Kirchhoff’s Laws
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PHXII03:CURRENT ELECTRICITY

357435 In this circuit, the value of \({I_2}\) is
supporting img

1 \(8A\)
2 \(6A\)
3 \(11A\)
4 \(3A\)
PHXII03:CURRENT ELECTRICITY

357436 What is the current flowing in arm \(AB\) ?
supporting img

1 \(\frac{{35}}{4}\;A\)
2 \(\frac{{13}}{7}\;A\)
3 \(\frac{5}{7}\;A\)
4 \(\frac{7}{5}\;A\)
PHXII03:CURRENT ELECTRICITY

357437 A current of 2 \(A\) flows in a system of conductors as shown. The potential difference \(({V_A} - {V_B})\) will be
supporting img

1 \( - 2V\)
2 \( + 1V\)
3 \( - 1V\)
4 \( + 2V\)
PHXII03:CURRENT ELECTRICITY

357438 As shown in the figure, a network of resistors is connected to a battery of \(24\;V\) with an internal resistance of \(3 \Omega\). The currents through the resistors \(R_{4}\) and \(R_{5}\) are \(I_{4}\) and \(I_{5}\) respectively.The values of \(I_{4}\) and \(I_{5}\) are
supporting img

1 \({I_4} = \frac{6}{5}\;A\) and \({I_5} = \frac{2}{5}\;A\)
2 \({I_4} = \frac{8}{5}\;A\) and \({I_5} = \frac{24}{5}\;A\)
3 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{8}{5}\;A\)
4 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{6}{5}\;A\)
JEE - 2023
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PHXII03:CURRENT ELECTRICITY

357435 In this circuit, the value of \({I_2}\) is
supporting img

1 \(8A\)
2 \(6A\)
3 \(11A\)
4 \(3A\)
PHXII03:CURRENT ELECTRICITY

357436 What is the current flowing in arm \(AB\) ?
supporting img

1 \(\frac{{35}}{4}\;A\)
2 \(\frac{{13}}{7}\;A\)
3 \(\frac{5}{7}\;A\)
4 \(\frac{7}{5}\;A\)
PHXII03:CURRENT ELECTRICITY

357437 A current of 2 \(A\) flows in a system of conductors as shown. The potential difference \(({V_A} - {V_B})\) will be
supporting img

1 \( - 2V\)
2 \( + 1V\)
3 \( - 1V\)
4 \( + 2V\)
PHXII03:CURRENT ELECTRICITY

357438 As shown in the figure, a network of resistors is connected to a battery of \(24\;V\) with an internal resistance of \(3 \Omega\). The currents through the resistors \(R_{4}\) and \(R_{5}\) are \(I_{4}\) and \(I_{5}\) respectively.The values of \(I_{4}\) and \(I_{5}\) are
supporting img

1 \({I_4} = \frac{6}{5}\;A\) and \({I_5} = \frac{2}{5}\;A\)
2 \({I_4} = \frac{8}{5}\;A\) and \({I_5} = \frac{24}{5}\;A\)
3 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{8}{5}\;A\)
4 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{6}{5}\;A\)
JEE - 2023
NEET DIGITAL LIBRARY
PHXII03:CURRENT ELECTRICITY

357435 In this circuit, the value of \({I_2}\) is
supporting img

1 \(8A\)
2 \(6A\)
3 \(11A\)
4 \(3A\)
PHXII03:CURRENT ELECTRICITY

357436 What is the current flowing in arm \(AB\) ?
supporting img

1 \(\frac{{35}}{4}\;A\)
2 \(\frac{{13}}{7}\;A\)
3 \(\frac{5}{7}\;A\)
4 \(\frac{7}{5}\;A\)
PHXII03:CURRENT ELECTRICITY

357437 A current of 2 \(A\) flows in a system of conductors as shown. The potential difference \(({V_A} - {V_B})\) will be
supporting img

1 \( - 2V\)
2 \( + 1V\)
3 \( - 1V\)
4 \( + 2V\)
PHXII03:CURRENT ELECTRICITY

357438 As shown in the figure, a network of resistors is connected to a battery of \(24\;V\) with an internal resistance of \(3 \Omega\). The currents through the resistors \(R_{4}\) and \(R_{5}\) are \(I_{4}\) and \(I_{5}\) respectively.The values of \(I_{4}\) and \(I_{5}\) are
supporting img

1 \({I_4} = \frac{6}{5}\;A\) and \({I_5} = \frac{2}{5}\;A\)
2 \({I_4} = \frac{8}{5}\;A\) and \({I_5} = \frac{24}{5}\;A\)
3 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{8}{5}\;A\)
4 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{6}{5}\;A\)
JEE - 2023
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PHXII03:CURRENT ELECTRICITY

357435 In this circuit, the value of \({I_2}\) is
supporting img

1 \(8A\)
2 \(6A\)
3 \(11A\)
4 \(3A\)
PHXII03:CURRENT ELECTRICITY

357436 What is the current flowing in arm \(AB\) ?
supporting img

1 \(\frac{{35}}{4}\;A\)
2 \(\frac{{13}}{7}\;A\)
3 \(\frac{5}{7}\;A\)
4 \(\frac{7}{5}\;A\)
PHXII03:CURRENT ELECTRICITY

357437 A current of 2 \(A\) flows in a system of conductors as shown. The potential difference \(({V_A} - {V_B})\) will be
supporting img

1 \( - 2V\)
2 \( + 1V\)
3 \( - 1V\)
4 \( + 2V\)
PHXII03:CURRENT ELECTRICITY

357438 As shown in the figure, a network of resistors is connected to a battery of \(24\;V\) with an internal resistance of \(3 \Omega\). The currents through the resistors \(R_{4}\) and \(R_{5}\) are \(I_{4}\) and \(I_{5}\) respectively.The values of \(I_{4}\) and \(I_{5}\) are
supporting img

1 \({I_4} = \frac{6}{5}\;A\) and \({I_5} = \frac{2}{5}\;A\)
2 \({I_4} = \frac{8}{5}\;A\) and \({I_5} = \frac{24}{5}\;A\)
3 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{8}{5}\;A\)
4 \({I_4} = \frac{2}{5}\;A\) and \({I_5} = \frac{6}{5}\;A\)
JEE - 2023
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