356828
An antenna behaves as a resonant circuit only when the length is
1 Equal to \(\lambda / 4\)
2 Equal to \(3 \lambda / 5\)
3 Equal to the integral multiples of \(\lambda / 2\)
4 Equal to \(3 \lambda / 4\)
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356829
The height of transmitting antenna is \(180\;m\) and the height of the receiving antenna is \(245\;m\). The maximum distance between them for satisfactory communication in line of sight will be (Given \(R = 6400\;km\))
1 \(48\;km\)
2 \(96\;km\)
3 \(104\;km\)
4 \(56\;km\)
Explanation:
Given, height of transmitting antenna, \(h_{T}=180 {~m}\) Height of receiving antenna,\(h_{R}=245 m\) Radius of earth, \(R=6400 {~km}\) The maximum distance upto which signals can be broadcasted is \(d_{m}=\sqrt{2 R h_{T}}+\sqrt{2 R h_{R}}\) \(=\sqrt{2 \times 64 \times 10^{5} \times 180}+\sqrt{2 \times 64 \times 10^{5} \times 245}\) \(=\sqrt{2 \times 6.4 \times 10^{6}}(\sqrt{180}+\sqrt{245}) \simeq 104 {~km}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356830
The examples of broadcast areA. radioB. televisionC. telephonyD. internet
1 A & B
2 A, B & D
3 A, B & C
4 B & D
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356831
In which frequency range, space waves are normally propagated?
356828
An antenna behaves as a resonant circuit only when the length is
1 Equal to \(\lambda / 4\)
2 Equal to \(3 \lambda / 5\)
3 Equal to the integral multiples of \(\lambda / 2\)
4 Equal to \(3 \lambda / 4\)
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356829
The height of transmitting antenna is \(180\;m\) and the height of the receiving antenna is \(245\;m\). The maximum distance between them for satisfactory communication in line of sight will be (Given \(R = 6400\;km\))
1 \(48\;km\)
2 \(96\;km\)
3 \(104\;km\)
4 \(56\;km\)
Explanation:
Given, height of transmitting antenna, \(h_{T}=180 {~m}\) Height of receiving antenna,\(h_{R}=245 m\) Radius of earth, \(R=6400 {~km}\) The maximum distance upto which signals can be broadcasted is \(d_{m}=\sqrt{2 R h_{T}}+\sqrt{2 R h_{R}}\) \(=\sqrt{2 \times 64 \times 10^{5} \times 180}+\sqrt{2 \times 64 \times 10^{5} \times 245}\) \(=\sqrt{2 \times 6.4 \times 10^{6}}(\sqrt{180}+\sqrt{245}) \simeq 104 {~km}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356830
The examples of broadcast areA. radioB. televisionC. telephonyD. internet
1 A & B
2 A, B & D
3 A, B & C
4 B & D
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356831
In which frequency range, space waves are normally propagated?
356828
An antenna behaves as a resonant circuit only when the length is
1 Equal to \(\lambda / 4\)
2 Equal to \(3 \lambda / 5\)
3 Equal to the integral multiples of \(\lambda / 2\)
4 Equal to \(3 \lambda / 4\)
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356829
The height of transmitting antenna is \(180\;m\) and the height of the receiving antenna is \(245\;m\). The maximum distance between them for satisfactory communication in line of sight will be (Given \(R = 6400\;km\))
1 \(48\;km\)
2 \(96\;km\)
3 \(104\;km\)
4 \(56\;km\)
Explanation:
Given, height of transmitting antenna, \(h_{T}=180 {~m}\) Height of receiving antenna,\(h_{R}=245 m\) Radius of earth, \(R=6400 {~km}\) The maximum distance upto which signals can be broadcasted is \(d_{m}=\sqrt{2 R h_{T}}+\sqrt{2 R h_{R}}\) \(=\sqrt{2 \times 64 \times 10^{5} \times 180}+\sqrt{2 \times 64 \times 10^{5} \times 245}\) \(=\sqrt{2 \times 6.4 \times 10^{6}}(\sqrt{180}+\sqrt{245}) \simeq 104 {~km}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356830
The examples of broadcast areA. radioB. televisionC. telephonyD. internet
1 A & B
2 A, B & D
3 A, B & C
4 B & D
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356831
In which frequency range, space waves are normally propagated?
356828
An antenna behaves as a resonant circuit only when the length is
1 Equal to \(\lambda / 4\)
2 Equal to \(3 \lambda / 5\)
3 Equal to the integral multiples of \(\lambda / 2\)
4 Equal to \(3 \lambda / 4\)
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356829
The height of transmitting antenna is \(180\;m\) and the height of the receiving antenna is \(245\;m\). The maximum distance between them for satisfactory communication in line of sight will be (Given \(R = 6400\;km\))
1 \(48\;km\)
2 \(96\;km\)
3 \(104\;km\)
4 \(56\;km\)
Explanation:
Given, height of transmitting antenna, \(h_{T}=180 {~m}\) Height of receiving antenna,\(h_{R}=245 m\) Radius of earth, \(R=6400 {~km}\) The maximum distance upto which signals can be broadcasted is \(d_{m}=\sqrt{2 R h_{T}}+\sqrt{2 R h_{R}}\) \(=\sqrt{2 \times 64 \times 10^{5} \times 180}+\sqrt{2 \times 64 \times 10^{5} \times 245}\) \(=\sqrt{2 \times 6.4 \times 10^{6}}(\sqrt{180}+\sqrt{245}) \simeq 104 {~km}\)
JEE - 2023
PHXII15:COMMUNICATION SYSTEMS
356830
The examples of broadcast areA. radioB. televisionC. telephonyD. internet
1 A & B
2 A, B & D
3 A, B & C
4 B & D
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356831
In which frequency range, space waves are normally propagated?
