Electrical Instruments
PHXII03:CURRENT ELECTRICITY

357273 In a metre bridge, the balancing length from the left end (standard resistance of one ohm is in the right gap) is found to be 20 \(cm\). The value of the unknown resistance is

1 \({\rm{0}}{\rm{.5}}\Omega \)
2 \({\rm{0}}{\rm{.8}}\Omega \)
3 \({\rm{0}}{\rm{.4}}\Omega \)
4 \({\rm{0}}{\rm{.25}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357274 A resistance wire connected in the left gap of a metre bridge balances a \(10\Omega \) resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 \(m\), then the length of \(1\Omega \) of the resistance wire is:

1 \(1.0 \times {10^{ - 1}}m\)
2 \(1.5 \times {10^{ - 1}}m\)
3 \(1.5 \times {10^{ - 2}}m\)
4 \(1.0 \times {10^{ - 2}}m\)
PHXII03:CURRENT ELECTRICITY

357275 In a meter bridge as shown in the figure it is given that resistance \(Y = 12.5\,\Omega \) and that the balance is obtained at a distance 39.5 \(cm\) from end \(A\) (by Jockey \(J\)). After interchanging the resistances \(X\) and \(Y\) a new balance point is found at a distance \({l_2}\) from end \(A\). What are the values of \(X\) and \({l_2}\)?
supporting img

1 \(19.5\,\Omega \) and \(39.5\,\Omega \)
2 \(8.16\,\Omega \) and 60 \(cm\)
3 \(8.16\,\Omega \) and 39.5 \(cm\)
4 \(19.15\,\Omega \) and 60.5 \(cm\)
PHXII03:CURRENT ELECTRICITY

357276 In a metre bridge experiment, resistances are connected as shown in figure. The balancing length \({l_1}\) is 55 \(cm\). Now an unknown resistance \(x\) is connected in series with \(P\left( {P = 3\Omega } \right)\) and the new balancing length is found to be 75 \(cm\). The value of \(x\) is
supporting img

1 \(\frac{{20}}{{11}}\Omega \)
2 \(\frac{{54}}{{12}}\Omega \)
3 \(\frac{{48}}{{11}}\Omega \)
4 \(\frac{{11}}{{48}}\Omega \)
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PHXII03:CURRENT ELECTRICITY

357273 In a metre bridge, the balancing length from the left end (standard resistance of one ohm is in the right gap) is found to be 20 \(cm\). The value of the unknown resistance is

1 \({\rm{0}}{\rm{.5}}\Omega \)
2 \({\rm{0}}{\rm{.8}}\Omega \)
3 \({\rm{0}}{\rm{.4}}\Omega \)
4 \({\rm{0}}{\rm{.25}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357274 A resistance wire connected in the left gap of a metre bridge balances a \(10\Omega \) resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 \(m\), then the length of \(1\Omega \) of the resistance wire is:

1 \(1.0 \times {10^{ - 1}}m\)
2 \(1.5 \times {10^{ - 1}}m\)
3 \(1.5 \times {10^{ - 2}}m\)
4 \(1.0 \times {10^{ - 2}}m\)
PHXII03:CURRENT ELECTRICITY

357275 In a meter bridge as shown in the figure it is given that resistance \(Y = 12.5\,\Omega \) and that the balance is obtained at a distance 39.5 \(cm\) from end \(A\) (by Jockey \(J\)). After interchanging the resistances \(X\) and \(Y\) a new balance point is found at a distance \({l_2}\) from end \(A\). What are the values of \(X\) and \({l_2}\)?
supporting img

1 \(19.5\,\Omega \) and \(39.5\,\Omega \)
2 \(8.16\,\Omega \) and 60 \(cm\)
3 \(8.16\,\Omega \) and 39.5 \(cm\)
4 \(19.15\,\Omega \) and 60.5 \(cm\)
PHXII03:CURRENT ELECTRICITY

357276 In a metre bridge experiment, resistances are connected as shown in figure. The balancing length \({l_1}\) is 55 \(cm\). Now an unknown resistance \(x\) is connected in series with \(P\left( {P = 3\Omega } \right)\) and the new balancing length is found to be 75 \(cm\). The value of \(x\) is
supporting img

1 \(\frac{{20}}{{11}}\Omega \)
2 \(\frac{{54}}{{12}}\Omega \)
3 \(\frac{{48}}{{11}}\Omega \)
4 \(\frac{{11}}{{48}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357273 In a metre bridge, the balancing length from the left end (standard resistance of one ohm is in the right gap) is found to be 20 \(cm\). The value of the unknown resistance is

1 \({\rm{0}}{\rm{.5}}\Omega \)
2 \({\rm{0}}{\rm{.8}}\Omega \)
3 \({\rm{0}}{\rm{.4}}\Omega \)
4 \({\rm{0}}{\rm{.25}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357274 A resistance wire connected in the left gap of a metre bridge balances a \(10\Omega \) resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 \(m\), then the length of \(1\Omega \) of the resistance wire is:

1 \(1.0 \times {10^{ - 1}}m\)
2 \(1.5 \times {10^{ - 1}}m\)
3 \(1.5 \times {10^{ - 2}}m\)
4 \(1.0 \times {10^{ - 2}}m\)
PHXII03:CURRENT ELECTRICITY

357275 In a meter bridge as shown in the figure it is given that resistance \(Y = 12.5\,\Omega \) and that the balance is obtained at a distance 39.5 \(cm\) from end \(A\) (by Jockey \(J\)). After interchanging the resistances \(X\) and \(Y\) a new balance point is found at a distance \({l_2}\) from end \(A\). What are the values of \(X\) and \({l_2}\)?
supporting img

1 \(19.5\,\Omega \) and \(39.5\,\Omega \)
2 \(8.16\,\Omega \) and 60 \(cm\)
3 \(8.16\,\Omega \) and 39.5 \(cm\)
4 \(19.15\,\Omega \) and 60.5 \(cm\)
PHXII03:CURRENT ELECTRICITY

357276 In a metre bridge experiment, resistances are connected as shown in figure. The balancing length \({l_1}\) is 55 \(cm\). Now an unknown resistance \(x\) is connected in series with \(P\left( {P = 3\Omega } \right)\) and the new balancing length is found to be 75 \(cm\). The value of \(x\) is
supporting img

1 \(\frac{{20}}{{11}}\Omega \)
2 \(\frac{{54}}{{12}}\Omega \)
3 \(\frac{{48}}{{11}}\Omega \)
4 \(\frac{{11}}{{48}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357273 In a metre bridge, the balancing length from the left end (standard resistance of one ohm is in the right gap) is found to be 20 \(cm\). The value of the unknown resistance is

1 \({\rm{0}}{\rm{.5}}\Omega \)
2 \({\rm{0}}{\rm{.8}}\Omega \)
3 \({\rm{0}}{\rm{.4}}\Omega \)
4 \({\rm{0}}{\rm{.25}}\Omega \)
PHXII03:CURRENT ELECTRICITY

357274 A resistance wire connected in the left gap of a metre bridge balances a \(10\Omega \) resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 \(m\), then the length of \(1\Omega \) of the resistance wire is:

1 \(1.0 \times {10^{ - 1}}m\)
2 \(1.5 \times {10^{ - 1}}m\)
3 \(1.5 \times {10^{ - 2}}m\)
4 \(1.0 \times {10^{ - 2}}m\)
PHXII03:CURRENT ELECTRICITY

357275 In a meter bridge as shown in the figure it is given that resistance \(Y = 12.5\,\Omega \) and that the balance is obtained at a distance 39.5 \(cm\) from end \(A\) (by Jockey \(J\)). After interchanging the resistances \(X\) and \(Y\) a new balance point is found at a distance \({l_2}\) from end \(A\). What are the values of \(X\) and \({l_2}\)?
supporting img

1 \(19.5\,\Omega \) and \(39.5\,\Omega \)
2 \(8.16\,\Omega \) and 60 \(cm\)
3 \(8.16\,\Omega \) and 39.5 \(cm\)
4 \(19.15\,\Omega \) and 60.5 \(cm\)
PHXII03:CURRENT ELECTRICITY

357276 In a metre bridge experiment, resistances are connected as shown in figure. The balancing length \({l_1}\) is 55 \(cm\). Now an unknown resistance \(x\) is connected in series with \(P\left( {P = 3\Omega } \right)\) and the new balancing length is found to be 75 \(cm\). The value of \(x\) is
supporting img

1 \(\frac{{20}}{{11}}\Omega \)
2 \(\frac{{54}}{{12}}\Omega \)
3 \(\frac{{48}}{{11}}\Omega \)
4 \(\frac{{11}}{{48}}\Omega \)