356824
A transmitting antenna is at a height of \(40 \mathrm{~m}\) and the receiving antenna is at a height of \(60 \mathrm{~m}\). The maximum distance between them for satisfactory communication is nearly
1 \(22.5\;km\)
2 \(27.5\;km\)
3 \(50\;km\)
4 \(25\;km\)
Explanation:
Distance between transmitter and receiver is \(\mathrm{s}=\sqrt{2 \mathrm{Rh}_{\mathrm{t}}}+\sqrt{2 \mathrm{Rh}_{\mathrm{r}}}\), \( = \sqrt {2 \times 64 \times {{10}^5} \times 40} + \sqrt {2 \times 64 \times {{10}^5} \times 60} = 50\;km\)
PHXII15:COMMUNICATION SYSTEMS
356825
A TV transmitting antenna is \(98 m\) high and the receiving antenna is at the ground level. If the radius of the earth is \(6400\;km\), the surface area covered by the transmitting antenna is approximately
1 \(1240\;k{m^2}\)
2 \(1549\;k{m^2}\)
3 \(3942\;k{m^2}\)
4 \(4868\;k{m^2}\)
Explanation:
Given: \(h=98 {~m}=98 \times 10^{-3} {~km}, R=6400 {~km}\) Range of transmitting antenna, \(r=\sqrt{2 R h}\) (\(R:\) Radius of Earth) \(r=\sqrt{2 \times 6400 \times 98 \times 10^{-3}}\) Surface area covered by transmitting antenna \(=\pi r^{2}\)\(=2 \times 6400 \times 98 \times 10^{-3} \times \dfrac{22}{7}\) \(=3942.4 {~km}^{2} \approx 3942 {~km}^{2}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356826
Effective radiated power by an antenna is
1 Proportional to the square at the length of the antenna
2 Inversely proportional to the wavelength
3 Inversely proportional to the square of the wavelength
4 Proportional to the wavelength
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356827
Match Column-I with Column-II. Column I Column II A \({F_1}\) - Layers P \(10\,km\) B \(D\) -Layers Q \(170\) - \(190\,km\) C Troposphere R \(100\,km\) D \(E\) -Layers S \(65\) - \(75\,km\)
1 A - Q, B - P, C - S, D - R
2 A - R, B - S, C - P, D - Q
3 A - Q, B - S, C - R, D - P
4 A - Q, B - S, C - P, D - R
Explanation:
Height of different layers of atmosphere is given by \(F_{1}\)-layer is up to \(200 {~km}\) \(D\)-layer is up to \(70 {~km}\) Troposphere is up to \(10 {~km}\) \(E\)-layer is up to \(120 {~km}\).
356824
A transmitting antenna is at a height of \(40 \mathrm{~m}\) and the receiving antenna is at a height of \(60 \mathrm{~m}\). The maximum distance between them for satisfactory communication is nearly
1 \(22.5\;km\)
2 \(27.5\;km\)
3 \(50\;km\)
4 \(25\;km\)
Explanation:
Distance between transmitter and receiver is \(\mathrm{s}=\sqrt{2 \mathrm{Rh}_{\mathrm{t}}}+\sqrt{2 \mathrm{Rh}_{\mathrm{r}}}\), \( = \sqrt {2 \times 64 \times {{10}^5} \times 40} + \sqrt {2 \times 64 \times {{10}^5} \times 60} = 50\;km\)
PHXII15:COMMUNICATION SYSTEMS
356825
A TV transmitting antenna is \(98 m\) high and the receiving antenna is at the ground level. If the radius of the earth is \(6400\;km\), the surface area covered by the transmitting antenna is approximately
1 \(1240\;k{m^2}\)
2 \(1549\;k{m^2}\)
3 \(3942\;k{m^2}\)
4 \(4868\;k{m^2}\)
Explanation:
Given: \(h=98 {~m}=98 \times 10^{-3} {~km}, R=6400 {~km}\) Range of transmitting antenna, \(r=\sqrt{2 R h}\) (\(R:\) Radius of Earth) \(r=\sqrt{2 \times 6400 \times 98 \times 10^{-3}}\) Surface area covered by transmitting antenna \(=\pi r^{2}\)\(=2 \times 6400 \times 98 \times 10^{-3} \times \dfrac{22}{7}\) \(=3942.4 {~km}^{2} \approx 3942 {~km}^{2}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356826
Effective radiated power by an antenna is
1 Proportional to the square at the length of the antenna
2 Inversely proportional to the wavelength
3 Inversely proportional to the square of the wavelength
4 Proportional to the wavelength
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356827
Match Column-I with Column-II. Column I Column II A \({F_1}\) - Layers P \(10\,km\) B \(D\) -Layers Q \(170\) - \(190\,km\) C Troposphere R \(100\,km\) D \(E\) -Layers S \(65\) - \(75\,km\)
1 A - Q, B - P, C - S, D - R
2 A - R, B - S, C - P, D - Q
3 A - Q, B - S, C - R, D - P
4 A - Q, B - S, C - P, D - R
Explanation:
Height of different layers of atmosphere is given by \(F_{1}\)-layer is up to \(200 {~km}\) \(D\)-layer is up to \(70 {~km}\) Troposphere is up to \(10 {~km}\) \(E\)-layer is up to \(120 {~km}\).
356824
A transmitting antenna is at a height of \(40 \mathrm{~m}\) and the receiving antenna is at a height of \(60 \mathrm{~m}\). The maximum distance between them for satisfactory communication is nearly
1 \(22.5\;km\)
2 \(27.5\;km\)
3 \(50\;km\)
4 \(25\;km\)
Explanation:
Distance between transmitter and receiver is \(\mathrm{s}=\sqrt{2 \mathrm{Rh}_{\mathrm{t}}}+\sqrt{2 \mathrm{Rh}_{\mathrm{r}}}\), \( = \sqrt {2 \times 64 \times {{10}^5} \times 40} + \sqrt {2 \times 64 \times {{10}^5} \times 60} = 50\;km\)
PHXII15:COMMUNICATION SYSTEMS
356825
A TV transmitting antenna is \(98 m\) high and the receiving antenna is at the ground level. If the radius of the earth is \(6400\;km\), the surface area covered by the transmitting antenna is approximately
1 \(1240\;k{m^2}\)
2 \(1549\;k{m^2}\)
3 \(3942\;k{m^2}\)
4 \(4868\;k{m^2}\)
Explanation:
Given: \(h=98 {~m}=98 \times 10^{-3} {~km}, R=6400 {~km}\) Range of transmitting antenna, \(r=\sqrt{2 R h}\) (\(R:\) Radius of Earth) \(r=\sqrt{2 \times 6400 \times 98 \times 10^{-3}}\) Surface area covered by transmitting antenna \(=\pi r^{2}\)\(=2 \times 6400 \times 98 \times 10^{-3} \times \dfrac{22}{7}\) \(=3942.4 {~km}^{2} \approx 3942 {~km}^{2}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356826
Effective radiated power by an antenna is
1 Proportional to the square at the length of the antenna
2 Inversely proportional to the wavelength
3 Inversely proportional to the square of the wavelength
4 Proportional to the wavelength
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356827
Match Column-I with Column-II. Column I Column II A \({F_1}\) - Layers P \(10\,km\) B \(D\) -Layers Q \(170\) - \(190\,km\) C Troposphere R \(100\,km\) D \(E\) -Layers S \(65\) - \(75\,km\)
1 A - Q, B - P, C - S, D - R
2 A - R, B - S, C - P, D - Q
3 A - Q, B - S, C - R, D - P
4 A - Q, B - S, C - P, D - R
Explanation:
Height of different layers of atmosphere is given by \(F_{1}\)-layer is up to \(200 {~km}\) \(D\)-layer is up to \(70 {~km}\) Troposphere is up to \(10 {~km}\) \(E\)-layer is up to \(120 {~km}\).
356824
A transmitting antenna is at a height of \(40 \mathrm{~m}\) and the receiving antenna is at a height of \(60 \mathrm{~m}\). The maximum distance between them for satisfactory communication is nearly
1 \(22.5\;km\)
2 \(27.5\;km\)
3 \(50\;km\)
4 \(25\;km\)
Explanation:
Distance between transmitter and receiver is \(\mathrm{s}=\sqrt{2 \mathrm{Rh}_{\mathrm{t}}}+\sqrt{2 \mathrm{Rh}_{\mathrm{r}}}\), \( = \sqrt {2 \times 64 \times {{10}^5} \times 40} + \sqrt {2 \times 64 \times {{10}^5} \times 60} = 50\;km\)
PHXII15:COMMUNICATION SYSTEMS
356825
A TV transmitting antenna is \(98 m\) high and the receiving antenna is at the ground level. If the radius of the earth is \(6400\;km\), the surface area covered by the transmitting antenna is approximately
1 \(1240\;k{m^2}\)
2 \(1549\;k{m^2}\)
3 \(3942\;k{m^2}\)
4 \(4868\;k{m^2}\)
Explanation:
Given: \(h=98 {~m}=98 \times 10^{-3} {~km}, R=6400 {~km}\) Range of transmitting antenna, \(r=\sqrt{2 R h}\) (\(R:\) Radius of Earth) \(r=\sqrt{2 \times 6400 \times 98 \times 10^{-3}}\) Surface area covered by transmitting antenna \(=\pi r^{2}\)\(=2 \times 6400 \times 98 \times 10^{-3} \times \dfrac{22}{7}\) \(=3942.4 {~km}^{2} \approx 3942 {~km}^{2}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356826
Effective radiated power by an antenna is
1 Proportional to the square at the length of the antenna
2 Inversely proportional to the wavelength
3 Inversely proportional to the square of the wavelength
4 Proportional to the wavelength
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356827
Match Column-I with Column-II. Column I Column II A \({F_1}\) - Layers P \(10\,km\) B \(D\) -Layers Q \(170\) - \(190\,km\) C Troposphere R \(100\,km\) D \(E\) -Layers S \(65\) - \(75\,km\)
1 A - Q, B - P, C - S, D - R
2 A - R, B - S, C - P, D - Q
3 A - Q, B - S, C - R, D - P
4 A - Q, B - S, C - P, D - R
Explanation:
Height of different layers of atmosphere is given by \(F_{1}\)-layer is up to \(200 {~km}\) \(D\)-layer is up to \(70 {~km}\) Troposphere is up to \(10 {~km}\) \(E\)-layer is up to \(120 {~km}\).
