358346
If there were only one type of charge in the universe, then
1 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } \ne 0\) on any surface
2 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = 0\) if the charge is outside the surface
3 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = \frac{q}{{{\varepsilon _0}}}\) if charges of magnitude \(q\) were inside the surface
4 Both (2) and (3) are correct
Explanation:
According to gauss’s theorem in electrostatics \(\oint_S {\overrightarrow E \cdot \overrightarrow {ds} } = \frac{q}{{{\varepsilon _0}}}\) Here \(q\) is charge enclosed by the surface. if the charge is outside the surface, then \({q_{inside}} = 0\) Also,\(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = 0\) So, both (2) and (3) are correct.
PHXII01:ELECTRIC CHARGES AND FIELDS
358347
Assertion : Upon displacement of charges within a closed surface, \(E\) at any point on the surface does not change. Reason : The flux crossing through a closed surface is independent of the location of charge within the surface.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Due to displacement of charge within closed surface \(E\) at any point may change. But net flux crossing the surface will not change.
358346
If there were only one type of charge in the universe, then
1 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } \ne 0\) on any surface
2 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = 0\) if the charge is outside the surface
3 \(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = \frac{q}{{{\varepsilon _0}}}\) if charges of magnitude \(q\) were inside the surface
4 Both (2) and (3) are correct
Explanation:
According to gauss’s theorem in electrostatics \(\oint_S {\overrightarrow E \cdot \overrightarrow {ds} } = \frac{q}{{{\varepsilon _0}}}\) Here \(q\) is charge enclosed by the surface. if the charge is outside the surface, then \({q_{inside}} = 0\) Also,\(\oint_S {\overrightarrow E \cdot d\overrightarrow s } = 0\) So, both (2) and (3) are correct.
PHXII01:ELECTRIC CHARGES AND FIELDS
358347
Assertion : Upon displacement of charges within a closed surface, \(E\) at any point on the surface does not change. Reason : The flux crossing through a closed surface is independent of the location of charge within the surface.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Due to displacement of charge within closed surface \(E\) at any point may change. But net flux crossing the surface will not change.