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CHEMISTRY(KCET)

285601 Acetic acid is treated with $Ca (OH)_{2}$ and the product so obtained is subjected to dry distillation. The final product is

1 propanal

2 ethanol

3 ethanal

4 propanone.

Explanation:

(d) $2 {CH}_{3} COOH + Ca (OH)_{2} \to$
${({CH}_{3} COO)}_{2} Ca + 2 H_{2} O$
Calcium acetate
Propanone

Karnataka CET 2015

CHEMISTRY(KCET)

285602 The distinguishing test betweenmethanoic acid and ethanoic acid is

1 Tollens' test

2 sodium bicarbonate test

3 litmus test

4 esterification test.

Explanation:

(a)
Methanoic acid has $- \overset{II}{C} -$ group as well as hydrogen attached to $C = O$ group.
Therefore it can reduce Tollen's reagent.

Karnataka CET 2015

CHEMISTRY(KCET)

285603 Iodoform reaction is answered by all, except

1

{CH}_{3} CHO

2

{CH}_{3} - {CH}_{2} - OH

3

{CH}_{3} - {CH}_{2} - {CH}_{2} OH

Explanation:

(d) Alcohols of the type, ${CH}_{3} - CH (OH) - R$ (where, $R = H /$ alkyl/aryl groups) and carbonyl compounds having $H_{3} C - \overset{O}{C}$ -group give iodoform reaction.

Karnataka CET 2014

CHEMISTRY(KCET)

285604 $C_{6} H_{5} COOH \to_{2 Δ}^{1. {NH}_{3}} P \overset{NaOBr}{\to} Q$

$R$ is $\to_{2.heatto 460 K}^{1.Conc. H_{2} {SO}_{4}} R$

1 o-bromosulphanilic acid

2 sulphanilamide

3 sulphanilic acid

4 p-bromosulphanilamide

Explanation:

(c) $C_{6} H_{5} COOH \to_{2 . Δ}^{1 . {NH}_{3}} C_{6} H_{5} {CONH}_{2}$
Benzoic acid
$C_{6} H_{4} ({NH}_{2}) ({SO}_{3} H) \underset{2.460 K, Δ}{\overset{I. conc. H_{2} {SO}_{4}}{⟵}} C_{6} H_{5} {NH}_{2}$
Sulphanilic acid, 'R'
Aniline, 'Q'

Karnataka CET 2014

CHEMISTRY(KCET)

285606 The acid strength of active methylene group in

1 i

>

iii

>

ii

2 i

>

ii

>

iii

3 ii

>

i

>

iii

4 iii

>

i

>

ii

Explanation:

(c) In active methylene compound (ii), methylene $(- {CH}_{2})$ group exists in between two strong EWGs i.e. $({CH}_{3} CO -)$ , which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)

Karnataka CET 2014

CHEMISTRY(KCET)

285601 Acetic acid is treated with $Ca (OH)_{2}$ and the product so obtained is subjected to dry distillation. The final product is

1 propanal

2 ethanol

3 ethanal

4 propanone.

Explanation:

(d) $2 {CH}_{3} COOH + Ca (OH)_{2} \to$
${({CH}_{3} COO)}_{2} Ca + 2 H_{2} O$
Calcium acetate
Propanone

Karnataka CET 2015

CHEMISTRY(KCET)

285602 The distinguishing test betweenmethanoic acid and ethanoic acid is

1 Tollens' test

2 sodium bicarbonate test

3 litmus test

4 esterification test.

Explanation:

(a)
Methanoic acid has $- \overset{II}{C} -$ group as well as hydrogen attached to $C = O$ group.
Therefore it can reduce Tollen's reagent.

Karnataka CET 2015

CHEMISTRY(KCET)

285603 Iodoform reaction is answered by all, except

1

{CH}_{3} CHO

2

{CH}_{3} - {CH}_{2} - OH

3

{CH}_{3} - {CH}_{2} - {CH}_{2} OH

Explanation:

(d) Alcohols of the type, ${CH}_{3} - CH (OH) - R$ (where, $R = H /$ alkyl/aryl groups) and carbonyl compounds having $H_{3} C - \overset{O}{C}$ -group give iodoform reaction.

Karnataka CET 2014

CHEMISTRY(KCET)

285604 $C_{6} H_{5} COOH \to_{2 Δ}^{1. {NH}_{3}} P \overset{NaOBr}{\to} Q$

$R$ is $\to_{2.heatto 460 K}^{1.Conc. H_{2} {SO}_{4}} R$

1 o-bromosulphanilic acid

2 sulphanilamide

3 sulphanilic acid

4 p-bromosulphanilamide

Explanation:

(c) $C_{6} H_{5} COOH \to_{2 . Δ}^{1 . {NH}_{3}} C_{6} H_{5} {CONH}_{2}$
Benzoic acid
$C_{6} H_{4} ({NH}_{2}) ({SO}_{3} H) \underset{2.460 K, Δ}{\overset{I. conc. H_{2} {SO}_{4}}{⟵}} C_{6} H_{5} {NH}_{2}$
Sulphanilic acid, 'R'
Aniline, 'Q'

Karnataka CET 2014

CHEMISTRY(KCET)

285606 The acid strength of active methylene group in

1 i

>

iii

>

ii

2 i

>

ii

>

iii

3 ii

>

i

>

iii

4 iii

>

i

>

ii

Explanation:

(c) In active methylene compound (ii), methylene $(- {CH}_{2})$ group exists in between two strong EWGs i.e. $({CH}_{3} CO -)$ , which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)

Karnataka CET 2014

CHEMISTRY(KCET)

285601 Acetic acid is treated with $Ca (OH)_{2}$ and the product so obtained is subjected to dry distillation. The final product is

1 propanal

2 ethanol

3 ethanal

4 propanone.

Explanation:

(d) $2 {CH}_{3} COOH + Ca (OH)_{2} \to$
${({CH}_{3} COO)}_{2} Ca + 2 H_{2} O$
Calcium acetate
Propanone

Karnataka CET 2015

CHEMISTRY(KCET)

285602 The distinguishing test betweenmethanoic acid and ethanoic acid is

1 Tollens' test

2 sodium bicarbonate test

3 litmus test

4 esterification test.

Explanation:

(a)
Methanoic acid has $- \overset{II}{C} -$ group as well as hydrogen attached to $C = O$ group.
Therefore it can reduce Tollen's reagent.

Karnataka CET 2015

CHEMISTRY(KCET)

285603 Iodoform reaction is answered by all, except

1

{CH}_{3} CHO

2

{CH}_{3} - {CH}_{2} - OH

3

{CH}_{3} - {CH}_{2} - {CH}_{2} OH

Explanation:

(d) Alcohols of the type, ${CH}_{3} - CH (OH) - R$ (where, $R = H /$ alkyl/aryl groups) and carbonyl compounds having $H_{3} C - \overset{O}{C}$ -group give iodoform reaction.

Karnataka CET 2014

CHEMISTRY(KCET)

285604 $C_{6} H_{5} COOH \to_{2 Δ}^{1. {NH}_{3}} P \overset{NaOBr}{\to} Q$

$R$ is $\to_{2.heatto 460 K}^{1.Conc. H_{2} {SO}_{4}} R$

1 o-bromosulphanilic acid

2 sulphanilamide

3 sulphanilic acid

4 p-bromosulphanilamide

Explanation:

(c) $C_{6} H_{5} COOH \to_{2 . Δ}^{1 . {NH}_{3}} C_{6} H_{5} {CONH}_{2}$
Benzoic acid
$C_{6} H_{4} ({NH}_{2}) ({SO}_{3} H) \underset{2.460 K, Δ}{\overset{I. conc. H_{2} {SO}_{4}}{⟵}} C_{6} H_{5} {NH}_{2}$
Sulphanilic acid, 'R'
Aniline, 'Q'

Karnataka CET 2014

CHEMISTRY(KCET)

285606 The acid strength of active methylene group in

1 i

>

iii

>

ii

2 i

>

ii

>

iii

3 ii

>

i

>

iii

4 iii

>

i

>

ii

Explanation:

(c) In active methylene compound (ii), methylene $(- {CH}_{2})$ group exists in between two strong EWGs i.e. $({CH}_{3} CO -)$ , which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)

Karnataka CET 2014

CHEMISTRY(KCET)

285601 Acetic acid is treated with $Ca (OH)_{2}$ and the product so obtained is subjected to dry distillation. The final product is

1 propanal

2 ethanol

3 ethanal

4 propanone.

Explanation:

(d) $2 {CH}_{3} COOH + Ca (OH)_{2} \to$
${({CH}_{3} COO)}_{2} Ca + 2 H_{2} O$
Calcium acetate
Propanone

Karnataka CET 2015

CHEMISTRY(KCET)

285602 The distinguishing test betweenmethanoic acid and ethanoic acid is

1 Tollens' test

2 sodium bicarbonate test

3 litmus test

4 esterification test.

Explanation:

(a)
Methanoic acid has $- \overset{II}{C} -$ group as well as hydrogen attached to $C = O$ group.
Therefore it can reduce Tollen's reagent.

Karnataka CET 2015

CHEMISTRY(KCET)

285603 Iodoform reaction is answered by all, except

1

{CH}_{3} CHO

2

{CH}_{3} - {CH}_{2} - OH

3

{CH}_{3} - {CH}_{2} - {CH}_{2} OH

Explanation:

(d) Alcohols of the type, ${CH}_{3} - CH (OH) - R$ (where, $R = H /$ alkyl/aryl groups) and carbonyl compounds having $H_{3} C - \overset{O}{C}$ -group give iodoform reaction.

Karnataka CET 2014

CHEMISTRY(KCET)

285604 $C_{6} H_{5} COOH \to_{2 Δ}^{1. {NH}_{3}} P \overset{NaOBr}{\to} Q$

$R$ is $\to_{2.heatto 460 K}^{1.Conc. H_{2} {SO}_{4}} R$

1 o-bromosulphanilic acid

2 sulphanilamide

3 sulphanilic acid

4 p-bromosulphanilamide

Explanation:

(c) $C_{6} H_{5} COOH \to_{2 . Δ}^{1 . {NH}_{3}} C_{6} H_{5} {CONH}_{2}$
Benzoic acid
$C_{6} H_{4} ({NH}_{2}) ({SO}_{3} H) \underset{2.460 K, Δ}{\overset{I. conc. H_{2} {SO}_{4}}{⟵}} C_{6} H_{5} {NH}_{2}$
Sulphanilic acid, 'R'
Aniline, 'Q'

Karnataka CET 2014

CHEMISTRY(KCET)

285606 The acid strength of active methylene group in

1 i

>

iii

>

ii

2 i

>

ii

>

iii

3 ii

>

i

>

iii

4 iii

>

i

>

ii

Explanation:

(c) In active methylene compound (ii), methylene $(- {CH}_{2})$ group exists in between two strong EWGs i.e. $({CH}_{3} CO -)$ , which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)

Karnataka CET 2014

CHEMISTRY(KCET)

285601 Acetic acid is treated with $Ca (OH)_{2}$ and the product so obtained is subjected to dry distillation. The final product is

1 propanal

2 ethanol

3 ethanal

4 propanone.

Explanation:

(d) $2 {CH}_{3} COOH + Ca (OH)_{2} \to$
${({CH}_{3} COO)}_{2} Ca + 2 H_{2} O$
Calcium acetate
Propanone

Karnataka CET 2015

CHEMISTRY(KCET)

285602 The distinguishing test betweenmethanoic acid and ethanoic acid is

1 Tollens' test

2 sodium bicarbonate test

3 litmus test

4 esterification test.

Explanation:

(a)
Methanoic acid has $- \overset{II}{C} -$ group as well as hydrogen attached to $C = O$ group.
Therefore it can reduce Tollen's reagent.

Karnataka CET 2015

CHEMISTRY(KCET)

285603 Iodoform reaction is answered by all, except

1

{CH}_{3} CHO

2

{CH}_{3} - {CH}_{2} - OH

3

{CH}_{3} - {CH}_{2} - {CH}_{2} OH

Explanation:

(d) Alcohols of the type, ${CH}_{3} - CH (OH) - R$ (where, $R = H /$ alkyl/aryl groups) and carbonyl compounds having $H_{3} C - \overset{O}{C}$ -group give iodoform reaction.

Karnataka CET 2014

CHEMISTRY(KCET)

285604 $C_{6} H_{5} COOH \to_{2 Δ}^{1. {NH}_{3}} P \overset{NaOBr}{\to} Q$

$R$ is $\to_{2.heatto 460 K}^{1.Conc. H_{2} {SO}_{4}} R$

1 o-bromosulphanilic acid

2 sulphanilamide

3 sulphanilic acid

4 p-bromosulphanilamide

Explanation:

(c) $C_{6} H_{5} COOH \to_{2 . Δ}^{1 . {NH}_{3}} C_{6} H_{5} {CONH}_{2}$
Benzoic acid
$C_{6} H_{4} ({NH}_{2}) ({SO}_{3} H) \underset{2.460 K, Δ}{\overset{I. conc. H_{2} {SO}_{4}}{⟵}} C_{6} H_{5} {NH}_{2}$
Sulphanilic acid, 'R'
Aniline, 'Q'

Karnataka CET 2014

CHEMISTRY(KCET)

285606 The acid strength of active methylene group in

1 i

>

iii

>

ii

2 i

>

ii

>

iii

3 ii

>

i

>

iii

4 iii

>

i

>

ii

Explanation:

(c) In active methylene compound (ii), methylene $(- {CH}_{2})$ group exists in between two strong EWGs i.e. $({CH}_{3} CO -)$ , which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)

Karnataka CET 2014