NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII03:CURRENT ELECTRICITY
357247
In the circuit shown, the voltmeter has a large resitance. The emf of the cell is \(E\). The reading of the voltmeter is
1 \({\rm{Zero}}\)
2 \(\frac{E}{{10}}\)
3 \(\frac{E}{5}\)
4 \(\frac{E}{2}\)
Explanation:
Current does not flow through voltmeter.The current distribution is shown in the figure. \(i = \frac{E}{5}\) The potential difference across \(AB\) is the reading of voltmeter \({V_B} - {V_A} = 6\left( {\frac{i}{2}} \right) - 4\frac{i}{2} = \frac{E}{5}\)
PHXII03:CURRENT ELECTRICITY
357248
A voltmeter of resistance \(998 \Omega\) is connected across a cell of emf \(2\,V\) and internal resistance \(2 \Omega\). The potential difference across the voltmeter is
1 \(1.99\,\;V\)
2 \(3.5\,\;V\)
3 \(5\;\,V\)
4 \(6\,\;V\)
Explanation:
From Ohm's law, current, \(i = \frac{E}{{R + r}} = \frac{2}{{998 + 2}} = 2 \times {10^{ - 3}}\;A\) Potential difference across the voltmeter \(V = iR = \left( {2 \times {{10}^{ - 3}}} \right) \times 998 = 1.996\;\,V\)
PHXII03:CURRENT ELECTRICITY
357249
Assertion : Potential measured by a voltmeter across a wire always less than actual potential difference across it. Reason : Finite resistance of voltmeter changes current flowing through the resistance across which potential difference is to be measured.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Option (1) is correct.
PHXII03:CURRENT ELECTRICITY
357250
There are three voltmeters of the same range but of resistance \(10000\,\Omega ,\;8000\,\Omega \) and \(4000\,\Omega \) respectively. The best voltmeter among these is the one whose resistance is
357247
In the circuit shown, the voltmeter has a large resitance. The emf of the cell is \(E\). The reading of the voltmeter is
1 \({\rm{Zero}}\)
2 \(\frac{E}{{10}}\)
3 \(\frac{E}{5}\)
4 \(\frac{E}{2}\)
Explanation:
Current does not flow through voltmeter.The current distribution is shown in the figure. \(i = \frac{E}{5}\) The potential difference across \(AB\) is the reading of voltmeter \({V_B} - {V_A} = 6\left( {\frac{i}{2}} \right) - 4\frac{i}{2} = \frac{E}{5}\)
PHXII03:CURRENT ELECTRICITY
357248
A voltmeter of resistance \(998 \Omega\) is connected across a cell of emf \(2\,V\) and internal resistance \(2 \Omega\). The potential difference across the voltmeter is
1 \(1.99\,\;V\)
2 \(3.5\,\;V\)
3 \(5\;\,V\)
4 \(6\,\;V\)
Explanation:
From Ohm's law, current, \(i = \frac{E}{{R + r}} = \frac{2}{{998 + 2}} = 2 \times {10^{ - 3}}\;A\) Potential difference across the voltmeter \(V = iR = \left( {2 \times {{10}^{ - 3}}} \right) \times 998 = 1.996\;\,V\)
PHXII03:CURRENT ELECTRICITY
357249
Assertion : Potential measured by a voltmeter across a wire always less than actual potential difference across it. Reason : Finite resistance of voltmeter changes current flowing through the resistance across which potential difference is to be measured.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Option (1) is correct.
PHXII03:CURRENT ELECTRICITY
357250
There are three voltmeters of the same range but of resistance \(10000\,\Omega ,\;8000\,\Omega \) and \(4000\,\Omega \) respectively. The best voltmeter among these is the one whose resistance is
357247
In the circuit shown, the voltmeter has a large resitance. The emf of the cell is \(E\). The reading of the voltmeter is
1 \({\rm{Zero}}\)
2 \(\frac{E}{{10}}\)
3 \(\frac{E}{5}\)
4 \(\frac{E}{2}\)
Explanation:
Current does not flow through voltmeter.The current distribution is shown in the figure. \(i = \frac{E}{5}\) The potential difference across \(AB\) is the reading of voltmeter \({V_B} - {V_A} = 6\left( {\frac{i}{2}} \right) - 4\frac{i}{2} = \frac{E}{5}\)
PHXII03:CURRENT ELECTRICITY
357248
A voltmeter of resistance \(998 \Omega\) is connected across a cell of emf \(2\,V\) and internal resistance \(2 \Omega\). The potential difference across the voltmeter is
1 \(1.99\,\;V\)
2 \(3.5\,\;V\)
3 \(5\;\,V\)
4 \(6\,\;V\)
Explanation:
From Ohm's law, current, \(i = \frac{E}{{R + r}} = \frac{2}{{998 + 2}} = 2 \times {10^{ - 3}}\;A\) Potential difference across the voltmeter \(V = iR = \left( {2 \times {{10}^{ - 3}}} \right) \times 998 = 1.996\;\,V\)
PHXII03:CURRENT ELECTRICITY
357249
Assertion : Potential measured by a voltmeter across a wire always less than actual potential difference across it. Reason : Finite resistance of voltmeter changes current flowing through the resistance across which potential difference is to be measured.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Option (1) is correct.
PHXII03:CURRENT ELECTRICITY
357250
There are three voltmeters of the same range but of resistance \(10000\,\Omega ,\;8000\,\Omega \) and \(4000\,\Omega \) respectively. The best voltmeter among these is the one whose resistance is
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII03:CURRENT ELECTRICITY
357247
In the circuit shown, the voltmeter has a large resitance. The emf of the cell is \(E\). The reading of the voltmeter is
1 \({\rm{Zero}}\)
2 \(\frac{E}{{10}}\)
3 \(\frac{E}{5}\)
4 \(\frac{E}{2}\)
Explanation:
Current does not flow through voltmeter.The current distribution is shown in the figure. \(i = \frac{E}{5}\) The potential difference across \(AB\) is the reading of voltmeter \({V_B} - {V_A} = 6\left( {\frac{i}{2}} \right) - 4\frac{i}{2} = \frac{E}{5}\)
PHXII03:CURRENT ELECTRICITY
357248
A voltmeter of resistance \(998 \Omega\) is connected across a cell of emf \(2\,V\) and internal resistance \(2 \Omega\). The potential difference across the voltmeter is
1 \(1.99\,\;V\)
2 \(3.5\,\;V\)
3 \(5\;\,V\)
4 \(6\,\;V\)
Explanation:
From Ohm's law, current, \(i = \frac{E}{{R + r}} = \frac{2}{{998 + 2}} = 2 \times {10^{ - 3}}\;A\) Potential difference across the voltmeter \(V = iR = \left( {2 \times {{10}^{ - 3}}} \right) \times 998 = 1.996\;\,V\)
PHXII03:CURRENT ELECTRICITY
357249
Assertion : Potential measured by a voltmeter across a wire always less than actual potential difference across it. Reason : Finite resistance of voltmeter changes current flowing through the resistance across which potential difference is to be measured.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Option (1) is correct.
PHXII03:CURRENT ELECTRICITY
357250
There are three voltmeters of the same range but of resistance \(10000\,\Omega ,\;8000\,\Omega \) and \(4000\,\Omega \) respectively. The best voltmeter among these is the one whose resistance is
