\(\frac{4}{9}\) Square of \(\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}\) So, \(\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)\) \(=\frac{4}{9}\) [\(\because\) multiplication of two rational number with same sign is always positive]
EXPONENTS and POWERS
296390
Simplify the following using law of exponents for a = 2, x = 1, y = 1, z = 1 a\(^{1}\) × a\(^{1}\) × a\(^{1}\)
\(\frac{4}{9}\) Square of \(\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}\) So, \(\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)\) \(=\frac{4}{9}\) [\(\because\) multiplication of two rational number with same sign is always positive]
EXPONENTS and POWERS
296390
Simplify the following using law of exponents for a = 2, x = 1, y = 1, z = 1 a\(^{1}\) × a\(^{1}\) × a\(^{1}\)
\(\frac{4}{9}\) Square of \(\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}\) So, \(\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)\) \(=\frac{4}{9}\) [\(\because\) multiplication of two rational number with same sign is always positive]
EXPONENTS and POWERS
296390
Simplify the following using law of exponents for a = 2, x = 1, y = 1, z = 1 a\(^{1}\) × a\(^{1}\) × a\(^{1}\)
\(\frac{4}{9}\) Square of \(\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}\) So, \(\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)\) \(=\frac{4}{9}\) [\(\because\) multiplication of two rational number with same sign is always positive]
EXPONENTS and POWERS
296390
Simplify the following using law of exponents for a = 2, x = 1, y = 1, z = 1 a\(^{1}\) × a\(^{1}\) × a\(^{1}\)
\(\frac{4}{9}\) Square of \(\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}\) So, \(\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)\) \(=\frac{4}{9}\) [\(\because\) multiplication of two rational number with same sign is always positive]
EXPONENTS and POWERS
296390
Simplify the following using law of exponents for a = 2, x = 1, y = 1, z = 1 a\(^{1}\) × a\(^{1}\) × a\(^{1}\)