306601
The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). The atomic weight of M is
1 40.3
2 36.3
3 24.3
4 11.3
Explanation:
As the given sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\), its formula would be \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). If m is the atomic weight of M, molecular weight of \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O = m + 32 + 64 + 126 = m + 222}}{\rm{.}}\) Hence, \({\rm{\% }}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{M = }}\frac{{\rm{m}}}{{{\rm{m + 222}}}}{\rm{ \times 100 = 9}}{\rm{.87}}\) (Given) or \({\rm{100m = 9}}{\rm{.87m + 222 \times 9}}{\rm{.87}}\) or \({\rm{90}}{\rm{.13m = 222 \times 9}}{\rm{.87}}{\mkern 1mu} {\mkern 1mu} {\rm{or}}{\mkern 1mu} {\mkern 1mu} {\rm{m = 24}}{\rm{.3}}\).
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306602
\(\mathrm{5.6 \mathrm{~L}}\) of a gas at S.T.P. weighs equal to \(\mathrm{8 \mathrm{~g}}\). The vapour density of gas is
1 32
2 16
3 8
4 40
Explanation:
Mass of \(\mathrm{22.4 \mathrm{~L}}\) gas at S.T.P. \(\mathrm{=\dfrac{8 \times 22.4}{5.6}=}\) \(\mathrm{32 \mathrm{~g}(1}\) mole \(\mathrm{)}\) \(\mathrm{\therefore}\) Mol. mass \(\mathrm{=32 \mathrm{~g} / \mathrm{mole}}\) Vapour density is half of molar mass \(\mathrm{\therefore}\) V.D \(\mathrm{=\dfrac{32}{2}=16}\)
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306603
Molecular mass is defined as the
1 Mass of one atom compared with the mass of one molecule
2 Mass of one atom compared with the mass of one atom of hydrogen
3 Mass of one molecule of any substance compared with the mass of one atom of C-12.
4 None of the above
Explanation:
Conceptual Questions
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306604
Vapour density of a metal chloride is 66. The molecular weight of the metal is
306601
The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). The atomic weight of M is
1 40.3
2 36.3
3 24.3
4 11.3
Explanation:
As the given sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\), its formula would be \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). If m is the atomic weight of M, molecular weight of \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O = m + 32 + 64 + 126 = m + 222}}{\rm{.}}\) Hence, \({\rm{\% }}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{M = }}\frac{{\rm{m}}}{{{\rm{m + 222}}}}{\rm{ \times 100 = 9}}{\rm{.87}}\) (Given) or \({\rm{100m = 9}}{\rm{.87m + 222 \times 9}}{\rm{.87}}\) or \({\rm{90}}{\rm{.13m = 222 \times 9}}{\rm{.87}}{\mkern 1mu} {\mkern 1mu} {\rm{or}}{\mkern 1mu} {\mkern 1mu} {\rm{m = 24}}{\rm{.3}}\).
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306602
\(\mathrm{5.6 \mathrm{~L}}\) of a gas at S.T.P. weighs equal to \(\mathrm{8 \mathrm{~g}}\). The vapour density of gas is
1 32
2 16
3 8
4 40
Explanation:
Mass of \(\mathrm{22.4 \mathrm{~L}}\) gas at S.T.P. \(\mathrm{=\dfrac{8 \times 22.4}{5.6}=}\) \(\mathrm{32 \mathrm{~g}(1}\) mole \(\mathrm{)}\) \(\mathrm{\therefore}\) Mol. mass \(\mathrm{=32 \mathrm{~g} / \mathrm{mole}}\) Vapour density is half of molar mass \(\mathrm{\therefore}\) V.D \(\mathrm{=\dfrac{32}{2}=16}\)
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306603
Molecular mass is defined as the
1 Mass of one atom compared with the mass of one molecule
2 Mass of one atom compared with the mass of one atom of hydrogen
3 Mass of one molecule of any substance compared with the mass of one atom of C-12.
4 None of the above
Explanation:
Conceptual Questions
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306604
Vapour density of a metal chloride is 66. The molecular weight of the metal is
306601
The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). The atomic weight of M is
1 40.3
2 36.3
3 24.3
4 11.3
Explanation:
As the given sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\), its formula would be \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). If m is the atomic weight of M, molecular weight of \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O = m + 32 + 64 + 126 = m + 222}}{\rm{.}}\) Hence, \({\rm{\% }}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{M = }}\frac{{\rm{m}}}{{{\rm{m + 222}}}}{\rm{ \times 100 = 9}}{\rm{.87}}\) (Given) or \({\rm{100m = 9}}{\rm{.87m + 222 \times 9}}{\rm{.87}}\) or \({\rm{90}}{\rm{.13m = 222 \times 9}}{\rm{.87}}{\mkern 1mu} {\mkern 1mu} {\rm{or}}{\mkern 1mu} {\mkern 1mu} {\rm{m = 24}}{\rm{.3}}\).
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306602
\(\mathrm{5.6 \mathrm{~L}}\) of a gas at S.T.P. weighs equal to \(\mathrm{8 \mathrm{~g}}\). The vapour density of gas is
1 32
2 16
3 8
4 40
Explanation:
Mass of \(\mathrm{22.4 \mathrm{~L}}\) gas at S.T.P. \(\mathrm{=\dfrac{8 \times 22.4}{5.6}=}\) \(\mathrm{32 \mathrm{~g}(1}\) mole \(\mathrm{)}\) \(\mathrm{\therefore}\) Mol. mass \(\mathrm{=32 \mathrm{~g} / \mathrm{mole}}\) Vapour density is half of molar mass \(\mathrm{\therefore}\) V.D \(\mathrm{=\dfrac{32}{2}=16}\)
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306603
Molecular mass is defined as the
1 Mass of one atom compared with the mass of one molecule
2 Mass of one atom compared with the mass of one atom of hydrogen
3 Mass of one molecule of any substance compared with the mass of one atom of C-12.
4 None of the above
Explanation:
Conceptual Questions
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306604
Vapour density of a metal chloride is 66. The molecular weight of the metal is
306601
The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). The atomic weight of M is
1 40.3
2 36.3
3 24.3
4 11.3
Explanation:
As the given sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\), its formula would be \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). If m is the atomic weight of M, molecular weight of \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O = m + 32 + 64 + 126 = m + 222}}{\rm{.}}\) Hence, \({\rm{\% }}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{M = }}\frac{{\rm{m}}}{{{\rm{m + 222}}}}{\rm{ \times 100 = 9}}{\rm{.87}}\) (Given) or \({\rm{100m = 9}}{\rm{.87m + 222 \times 9}}{\rm{.87}}\) or \({\rm{90}}{\rm{.13m = 222 \times 9}}{\rm{.87}}{\mkern 1mu} {\mkern 1mu} {\rm{or}}{\mkern 1mu} {\mkern 1mu} {\rm{m = 24}}{\rm{.3}}\).
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306602
\(\mathrm{5.6 \mathrm{~L}}\) of a gas at S.T.P. weighs equal to \(\mathrm{8 \mathrm{~g}}\). The vapour density of gas is
1 32
2 16
3 8
4 40
Explanation:
Mass of \(\mathrm{22.4 \mathrm{~L}}\) gas at S.T.P. \(\mathrm{=\dfrac{8 \times 22.4}{5.6}=}\) \(\mathrm{32 \mathrm{~g}(1}\) mole \(\mathrm{)}\) \(\mathrm{\therefore}\) Mol. mass \(\mathrm{=32 \mathrm{~g} / \mathrm{mole}}\) Vapour density is half of molar mass \(\mathrm{\therefore}\) V.D \(\mathrm{=\dfrac{32}{2}=16}\)
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306603
Molecular mass is defined as the
1 Mass of one atom compared with the mass of one molecule
2 Mass of one atom compared with the mass of one atom of hydrogen
3 Mass of one molecule of any substance compared with the mass of one atom of C-12.
4 None of the above
Explanation:
Conceptual Questions
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306604
Vapour density of a metal chloride is 66. The molecular weight of the metal is
306601
The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). The atomic weight of M is
1 40.3
2 36.3
3 24.3
4 11.3
Explanation:
As the given sulphate is isomorphous with \({\rm{ZnS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\), its formula would be \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\). If m is the atomic weight of M, molecular weight of \({\rm{MS}}{{\rm{O}}_{\rm{4}}}{\rm{.7}}{{\rm{H}}_{\rm{2}}}{\rm{O = m + 32 + 64 + 126 = m + 222}}{\rm{.}}\) Hence, \({\rm{\% }}{\mkern 1mu} {\mkern 1mu} {\rm{of}}{\mkern 1mu} {\mkern 1mu} {\rm{M = }}\frac{{\rm{m}}}{{{\rm{m + 222}}}}{\rm{ \times 100 = 9}}{\rm{.87}}\) (Given) or \({\rm{100m = 9}}{\rm{.87m + 222 \times 9}}{\rm{.87}}\) or \({\rm{90}}{\rm{.13m = 222 \times 9}}{\rm{.87}}{\mkern 1mu} {\mkern 1mu} {\rm{or}}{\mkern 1mu} {\mkern 1mu} {\rm{m = 24}}{\rm{.3}}\).
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306602
\(\mathrm{5.6 \mathrm{~L}}\) of a gas at S.T.P. weighs equal to \(\mathrm{8 \mathrm{~g}}\). The vapour density of gas is
1 32
2 16
3 8
4 40
Explanation:
Mass of \(\mathrm{22.4 \mathrm{~L}}\) gas at S.T.P. \(\mathrm{=\dfrac{8 \times 22.4}{5.6}=}\) \(\mathrm{32 \mathrm{~g}(1}\) mole \(\mathrm{)}\) \(\mathrm{\therefore}\) Mol. mass \(\mathrm{=32 \mathrm{~g} / \mathrm{mole}}\) Vapour density is half of molar mass \(\mathrm{\therefore}\) V.D \(\mathrm{=\dfrac{32}{2}=16}\)
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306603
Molecular mass is defined as the
1 Mass of one atom compared with the mass of one molecule
2 Mass of one atom compared with the mass of one atom of hydrogen
3 Mass of one molecule of any substance compared with the mass of one atom of C-12.
4 None of the above
Explanation:
Conceptual Questions
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
306604
Vapour density of a metal chloride is 66. The molecular weight of the metal is