358342 A point charge \(q\) is placed at the corner of a cube of side a as shown in the figure. What is the electric flux through the face \(ABCD\) ?

358343 A point charge \({q}\) is located on the axis of a disc of radius \({R}\) at a distance \({b=5 \sqrt{3} {~m}}\) from the plane of the disc as shown in figure. What should be the radius of the disc if one-fourth of the total electric flux from the charge passes through the disc.

358344 Assertion :
Gauss's law can't be used to calculate electric field near an electric dipole.
Reason :
Electric dipole does not have symmetrical field.

358345 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
If an electric dipole of dipole moment \(30 \times {10^{ - 5}}Cm\) is enclosed by a closed surface, the net flux coming out of the surface will be zero.
Reason :
Electric dipole consists of two equal and opposite charges.

358342 A point charge \(q\) is placed at the corner of a cube of side a as shown in the figure. What is the electric flux through the face \(ABCD\) ?

358343 A point charge \({q}\) is located on the axis of a disc of radius \({R}\) at a distance \({b=5 \sqrt{3} {~m}}\) from the plane of the disc as shown in figure. What should be the radius of the disc if one-fourth of the total electric flux from the charge passes through the disc.

358344 Assertion :
Gauss's law can't be used to calculate electric field near an electric dipole.
Reason :
Electric dipole does not have symmetrical field.

358345 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
If an electric dipole of dipole moment \(30 \times {10^{ - 5}}Cm\) is enclosed by a closed surface, the net flux coming out of the surface will be zero.
Reason :
Electric dipole consists of two equal and opposite charges.

358342 A point charge \(q\) is placed at the corner of a cube of side a as shown in the figure. What is the electric flux through the face \(ABCD\) ?

358343 A point charge \({q}\) is located on the axis of a disc of radius \({R}\) at a distance \({b=5 \sqrt{3} {~m}}\) from the plane of the disc as shown in figure. What should be the radius of the disc if one-fourth of the total electric flux from the charge passes through the disc.

358344 Assertion :
Gauss's law can't be used to calculate electric field near an electric dipole.
Reason :
Electric dipole does not have symmetrical field.

358345 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
If an electric dipole of dipole moment \(30 \times {10^{ - 5}}Cm\) is enclosed by a closed surface, the net flux coming out of the surface will be zero.
Reason :
Electric dipole consists of two equal and opposite charges.

358342 A point charge \(q\) is placed at the corner of a cube of side a as shown in the figure. What is the electric flux through the face \(ABCD\) ?

358343 A point charge \({q}\) is located on the axis of a disc of radius \({R}\) at a distance \({b=5 \sqrt{3} {~m}}\) from the plane of the disc as shown in figure. What should be the radius of the disc if one-fourth of the total electric flux from the charge passes through the disc.

358344 Assertion :
Gauss's law can't be used to calculate electric field near an electric dipole.
Reason :
Electric dipole does not have symmetrical field.

358345 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
If an electric dipole of dipole moment \(30 \times {10^{ - 5}}Cm\) is enclosed by a closed surface, the net flux coming out of the surface will be zero.
Reason :
Electric dipole consists of two equal and opposite charges.