357311 A potentiometer is connected across \(A\) and \(B\) and a balance is obtained at \(64.0\;cm\). When potentiometer lead to \(B\) is moved to \(C\), a balance is found at \(8.0\;cm\). If the potentiometer is now connected across \(B\) and \(C\), a balance will be found at

357312 In a potentiometer experiment two cells of e.m.f.’s \({E_1}\) and \({E_2}\) are used in series and the balancing length is found to be 58 \(cm\) of the wire. If the polarity of \({E_2}\) is reversed, then the balancing length becomes 29 \(cm\). The ratio \(\frac{{{E_1}}}{{{E_2}}}\) of the e.m.f. of the two cells is \(({E_1}\; > {E_2})\)

357313 A potentiometer of one metre length, an unknown, e.m.f voltage source is balanced at 60 \(cm\) length of potentiometer wire, while a 3 volt battery is balanced at 45 \(cm\) length. Then the e.m.f. of the unknown voltage source is

357314 In a potentiometer the balance length with standard cadmium cell is 509 \(cm\). The emf of a cell which when connected in place of the standard cell gave a balance length of 750 \(cm\) is (emf of standard cell is 1.018\(V\))

357315 Figure shows a 200 \(cm\) potentiometer wire \({A B}\) with resistance \({15\,\, \Omega}\). Find the balancing length for a 3 \(V\) cell.

357311 A potentiometer is connected across \(A\) and \(B\) and a balance is obtained at \(64.0\;cm\). When potentiometer lead to \(B\) is moved to \(C\), a balance is found at \(8.0\;cm\). If the potentiometer is now connected across \(B\) and \(C\), a balance will be found at

357312 In a potentiometer experiment two cells of e.m.f.’s \({E_1}\) and \({E_2}\) are used in series and the balancing length is found to be 58 \(cm\) of the wire. If the polarity of \({E_2}\) is reversed, then the balancing length becomes 29 \(cm\). The ratio \(\frac{{{E_1}}}{{{E_2}}}\) of the e.m.f. of the two cells is \(({E_1}\; > {E_2})\)

357313 A potentiometer of one metre length, an unknown, e.m.f voltage source is balanced at 60 \(cm\) length of potentiometer wire, while a 3 volt battery is balanced at 45 \(cm\) length. Then the e.m.f. of the unknown voltage source is

357314 In a potentiometer the balance length with standard cadmium cell is 509 \(cm\). The emf of a cell which when connected in place of the standard cell gave a balance length of 750 \(cm\) is (emf of standard cell is 1.018\(V\))

357315 Figure shows a 200 \(cm\) potentiometer wire \({A B}\) with resistance \({15\,\, \Omega}\). Find the balancing length for a 3 \(V\) cell.

357311 A potentiometer is connected across \(A\) and \(B\) and a balance is obtained at \(64.0\;cm\). When potentiometer lead to \(B\) is moved to \(C\), a balance is found at \(8.0\;cm\). If the potentiometer is now connected across \(B\) and \(C\), a balance will be found at

357312 In a potentiometer experiment two cells of e.m.f.’s \({E_1}\) and \({E_2}\) are used in series and the balancing length is found to be 58 \(cm\) of the wire. If the polarity of \({E_2}\) is reversed, then the balancing length becomes 29 \(cm\). The ratio \(\frac{{{E_1}}}{{{E_2}}}\) of the e.m.f. of the two cells is \(({E_1}\; > {E_2})\)

357313 A potentiometer of one metre length, an unknown, e.m.f voltage source is balanced at 60 \(cm\) length of potentiometer wire, while a 3 volt battery is balanced at 45 \(cm\) length. Then the e.m.f. of the unknown voltage source is

357314 In a potentiometer the balance length with standard cadmium cell is 509 \(cm\). The emf of a cell which when connected in place of the standard cell gave a balance length of 750 \(cm\) is (emf of standard cell is 1.018\(V\))

357315 Figure shows a 200 \(cm\) potentiometer wire \({A B}\) with resistance \({15\,\, \Omega}\). Find the balancing length for a 3 \(V\) cell.

357311 A potentiometer is connected across \(A\) and \(B\) and a balance is obtained at \(64.0\;cm\). When potentiometer lead to \(B\) is moved to \(C\), a balance is found at \(8.0\;cm\). If the potentiometer is now connected across \(B\) and \(C\), a balance will be found at

357312 In a potentiometer experiment two cells of e.m.f.’s \({E_1}\) and \({E_2}\) are used in series and the balancing length is found to be 58 \(cm\) of the wire. If the polarity of \({E_2}\) is reversed, then the balancing length becomes 29 \(cm\). The ratio \(\frac{{{E_1}}}{{{E_2}}}\) of the e.m.f. of the two cells is \(({E_1}\; > {E_2})\)

357313 A potentiometer of one metre length, an unknown, e.m.f voltage source is balanced at 60 \(cm\) length of potentiometer wire, while a 3 volt battery is balanced at 45 \(cm\) length. Then the e.m.f. of the unknown voltage source is

357314 In a potentiometer the balance length with standard cadmium cell is 509 \(cm\). The emf of a cell which when connected in place of the standard cell gave a balance length of 750 \(cm\) is (emf of standard cell is 1.018\(V\))

357315 Figure shows a 200 \(cm\) potentiometer wire \({A B}\) with resistance \({15\,\, \Omega}\). Find the balancing length for a 3 \(V\) cell.

357311 A potentiometer is connected across \(A\) and \(B\) and a balance is obtained at \(64.0\;cm\). When potentiometer lead to \(B\) is moved to \(C\), a balance is found at \(8.0\;cm\). If the potentiometer is now connected across \(B\) and \(C\), a balance will be found at

357312 In a potentiometer experiment two cells of e.m.f.’s \({E_1}\) and \({E_2}\) are used in series and the balancing length is found to be 58 \(cm\) of the wire. If the polarity of \({E_2}\) is reversed, then the balancing length becomes 29 \(cm\). The ratio \(\frac{{{E_1}}}{{{E_2}}}\) of the e.m.f. of the two cells is \(({E_1}\; > {E_2})\)

357313 A potentiometer of one metre length, an unknown, e.m.f voltage source is balanced at 60 \(cm\) length of potentiometer wire, while a 3 volt battery is balanced at 45 \(cm\) length. Then the e.m.f. of the unknown voltage source is

357314 In a potentiometer the balance length with standard cadmium cell is 509 \(cm\). The emf of a cell which when connected in place of the standard cell gave a balance length of 750 \(cm\) is (emf of standard cell is 1.018\(V\))

357315 Figure shows a 200 \(cm\) potentiometer wire \({A B}\) with resistance \({15\,\, \Omega}\). Find the balancing length for a 3 \(V\) cell.