357849 The de-Broglie wavelength of a proton and an \(\alpha\)-particle are \(\lambda\) and \(2 \lambda\) respectively. The ratio of the velocities of proton and \(\alpha\)-particle will be

357850 The de Broglie wavelength of a neutron at \(27^\circ C\) is \(\lambda_{0}\). What will be its wavelength at \(927^{\circ} C\) ?

357851 The kinetic energy of an electron is 5 \(eV\) . The de Broglie wavelength associated with it\({\left(h=6.6 \times 10^{-34} {~J} {~s}, m_{e}=9.1 \times 10^{-31} {~kg}\right)}\) is

357852 The momentum of a proton is \({2.5 \times 10^{-29} {~kg}-{m} / {s}}\). Its frequency will be

357853 The radius of an \({\alpha}\)-particle moving in a circle in a constant magnetic field is half of the radius of an electron moving in circular path in the same field. The de-Broglie wavelength of \({\alpha}\)-particle is \({n}\) times that of the electron. Find \({n}\) (an integer).

357849 The de-Broglie wavelength of a proton and an \(\alpha\)-particle are \(\lambda\) and \(2 \lambda\) respectively. The ratio of the velocities of proton and \(\alpha\)-particle will be

357850 The de Broglie wavelength of a neutron at \(27^\circ C\) is \(\lambda_{0}\). What will be its wavelength at \(927^{\circ} C\) ?

357851 The kinetic energy of an electron is 5 \(eV\) . The de Broglie wavelength associated with it\({\left(h=6.6 \times 10^{-34} {~J} {~s}, m_{e}=9.1 \times 10^{-31} {~kg}\right)}\) is

357852 The momentum of a proton is \({2.5 \times 10^{-29} {~kg}-{m} / {s}}\). Its frequency will be

357853 The radius of an \({\alpha}\)-particle moving in a circle in a constant magnetic field is half of the radius of an electron moving in circular path in the same field. The de-Broglie wavelength of \({\alpha}\)-particle is \({n}\) times that of the electron. Find \({n}\) (an integer).

357849 The de-Broglie wavelength of a proton and an \(\alpha\)-particle are \(\lambda\) and \(2 \lambda\) respectively. The ratio of the velocities of proton and \(\alpha\)-particle will be

357850 The de Broglie wavelength of a neutron at \(27^\circ C\) is \(\lambda_{0}\). What will be its wavelength at \(927^{\circ} C\) ?

357851 The kinetic energy of an electron is 5 \(eV\) . The de Broglie wavelength associated with it\({\left(h=6.6 \times 10^{-34} {~J} {~s}, m_{e}=9.1 \times 10^{-31} {~kg}\right)}\) is

357852 The momentum of a proton is \({2.5 \times 10^{-29} {~kg}-{m} / {s}}\). Its frequency will be

357853 The radius of an \({\alpha}\)-particle moving in a circle in a constant magnetic field is half of the radius of an electron moving in circular path in the same field. The de-Broglie wavelength of \({\alpha}\)-particle is \({n}\) times that of the electron. Find \({n}\) (an integer).

357849 The de-Broglie wavelength of a proton and an \(\alpha\)-particle are \(\lambda\) and \(2 \lambda\) respectively. The ratio of the velocities of proton and \(\alpha\)-particle will be

357850 The de Broglie wavelength of a neutron at \(27^\circ C\) is \(\lambda_{0}\). What will be its wavelength at \(927^{\circ} C\) ?

357851 The kinetic energy of an electron is 5 \(eV\) . The de Broglie wavelength associated with it\({\left(h=6.6 \times 10^{-34} {~J} {~s}, m_{e}=9.1 \times 10^{-31} {~kg}\right)}\) is

357852 The momentum of a proton is \({2.5 \times 10^{-29} {~kg}-{m} / {s}}\). Its frequency will be

357853 The radius of an \({\alpha}\)-particle moving in a circle in a constant magnetic field is half of the radius of an electron moving in circular path in the same field. The de-Broglie wavelength of \({\alpha}\)-particle is \({n}\) times that of the electron. Find \({n}\) (an integer).

357849 The de-Broglie wavelength of a proton and an \(\alpha\)-particle are \(\lambda\) and \(2 \lambda\) respectively. The ratio of the velocities of proton and \(\alpha\)-particle will be

357850 The de Broglie wavelength of a neutron at \(27^\circ C\) is \(\lambda_{0}\). What will be its wavelength at \(927^{\circ} C\) ?

357851 The kinetic energy of an electron is 5 \(eV\) . The de Broglie wavelength associated with it\({\left(h=6.6 \times 10^{-34} {~J} {~s}, m_{e}=9.1 \times 10^{-31} {~kg}\right)}\) is

357852 The momentum of a proton is \({2.5 \times 10^{-29} {~kg}-{m} / {s}}\). Its frequency will be

357853 The radius of an \({\alpha}\)-particle moving in a circle in a constant magnetic field is half of the radius of an electron moving in circular path in the same field. The de-Broglie wavelength of \({\alpha}\)-particle is \({n}\) times that of the electron. Find \({n}\) (an integer).