1 Wavelength of de Broglie wave depends upon velocity.
2 Material wave (de Broglie wave) can travel in vacuum.
3 Electromagnetic wave can travel through vacuum.
4 The velocity of photon is the same as light passes through any medium.
Explanation:
Velocity of a photon depends on medium
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357846
According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is \({10^{-9} {~m}}\). What is the principal quantum number for this electron?
357847
Assertion : The de Broglie wavelength of a molecule varies inversely as the square root of temperature. Reason : The root mean square velocity of the molecule depends on the temperature.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
de Broglie wavelength associated with gas molecule varies as \(\lambda \propto \dfrac{1}{\sqrt{T}}\) Also, root mean square velocity of gas molecule is, \({v_{{\rm{rms}}}} = \sqrt {\frac{{3RT}}{M}} \) Momentum \(p=\dfrac{h}{\lambda}=m v_{r m s}\). So option (2) is correct.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357848
If the value of Planck's constant is more than its present value, then the de Broglie wavelength associated with a material particle will be
1 More
2 Less
3 Same
4 More for lighter particles and less for heavy particles
Explanation:
\(\lambda \,\alpha \,h\) if \(h\) is more then \(\lambda \) is also more
1 Wavelength of de Broglie wave depends upon velocity.
2 Material wave (de Broglie wave) can travel in vacuum.
3 Electromagnetic wave can travel through vacuum.
4 The velocity of photon is the same as light passes through any medium.
Explanation:
Velocity of a photon depends on medium
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357846
According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is \({10^{-9} {~m}}\). What is the principal quantum number for this electron?
357847
Assertion : The de Broglie wavelength of a molecule varies inversely as the square root of temperature. Reason : The root mean square velocity of the molecule depends on the temperature.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
de Broglie wavelength associated with gas molecule varies as \(\lambda \propto \dfrac{1}{\sqrt{T}}\) Also, root mean square velocity of gas molecule is, \({v_{{\rm{rms}}}} = \sqrt {\frac{{3RT}}{M}} \) Momentum \(p=\dfrac{h}{\lambda}=m v_{r m s}\). So option (2) is correct.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357848
If the value of Planck's constant is more than its present value, then the de Broglie wavelength associated with a material particle will be
1 More
2 Less
3 Same
4 More for lighter particles and less for heavy particles
Explanation:
\(\lambda \,\alpha \,h\) if \(h\) is more then \(\lambda \) is also more
1 Wavelength of de Broglie wave depends upon velocity.
2 Material wave (de Broglie wave) can travel in vacuum.
3 Electromagnetic wave can travel through vacuum.
4 The velocity of photon is the same as light passes through any medium.
Explanation:
Velocity of a photon depends on medium
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357846
According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is \({10^{-9} {~m}}\). What is the principal quantum number for this electron?
357847
Assertion : The de Broglie wavelength of a molecule varies inversely as the square root of temperature. Reason : The root mean square velocity of the molecule depends on the temperature.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
de Broglie wavelength associated with gas molecule varies as \(\lambda \propto \dfrac{1}{\sqrt{T}}\) Also, root mean square velocity of gas molecule is, \({v_{{\rm{rms}}}} = \sqrt {\frac{{3RT}}{M}} \) Momentum \(p=\dfrac{h}{\lambda}=m v_{r m s}\). So option (2) is correct.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357848
If the value of Planck's constant is more than its present value, then the de Broglie wavelength associated with a material particle will be
1 More
2 Less
3 Same
4 More for lighter particles and less for heavy particles
Explanation:
\(\lambda \,\alpha \,h\) if \(h\) is more then \(\lambda \) is also more
1 Wavelength of de Broglie wave depends upon velocity.
2 Material wave (de Broglie wave) can travel in vacuum.
3 Electromagnetic wave can travel through vacuum.
4 The velocity of photon is the same as light passes through any medium.
Explanation:
Velocity of a photon depends on medium
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357846
According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is \({10^{-9} {~m}}\). What is the principal quantum number for this electron?
357847
Assertion : The de Broglie wavelength of a molecule varies inversely as the square root of temperature. Reason : The root mean square velocity of the molecule depends on the temperature.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
de Broglie wavelength associated with gas molecule varies as \(\lambda \propto \dfrac{1}{\sqrt{T}}\) Also, root mean square velocity of gas molecule is, \({v_{{\rm{rms}}}} = \sqrt {\frac{{3RT}}{M}} \) Momentum \(p=\dfrac{h}{\lambda}=m v_{r m s}\). So option (2) is correct.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357848
If the value of Planck's constant is more than its present value, then the de Broglie wavelength associated with a material particle will be
1 More
2 Less
3 Same
4 More for lighter particles and less for heavy particles
Explanation:
\(\lambda \,\alpha \,h\) if \(h\) is more then \(\lambda \) is also more
