathrm{17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\) solution. Then, the percentage of \(\mathrm{\mathrm{KOH}}\) in mixture is

1 80

2 10

3 34

4 56

Explanation:

Suppose the amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{=\mathrm{xg}}\)
\(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-\mathrm{x}) \mathrm{g}}\)
\(\mathrm{25 \mathrm{~mL}}\) of alkali solution \(\mathrm{=17 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
or \(\mathrm{250 \mathrm{~mL}}\) of alkali solution \(\mathrm{=170 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N} / 2) \mathrm{HCl}}\)
\(\mathrm{1000 \mathrm{~mL}}\) of \(\mathrm{(\mathrm{N}) \mathrm{HCl}}\) contains \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{170 \mathrm{~mL}}\) of \(\mathrm{\mathrm{N} / 2 \mathrm{HCl}}\) will contain
\(\mathrm{\dfrac{36.5 \times 170}{1000 \times 2}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) Eq. mass of \(\mathrm{\mathrm{NaOH}=40 \mathrm{geq} \mathrm{mol}^{-1}}\)
and that of \(\mathrm{\mathrm{KOH}=56{\mathrm{~g} \mathrm{eq} \mathrm{mol}^{-1}}^{-1}}\)
\(\mathrm{40 \mathrm{~g}}\) of \(\mathrm{\mathrm{NaOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
\(\mathrm{\mathrm{xg}}\) of \(\mathrm{\mathrm{NaOH}}\) will require \(\mathrm{\dfrac{36.5 \times \mathrm{x}}{40} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Similarly, \(\mathrm{56 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\) require \(\mathrm{36.5 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
(3.5-x) of \(\mathrm{\mathrm{KOH}}\) will require
\(\mathrm{=\dfrac{36.5(3.5-\mathrm{x})}{56} \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\)
Thus, \(\mathrm{\dfrac{36.5 \mathrm{x}}{40}+\dfrac{36.5(3.5-\mathrm{x})}{56}=3.1025 \mathrm{~g}}\) of \(\mathrm{\mathrm{HCl}}\) or \(\mathrm{\mathrm{x}=3.15 \mathrm{~g}}\)
\(\mathrm{=}\) Amount of \(\mathrm{\mathrm{NaOH}}\) in the mixture \(\mathrm{\therefore}\) Amount of \(\mathrm{\mathrm{KOH}=(3.5-3.15) \mathrm{g}=0.35 \mathrm{~g}}\)
\(\mathrm{3.5 \mathrm{~g}}\) of the mixture contain \(\mathrm{0.35 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
\(\mathrm{100 \mathrm{~g}}\) of the mixture contain \(\mathrm{=\dfrac{0.35 \mathrm{~g} \times 100}{3.5}}\)
\(\mathrm{=10 \mathrm{~g}}\) of \(\mathrm{\mathrm{KOH}}\)
Hence, \(\mathrm{\%}\) of \(\mathrm{\mathrm{KOH}=10 \%}\)

AIIMS - 2017

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307024 Ethane reacts with oxygen gas to produce \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) and \({{\rm{H}}_{\rm{2}}}{\rm{O}}\). To produce 0.25 mol of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) the mass of ethane required is

1 1.75 g

2 7 g

3 3.75 g

4 2.8 g

CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY

307025 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

1 1 mole

2 2 moles

3 3 moles

4 4 moles

Explanation:

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