357316 The length of a potentiometer wire is \(l.\) A cell of \(emf\,E\) is balanced at a length \(l/3\) from the positive end of the wire. If the length of the wire is increased by \(l/2\) At what distance will be the same cell give a balance point.

357317 A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf 2.0 \(V\) and a negligible internal resistance. The potentiometer wire itself is 4\(m\) long. When the resistance \(R\) connected across the given cell, has values of (1) infinity, (2)\(9.5\Omega \), the balancing lengths, on the potentiometer wire are found to be 3\(m\) and 2.85 \(m\) respectively. The value of internal resistance of the cell is

357318 In figure battery \(E\) is balanced on \(55\;cm\) length of potentiometer wire but when a resistance of \(10\,\Omega \) is connected in parallel with the battery then it balances on \(50\;cm\) length of the potentiometer wire then internal resistance \(r\) of the battery is :

357319 The circuit shown here is used to compare the emf of two cells \({E_1}\;\) and \({E_2}\). The null point is at \(C\) when the galvanometer is connected to \({E_1}\) .When the galvanometer is connected to \({E_2}\), the null point will be

357316 The length of a potentiometer wire is \(l.\) A cell of \(emf\,E\) is balanced at a length \(l/3\) from the positive end of the wire. If the length of the wire is increased by \(l/2\) At what distance will be the same cell give a balance point.

357317 A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf 2.0 \(V\) and a negligible internal resistance. The potentiometer wire itself is 4\(m\) long. When the resistance \(R\) connected across the given cell, has values of (1) infinity, (2)\(9.5\Omega \), the balancing lengths, on the potentiometer wire are found to be 3\(m\) and 2.85 \(m\) respectively. The value of internal resistance of the cell is

357318 In figure battery \(E\) is balanced on \(55\;cm\) length of potentiometer wire but when a resistance of \(10\,\Omega \) is connected in parallel with the battery then it balances on \(50\;cm\) length of the potentiometer wire then internal resistance \(r\) of the battery is :

357319 The circuit shown here is used to compare the emf of two cells \({E_1}\;\) and \({E_2}\). The null point is at \(C\) when the galvanometer is connected to \({E_1}\) .When the galvanometer is connected to \({E_2}\), the null point will be

357316 The length of a potentiometer wire is \(l.\) A cell of \(emf\,E\) is balanced at a length \(l/3\) from the positive end of the wire. If the length of the wire is increased by \(l/2\) At what distance will be the same cell give a balance point.

357317 A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf 2.0 \(V\) and a negligible internal resistance. The potentiometer wire itself is 4\(m\) long. When the resistance \(R\) connected across the given cell, has values of (1) infinity, (2)\(9.5\Omega \), the balancing lengths, on the potentiometer wire are found to be 3\(m\) and 2.85 \(m\) respectively. The value of internal resistance of the cell is

357318 In figure battery \(E\) is balanced on \(55\;cm\) length of potentiometer wire but when a resistance of \(10\,\Omega \) is connected in parallel with the battery then it balances on \(50\;cm\) length of the potentiometer wire then internal resistance \(r\) of the battery is :

357319 The circuit shown here is used to compare the emf of two cells \({E_1}\;\) and \({E_2}\). The null point is at \(C\) when the galvanometer is connected to \({E_1}\) .When the galvanometer is connected to \({E_2}\), the null point will be

357316 The length of a potentiometer wire is \(l.\) A cell of \(emf\,E\) is balanced at a length \(l/3\) from the positive end of the wire. If the length of the wire is increased by \(l/2\) At what distance will be the same cell give a balance point.

357317 A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf 2.0 \(V\) and a negligible internal resistance. The potentiometer wire itself is 4\(m\) long. When the resistance \(R\) connected across the given cell, has values of (1) infinity, (2)\(9.5\Omega \), the balancing lengths, on the potentiometer wire are found to be 3\(m\) and 2.85 \(m\) respectively. The value of internal resistance of the cell is

357318 In figure battery \(E\) is balanced on \(55\;cm\) length of potentiometer wire but when a resistance of \(10\,\Omega \) is connected in parallel with the battery then it balances on \(50\;cm\) length of the potentiometer wire then internal resistance \(r\) of the battery is :

357319 The circuit shown here is used to compare the emf of two cells \({E_1}\;\) and \({E_2}\). The null point is at \(C\) when the galvanometer is connected to \({E_1}\) .When the galvanometer is connected to \({E_2}\), the null point will be