306596 Assertion :
1 amu equals to \(1.66 \times 10^{-24} \mathrm{~g}\).
Reason :
\(1.66 \times 10^{-24} \mathrm{~g}\). equals to \(\dfrac{1}{12}\) th of mass of a C-12 atom.

306597 Naturally occurring chlorine is 75.53% \({\rm{C}}{{\rm{l}}^{{\rm{35}}}}\) which has an atomic mass of 34.969 amu and 24.47% \({\rm{C}}{{\rm{l}}^{{\rm{37}}}}\) which has a mass of 36.969 amu. Calculate the average atomic mass of chlorine.

306598 The vapour density of gas \(\rm{{\text{A}}}\) is four times that of \(\rm{{\text{B}}}\). If molecular mass of \(\rm{{\text{B}}}\) is \(\rm{{\text{M}}}\), then molecular mass of \(\mathrm{\mathrm{A}}\) is

306599 A mixture of gas "X" (mol. wt. 16) and gas “Y” (mol. wt. 28) in the mole ratio a : b has a mean molecular weight 20. What would be mean molecular weight if the gases are mixed in the ratio b : a under identical conditions (gases are non reacting)?

306596 Assertion :
1 amu equals to \(1.66 \times 10^{-24} \mathrm{~g}\).
Reason :
\(1.66 \times 10^{-24} \mathrm{~g}\). equals to \(\dfrac{1}{12}\) th of mass of a C-12 atom.

306597 Naturally occurring chlorine is 75.53% \({\rm{C}}{{\rm{l}}^{{\rm{35}}}}\) which has an atomic mass of 34.969 amu and 24.47% \({\rm{C}}{{\rm{l}}^{{\rm{37}}}}\) which has a mass of 36.969 amu. Calculate the average atomic mass of chlorine.

306598 The vapour density of gas \(\rm{{\text{A}}}\) is four times that of \(\rm{{\text{B}}}\). If molecular mass of \(\rm{{\text{B}}}\) is \(\rm{{\text{M}}}\), then molecular mass of \(\mathrm{\mathrm{A}}\) is

306599 A mixture of gas "X" (mol. wt. 16) and gas “Y” (mol. wt. 28) in the mole ratio a : b has a mean molecular weight 20. What would be mean molecular weight if the gases are mixed in the ratio b : a under identical conditions (gases are non reacting)?

306596 Assertion :
1 amu equals to \(1.66 \times 10^{-24} \mathrm{~g}\).
Reason :
\(1.66 \times 10^{-24} \mathrm{~g}\). equals to \(\dfrac{1}{12}\) th of mass of a C-12 atom.

306597 Naturally occurring chlorine is 75.53% \({\rm{C}}{{\rm{l}}^{{\rm{35}}}}\) which has an atomic mass of 34.969 amu and 24.47% \({\rm{C}}{{\rm{l}}^{{\rm{37}}}}\) which has a mass of 36.969 amu. Calculate the average atomic mass of chlorine.

306598 The vapour density of gas \(\rm{{\text{A}}}\) is four times that of \(\rm{{\text{B}}}\). If molecular mass of \(\rm{{\text{B}}}\) is \(\rm{{\text{M}}}\), then molecular mass of \(\mathrm{\mathrm{A}}\) is

306599 A mixture of gas "X" (mol. wt. 16) and gas “Y” (mol. wt. 28) in the mole ratio a : b has a mean molecular weight 20. What would be mean molecular weight if the gases are mixed in the ratio b : a under identical conditions (gases are non reacting)?

306596 Assertion :
1 amu equals to \(1.66 \times 10^{-24} \mathrm{~g}\).
Reason :
\(1.66 \times 10^{-24} \mathrm{~g}\). equals to \(\dfrac{1}{12}\) th of mass of a C-12 atom.

306597 Naturally occurring chlorine is 75.53% \({\rm{C}}{{\rm{l}}^{{\rm{35}}}}\) which has an atomic mass of 34.969 amu and 24.47% \({\rm{C}}{{\rm{l}}^{{\rm{37}}}}\) which has a mass of 36.969 amu. Calculate the average atomic mass of chlorine.

306598 The vapour density of gas \(\rm{{\text{A}}}\) is four times that of \(\rm{{\text{B}}}\). If molecular mass of \(\rm{{\text{B}}}\) is \(\rm{{\text{M}}}\), then molecular mass of \(\mathrm{\mathrm{A}}\) is

306599 A mixture of gas "X" (mol. wt. 16) and gas “Y” (mol. wt. 28) in the mole ratio a : b has a mean molecular weight 20. What would be mean molecular weight if the gases are mixed in the ratio b : a under identical conditions (gases are non reacting)?